This is AI generated Response.
Asked by: gvr
Created at: 2025-07-28 07:43:48
Final Answer:
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Let's analyze and solve **(a)** as an example step-by-step, including MATLAB code for verification.
---
### **(a)**
Given:
\[
L(s) = \frac{(s+2)(s+6)}{s(s+1)(s+5)(s+10)}
\]
### **Step 1: Identify Poles and Zeros**
- **Zeros:** \( s = -2, -6 \)
- **Poles:** \( s = 0, -1, -5, -10 \)
### **Step 2: Root Locus Start and End Points**
- **Starts**: At open-loop poles (\( s = 0, -1, -5, -10 \))
- **Ends**: At open-loop zeros (\( s = -2, -6 \)) and infinity (since 4 poles, 2 zeros, so 2 loci end at infinity)
### **Step 3: Number of Asymptotes**
- Number of poles \( n = 4 \), number of zeros \( m = 2 \)
- Number of asymptotes \( = n - m = 2 \)
### **Step 4: Centroid and Asymptote Angles**
- **Centroid:**
\[
\text{Centroid} = \frac{\sum \text{Poles} - \sum \text{Zeros}}{n-m}
\]
\[
= \frac{(0) + (-1) + (-5) + (-10) - [(-2) + (-6)]}{2}
= \frac{-16 + 8}{2} = \frac{-8}{2} = -4
\]
- **Angles:**
\[
\theta = \frac{(2q+1)180^\circ}{n-m}, \quad q=0,1
\]
For \( n-m=2 \):
\( q=0 \rightarrow 90^\circ \), \( q=1 \rightarrow 270^\circ \) (or \(-90^\circ\))
### **Step 5: Departure and Arrival Angles**
- **Departure Angle:** Only relevant for complex poles/zeros. Here, all real, so not applicable.
### **Step 6: Root Locus Sketch**
- Draw the s-plane.
- Mark zeros at \( s=-2, -6 \).
- Mark poles at \( s=0, -1, -5, -10 \).
- Sketch loci: From each pole, loci approach zeros or move to infinity along asymptotes from centroid at \( s = -4 \), at \( \pm 90^\circ \) angles.
---
## **MATLAB Code**
```matlab
% Define numerator and denominator
num = [1 8 12]; % (s+2)(s+6) = s^2 + 8s + 12
den = conv([1 0], conv([1 1], conv([1 5], [1 10]))); % s(s+1)(s+5)(s+10)
% Root locus plot
figure;
rlocus(num, den);
title('Root Locus of L(s) = (s+2)(s+6) / [s(s+1)(s+5)(s+10)]');
grid on;
```
---
## **Summary Table for (a):**
| Quantity | Value |
|------------------|------------------------|
| Poles | 0, -1, -5, -10 |
| Zeros | -2, -6 |
| Asymptote Number | 2 |
| Centroid | -4 |
| Asymptote Angles | 90°, 270° |
---
**Repeat** similar steps for parts (b)-(e).
Would you like a solution for the next part (b) as well?
Question:
yes please all need
This is AI generated Response.
Asked by: gvr
Created at: 2025-07-28 07:45:03
Final Answer:
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Let's proceed step-by-step for each part (b) to (e), including hand sketches (conceptually described), asymptote details, departure angles, and MATLAB code for verification.
---
## (b) \(L(s) = \frac{1}{(s+2)(s+6)}\)
### **Step 1: Poles and Zeros**
- **Zeros:** None
- **Poles:** \( s = -2, -6 \)
### **Step 2: Root Locus Start and End Points**
- Poles at \( -2 \) and \( -6 \)
- Since no zeros, both loci go to infinity.
### **Step 3: Number of Asymptotes**
- Number of poles \( n=2 \), zeros \( m=0 \)
- Asymptotes: \( n - m = 2 \)
### **Step 4: Asymptote Centroid and Angles**
- \[
\text{Centroid} = \frac{-2 + (-6)}{2} = \frac{-8}{2} = -4
\]
- Angles: \( \pm 90^\circ \) (since \( n-m=2 \))
### **Step 5: Sketch Description**
- Poles at \( -2 \) and \( -6 \)
- Loci on the real axis: Between \( -6 \) and \( -2 \), the locus exists.
- From each pole, the locus extends to infinity along asymptotes at \( \pm 90^\circ \) crossing centroid at \( -4 \).
---
## MATLAB Code for (b):
```matlab
% Part (b)
num_b = 1; % numerator
den_b = conv([1 2], [1 6]); % (s+2)(s+6)
rlocus(num_b, den_b);
title('Root Locus of 1/[(s+2)(s+6)]');
grid on;
```
---
## (c) \(L(s) = \frac{s+1}{(s+3)(s+4)}\)
### **Step 1: Poles and Zeros**
- **Zeros:** at \( s = -1 \)
- **Poles:** at \( s = -3, -4 \)
### **Step 2: Poles and zeros summary**
- Poles at \( -3, -4 \)
- Zero at \( -1 \)
### **Step 3: Asymptotes**
- \( n=2 \), \( m=1 \)
- Asymptotes: \( 2 - 1=1 \)
- **Centroid:**
\[
\frac{-3 + (-4) - (-1)}{1} = \frac{-7 + 1}{1} = -6
\]
- **Angles:**
\[
\frac{(2q+1)180^\circ}{1} = 180^\circ
\]
Only one asymptote at \( 180^\circ \).
### **Step 4: Sketch description**
- Zero at \( -1 \), poles at \( -3, -4 \).
- One asymptote at \( 180^\circ \) crossing at \( s = -6 \).
- Root locus: from poles, approaching the zero or going to infinity along the asymptote.
---
## MATLAB Code for (c):
```matlab
% Part (c)
num_c = [1 1]; % s+1
den_c = conv([1 3], [1 4]);
rlocus(num_c, den_c);
title('Root Locus of (s+1)/[(s+3)(s+4)]');
grid on;
```
---
## (d) \(L(s) = \frac{5}{(s+1)(s+2)(s+3)}\)
### **Step 1: Poles and Zeros**
- **Zero:** none
- **Poles:** at \( -1, -2, -3 \)
### **Step 2: Asymptotes**
- \( n=3 \), \( m=0 \)
- Number of asymptotes: 3
- **Centroid:**
\[
\frac{-1 + (-2) + (-3)}{3} = \frac{-6}{3} = -2
\]
- **Angles:**
\[
\frac{(2q+1)180^\circ}{3} = 60^\circ, 180^\circ, 300^\circ
\]
### **Step 3: Sketch description**
- Poles at \( -1, -2, -3 \)
- Asymptotes at \( 60^\circ, 180^\circ, 300^\circ \) crossing at \( -2 \).
---
## MATLAB Code for (d):
```matlab
% Part (d)
num_d = 5; % numerator constant
den_d = conv([1 1], conv([1 2], [1 3]));
rlocus(num_d, den_d);
title('Root Locus of 5/[(s+1)(s+2)(s+3)]');
grid on;
```
---
## (e) \(L(s) = \frac{1}{(s+1)(s+2)}\)
### **Step 1: Poles and Zeros**
- Poles at \( -1, -2 \)
- No zeros
### **Step 2: Asymptotes**
- \( n=2 \), \( m=0 \), asymptotes: 2
- **Centroid:**
\[
\frac{-1 + (-2)}{2} = -1.5
\]
- **Angles:**
\(\pm 90^\circ\)
### **Step 3: Sketch**
- Poles at \( -1, -2 \)
- Loci on the real axis between the poles.
- Asymptotes at \( \pm 90^\circ \) crossing at \( -1.5 \).
---
## MATLAB Code for (e):
```matlab
% Part (e)
num_e = 1;
den_e = conv([1 1], [1 2]);
rlocus(num_e, den_e);
title('Root Locus of 1/[(s+1)(s+2)]');
grid on;
```
---
# **Summary:**
| Part | Poles | Zeros | Asymptotes | Centroid | Asymptote Angles | Key Features |
|--------|------------------------|----------------------|------------|---------|------------------|------------------------------------------------|
| (a) | 0, -1, -5, -10 | -2, -6 | 2 | -4 | 90°, 270° | Poles and zeros, asymptotes crossing at -4 |
| (b) | -2, -6 | None | 2 | -4 | 90°, 270° | Poles on real axis, loci extend to infinity |
| (c) | -3, -4 | -1 | 1 | -6 | 180° | One zero, one asymptote at 180° |
| (d) | -1, -2, -3 | None | 3 | -2 | 60°, 180°, 300° | Three asymptotes crossing at -2 |
| (e) | -1, -2 | None | 2 | -1.5 | 90°, -90° | Poles on real axis, asymptotes at ±90° |
---
**Note:** To verify your hand sketches, run the MATLAB code provided. The MATLAB plots will show the actual root locus, confirming asymptote directions, poles, zeros, and loci paths.
---
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