2-methylcyclohexene + CHCl3 + t-BuOK -> ? Provide the key intermediate and the final product ( 3 pts ) . Show the curved arrow Mechanism for the following reaction. Step by step
Question:
2-methylcyclohexene + CHCl3 + t-BuOK -> ? Provide the key intermediate and the final product ( 3 pts ) . Show the curved arrow Mechanism for the following reaction. Step by step
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Asked by: Test User 100016
Created at: 2025-04-26 08:08:23
Asked by: Test User 100016
Created at: 2025-04-26 08:08:23
Final Answer:
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Let’s break down the reaction:
### Reactants:
- **2-methylcyclohexene**
- **Chloroform (CHCl₃)**
- **Potassium tert-butoxide (t-BuOK)**
---
## Step 1: Understanding the Reaction
This is a classic example of **carbene addition** (specifically, the formation of a **dichlorocarbene**, :CCl₂).
**t-BuOK** is a strong base. It deprotonates **CHCl₃** to generate the **dichlorocarbene** (:CCl₂), which then adds to the double bond of the alkene (**2-methylcyclohexene**) to form a **cyclopropane ring** fused to the cyclohexane ring, with two Cl atoms on the newly formed cyclopropane.
---
## Step 2: Mechanism
### **A. Generation of Dichlorocarbene (:CCl₂)**
**Step 1: Deprotonation of Chloroform**
- **t-BuOK** abstracts a proton from **CHCl₃**, forming **trichloromethide anion (CCl₃⁻)** and **tert-butanol**.
```
CHCl₃ + t-BuOK → CCl₃⁻ + t-BuOH + K⁺
```
**Arrow-pushing**:
- Lone pair on O⁻ of t-BuO⁻ attacks the H of CHCl₃.
- The C-H bond electrons move to the C, making CCl₃⁻.
**Step 2: Loss of Cl⁻ to generate :CCl₂**
- The CCl₃⁻ anion is unstable and eliminates **Cl⁻** to form **dichlorocarbene (:CCl₂)**.
```
CCl₃⁻ → :CCl₂ + Cl⁻
```
**Arrow-pushing**:
- Lone pair on C pushes out a Cl⁻, forming a neutral carbene (:CCl₂).
---
### **B. Addition of Dichlorocarbene to 2-Methylcyclohexene**
- The **dichlorocarbene (:CCl₂)** adds to the double bond of **2-methylcyclohexene** in a **concerted cyclopropanation**.
**Mechanism**:
- The π electrons of the alkene attack the empty p-orbital of :CCl₂.
- Simultaneously, a lone pair from :CCl₂ forms a bond to the other alkene carbon.
- This forms a **bicyclo[4.1.0]heptane ring system** (the cyclohexane fused to a cyclopropane), and the two Cl atoms are attached to the same cyclopropane carbon.
---
## Step 3: Drawing the Mechanism
### **1. Generation of the carbene:**
```
:O⁻
t-Bu-O⁻ + CHCl₃ → t-Bu-OH + :CCl₃⁻
|
:CCl₃⁻ → :CCl₂ + Cl⁻
```
- Arrow from O⁻ to H of CHCl₃, arrow from C-H to C.
- Arrow from lone pair on C to Cl, eliminating Cl⁻.
### **2. Carbene addition:**
```
2-methylcyclohexene + :CCl₂ →
(bicyclo[4.1.0]heptane derivative with two Cl on the cyclopropane ring)
```
- Arrow from alkene π bond to carbene C.
- Lone pair from carbene forms bond to other alkene carbon.
---
## Step 4: Final Product
**Name:**
**1,1-dichloro-2-methylbicyclo[4.1.0]heptane**
**Structure:**
- A cyclohexane ring with a fused cyclopropane ring between C1 and C2.
- The two Cl atoms are both on the C1 of the cyclopropane ring.
- The methyl group is at C2.
**Drawn Structure:**
```
(Methyl)
|
_____2
/ \
/ \
1---------6
| |
7---------3
\ /
\_____/
|
Cl
|
Cl
```
- The cyclopropane is fused between C1 and C2.
---
## **Summary Table**
| Step | Key Intermediate | Final Product |
|--------------------|-----------------|--------------------------------------------------|
| Carbene formation | :CCl₂ | 1,1-dichloro-2-methylbicyclo[4.1.0]heptane |
---
## **Curved Arrow Mechanism (Summary)**
1. **t-BuO⁻** deprotonates **CHCl₃** (arrow from O⁻ to H; arrow from C-H to C).
2. **CCl₃⁻** eliminates **Cl⁻** (arrow from lone pair on C to Cl).
3. **:CCl₂** adds to alkene (arrows from π bond to carbene C, and from carbene lone pair to other alkene carbon).
---
## **In words:**
**2-methylcyclohexene** reacts with **chloroform** and **t-BuOK** to produce **1,1-dichloro-2-methylbicyclo[4.1.0]heptane** via a **dichlorocarbene addition**. The key intermediate is **dichlorocarbene (:CCl₂)**.
---
**If you need a detailed hand-drawn mechanism, let me know!**
Question:
wedge and dash bond present in the final product
This is AI generated Response.
Asked by: Test User 100016
Created at: 2025-04-26 08:42:39
Asked by: Test User 100016
Created at: 2025-04-26 08:42:39
Final Answer:
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Certainly! Here's a detailed explanation with the key intermediate, the final product, and the curved arrow mechanism, including the stereochemistry (wedge and dash bonds).
---
### **Reaction Overview:**
**Reactants:**
- 2-methylcyclohexene (alkene with a methyl at C2)
- Chloroform (CHCl₃)
- Potassium tert-butoxide (t-BuOK)
**Product:**
- 1,1-dichloro-2-methylbicyclo[4.1.0]heptane
---
### **Step 1: Formation of Dichlorocarbene (:CCl₂)**
**a. Deprotonation of chloroform:**
- t-BuOK abstracts the acidic proton (H) from chloroform:

*Arrow:* Lone pair from O⁻ attacks H of CHCl₃, forming t-BuOH and CCl₃⁻.
**b. Loss of chloride to form carbene:**
- The trichloromethyl anion (CCl₃⁻) expels Cl⁻ to generate dichlorocarbene (:CCl₂):

*Arrow:* Lone pair on CCl₃⁻ attacks Cl, ejecting Cl⁻, leaving behind :CCl₂.
---
### **Step 2: Carbene addition to the alkene**
- The carbene (:CCl₂) adds across the double bond of 2-methylcyclohexene, forming a cyclopropane fused to the cyclohexane ring.
- **Mechanism:**
- The π electrons of the alkene attack the carbene carbon (:CCl₂).
- Simultaneously, the lone pair on carbene forms a bond with the other alkene carbon.
- **Stereochemistry:**
- The addition occurs **concertedly** and **stereospecifically**.
- The two Cl atoms end up on the same face of the cyclopropane ring (cis addition) leading to the stereochemistry shown with wedge/dash bonds.
---
### **Step 3: Final Product**
The product is **1,1-dichloro-2-methylbicyclo[4.1.0]heptane**.
**Structural features:**
- The cyclopropane ring is fused to the cyclohexane ring.
- Both Cl atoms are attached to the same carbon of the cyclopropane (C-1).
- The methyl group remains at C-2.
- The stereochemistry (wedge/dash) indicates the Cl atoms are on the same face (cis).
---
### **Diagram of the Product (with stereochemistry):**
```
Cl (wedge)
|
___ C (C-1)
/ \__/
| /
| /
| /
| /
/\/
/ \
(Cyclohexane ring with methyl at C2)
```
- The two Cl atoms are both **wedged** (coming out of the plane), indicating they are **cis**.
---
### **Summary:**
| Step | Key Intermediate | Final Product |
|---------|---------------------|------------------------------|
| Carbene formation | :CCl₂ | 1,1-dichloro-2-methylbicyclo[4.1.0]heptane |
---
### **Curved Arrow Summary:**
1. **Deprotonation of chloroform:**
- Arrow from lone pair on O⁻ to H of CHCl₃.
- Arrow from C-H bond to carbon, forming CCl₃⁻.
2. **Formation of carbene:**
- Arrow from lone pair on CCl₃⁻ to Cl, ejecting Cl⁻.
3. **Addition to alkene:**
- Arrow from π bond of alkene to carbene carbon.
- Arrow from lone pair on carbene to the other alkene carbon.
---
**This process results in the formation of a cyclopropane fused to a cyclohexane with two Cl substituents on the same face, giving the stereochemistry indicated by wedge bonds.**
---
**Let me know if you'd like a hand-drawn sketch or further clarification!**
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