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What is the output of the following program? #include < stdio.h > int main() { int a=1; switch(a) { printf("GATE-CSE"); case 0: printf("Zero"); case 1: printf("One"); default: printf("None"); } return 0; }

Question:

What is the output of the following program? #include < stdio.h > int main() { int a=1; switch(a) { printf("GATE-CSE"); case 0: printf("Zero"); case 1: printf("One"); default: printf("None"); } return 0; }

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Asked by: Vishal
Created at: 2026-01-03 15:00:18

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# Output of the Program The program's behavior depends on the placement of the `printf` statement of the `switch` cases and absence of `break` statements inside switch. --- Code Analysis c #include <stdio.h>int main() int a 1; switch(a) { ("GATE-CSE"); case : printf("Zero"); case 1 printf("One default:("None"); } return; } ` ### Key points- The `printf("GATE-CSE");` statement is **outside** and **before** the `case` labels. - Since there's no `break`, execution will **fall through** after the first statement. --- ## Execution Flow 1. `int a = 1;` 2. Enters the `switch(a)` statement. 3. Executes `printf("GATE-CSE");` **before** checking any case. 4. Since no `break` exists, it falls through all subsequent cases: - `case :` is skipped because `a` is 1. - `case 1:` matches, so it executes `printf("One");`. - Continues to `default:` and executes `printf("None");`. --- ## Final Output ```plaintext GATE-CSEOneNone ``` **Note:** All outputs are concatenated because there are no newline characters. --- ## Summary - The output begins with **"GATE-CSE"**. - Then **"One"** (from `case 1`). - Then **"None"** (from `default`). **Total output:** ```plaintext GATE-CSEOneNone ```

Question:

But correct answer shown is One None

This is AI generated Response.
Asked by: Vishal
Created at: 2026-01-03 15:01:25

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# Output of the Program The program behavior is influenced by the placement of the `printf` statement and the absence of `break` statements within the `switch`. --- ## Code Analysis ```c #include <stdio.h> int main() { int a = 1; switch(a) { printf("GATE-CSE"); case 0: printf("Zero"); break; case 1: printf("One"); break; default: printf("None"); } return 0; } ``` ### Key Points - The `printf("GATE-CSE");` statement is **outside** and **before** the case labels. - There are no `break` statements after the `case` blocks, allowing execution to **fall through**. --- ## Execution Flow 1. `int a = 1;` 2. Enters the `switch(a)` statement. 3. Executes `printf("GATE-CSE");` **before** checking any case. 4. Since `a` is 1, it: - Skips `case 0:` and does not execute `printf("Zero");`. - Matches `case 1:` and executes `printf("One");`. - Falls through to `default:` and executes `printf("None");`. --- ## Final Output ```plaintext GATE-CSEOneNone ``` **Note:** All outputs are concatenated due to the absence of newline characters. --- ## Summary - The output begins with **"GATE-CSE"**. - Then **"One"** (from `case 1`). - Finally **"None"** (from `default`). **Total output:** ```plaintext GATE-CSEOneNone ```

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