VIPSolutionsWhat series of reagents could be used to carry out the conversion shown in the image attached below. a.CH3CH2CL/ALCL3;CL2/FECL3;KMNO4,H2O,heat b.CH3CH2CL/ALCL3;CL2/FECL3;PCC,CH2CL2 c.CH3CH2CL/ALCL3;KMNO4,H2O,heat,CL2/FECL3 d.CH3CH2CL/ALCL3;CL2/FECL3;NA2CR2O7/H20 e.CH3CH2CL/ALCL3;NAOH;CL2/FECL35 \ os WY A \ ™ \& Le * \
Question:
What series of reagents could be used to carry out the conversion shown in the image attached below.
a.CH3CH2CL/ALCL3;CL2/FECL3;KMNO4,H2O,heat
b.CH3CH2CL/ALCL3;CL2/FECL3;PCC,CH2CL2
c.CH3CH2CL/ALCL3;KMNO4,H2O,heat,CL2/FECL3
d.CH3CH2CL/ALCL3;CL2/FECL3;NA2CR2O7/H20
e.CH3CH2CL/ALCL3;NAOH;CL2/FECL3
5 \ os
WY
A
\ ™
\& Le *
\
This is AI generated Response.
Asked by: Test User 100235
Created at: 2025-05-11 10:42:12
Asked by: Test User 100235
Created at: 2025-05-11 10:42:12
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Let's analyze the transformation step by step:
**Starting material:** Benzene
**Product:** *p*-Chlorobenzoic acid (para-chlorobenzoic acid)
### Steps Involved:
1. **Alkylation (Friedel-Crafts):** Attach an ethyl group to benzene to get ethylbenzene.
- Reagent: CH₃CH₂Cl/AlCl₃
2. **Halogenation (Chlorination):** Introduce a chlorine atom to the para position (relative to the ethyl group).
- Reagent: Cl₂/FeCl₃
3. **Oxidation:** Oxidize the ethyl group to a carboxylic acid.
- Reagent: KMnO₄, H₂O, heat
### Correct sequence:
**a.** CH₃CH₂Cl/AlCl₃; Cl₂/FeCl₃; KMnO₄, H₂O, heat
**Explanation:**
- Friedel-Crafts alkylation introduces the ethyl group (activating, ortho/para-directing).
- Chlorination adds Cl to the para position.
- Strong oxidation (KMnO₄) converts the ethyl side chain to a carboxylic acid group.
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### **The correct answer is:**
**a. CH₃CH₂Cl/AlCl₃; Cl₂/FeCl₃; KMnO₄, H₂O, heat**
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