Let's analyze the problem using Newton's law of universal gravitation: The force \( F \) between two masses \( m_1 \) and \( m_2 \) separated by distance \( r \) is: \[ F = G \frac{m_1 m_2}{r^2} \] Now, **the mass of each object is doubled**, so \( m_1 \to 2m_1 \) and \( m_2 \to 2m_2 \). **The distance between their centers is doubled**, so \( r \to 2r \). Plug these into the formula: \[ F' = G \frac{(2m_1)(2m_2)}{(2r)^2} = G \frac{4m_1m_2}{4r^2} = G \frac{m_1m_2}{r^2} \] So, the new force \( F' \) is **equal to** the original force \( F \). **Correct answer:** **D. It remains the same.**