1. For a vertical curve with the following data: L = 425.00 ft.; g1= -2.30%; g2= +0.90%; VPI sta = 23+50.00 ft.; VPI elev = 949.35 ft., determine the:
e. (4 pts.) Elevations on the curve at full stations
f. (2 pts.) Elevations on the tangents at full stations
g. (4 pts.) Tangent offsets at full stations
h. (2 pts.) High/low point station
i. (2 pts.) High/low point elevation
j. (2 pts.) Elevation on the curve at station 29+70.00 ft.
k. (2 pts.) Elevation on the curve at a point 250.00 ft. from the BVC.
Question:
1. For a vertical curve with the following data: L = 425.00 ft.; g1= -2.30%; g2= +0.90%; VPI sta = 23+50.00 ft.; VPI elev = 949.35 ft., determine the:
e. (4 pts.) Elevations on the curve at full stations
f. (2 pts.) Elevations on the tangents at full stations
g. (4 pts.) Tangent offsets at full stations
h. (2 pts.) High/low point station
i. (2 pts.) High/low point elevation
j. (2 pts.) Elevation on the curve at station 29+70.00 ft.
k. (2 pts.) Elevation on the curve at a point 250.00 ft. from the BVC.
This is AI generated Response.
Asked by: Md Israrul Haque
Created at: 2025-08-25 23:14:25
Final Answer:
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Let's go step by step for your vertical curve problem.
### **Given Data**
- **L** = 425.00 ft (Length of vertical curve)
- **g₁** = -2.30% (Initial tangent grade)
- **g₂** = +0.90% (Final tangent grade)
- **VPI Sta** = 23+50.00 ft (Station of Vertical Point of Intersection)
- **VPI Elev** = 949.35 ft (Elevation at VPI)
Let’s define:
- **BVC** (Beginning of Vertical Curve)
- **EVC** (End of Vertical Curve)
---
## **Step 1: Find BVC and EVC Stations**
- The BVC is **L/2** before the VPI:
- \( \text{BVC Sta} = 23+50.00 - \frac{425}{2} = 23+50.00 - 212.50 = 21+37.50 \)
- The EVC is **L/2** after the VPI:
- \( \text{EVC Sta} = 23+50.00 + 212.50 = 25+62.50 \)
---
## **Step 2: Find Elevation at BVC**
- Distance from BVC to VPI: 212.50 ft
- Grade at BVC: g₁ = -2.30% = -0.0230
\[
\text{Elev at BVC} = \text{Elev at VPI} - (\text{distance}) \times g_1
\]
\[
= 949.35\,\text{ft} - 212.5 \times (-0.0230)
\]
\[
= 949.35 + 4.8875 = 954.2375\,\text{ft}
\]
---
## **Step 3: Vertical Curve Equation**
The parabolic vertical curve equation (for station x feet past BVC):
\[
y = y_{\text{BVC}} + g_1 x + \frac{A}{2L} x^2
\]
where
- \( A = g_2 - g_1 = 0.90\% - (-2.30\%) = 3.20\% = 0.0320 \)
- \( L = 425 \)
- \( y_{\text{BVC}} = 954.2375 \)
\[
y = 954.2375 + (-0.0230)x + \frac{0.0320}{2 \times 425} x^2
\]
\[
\frac{0.0320}{850} = 0.00003765
\]
So,
\[
y = 954.2375 - 0.0230x + 0.00003765x^2
\]
---
## **Step 4: Full Stations from BVC to EVC**
BVC = 21+37.50
EVC = 25+62.50
Full stations are: 22+00, 23+00, 24+00, 25+00
### **For each full station, find:**
- Distance from BVC, \( x \)
- Elevation on curve
- Elevation on tangent
- Tangent offset
---
### **22+00**
- Sta: 22+00 = 2200 ft
- \( x_{22+00} = 2200 - 2137.5 = 62.5 \) ft
### **23+00**
- Sta: 23+00 = 2300 ft
- \( x_{23+00} = 2300 - 2137.5 = 162.5 \) ft
### **24+00**
- Sta: 24+00 = 2400 ft
- \( x_{24+00} = 2400 - 2137.5 = 262.5 \) ft
### **25+00**
- Sta: 25+00 = 2500 ft
- \( x_{25+00} = 2500 - 2137.5 = 362.5 \) ft
---
## **Step 5: Calculations**
### **e. Elevations on the curve at full stations**
\[
y = 954.2375 - 0.0230x + 0.00003765x^2
\]
#### **22+00 (x = 62.5):**
\[
y = 954.2375 - 0.0230 \times 62.5 + 0.00003765 \times (62.5)^2 \\
= 954.2375 - 1.4375 + 0.147 \\
= 952.9470\,\text{ft}
\]
#### **23+00 (x = 162.5):**
\[
y = 954.2375 - 0.0230 \times 162.5 + 0.00003765 \times (162.5)^2 \\
= 954.2375 - 3.7375 + 0.992 \\
= 951.4920\,\text{ft}
\]
#### **24+00 (x = 262.5):**
\[
y = 954.2375 - 0.0230 \times 262.5 + 0.00003765 \times (262.5)^2 \\
= 954.2375 - 6.0375 + 2.591 \\
= 950.7910\,\text{ft}
\]
#### **25+00 (x = 362.5):**
\[
y = 954.2375 - 0.0230 \times 362.5 + 0.00003765 \times (362.5)^2 \\
= 954.2375 - 8.3375 + 4.944 \\
= 950.8440\,\text{ft}
\]
---
### **f. Elevations on the tangents at full stations**
(The tangent in question is the initial tangent, unless specified otherwise.)
\[
y_{\text{tangent}} = 954.2375 + g_1 x
\]
#### **22+00 (x = 62.5):**
\[
= 954.2375 + (-0.0230 \times 62.5) = 954.2375 - 1.4375 = 952.8000\,\text{ft}
\]
#### **23+00 (x = 162.5):**
\[
= 954.2375 - 3.7375 = 950.5000\,\text{ft}
\]
#### **24+00 (x = 262.5):**
\[
= 954.2375 - 6.0375 = 948.2000\,\text{ft}
\]
#### **25+00 (x = 362.5):**
\[
= 954.2375 - 8.3375 = 945.9000\,\text{ft}
\]
---
### **g. Tangent offsets at full stations**
\[
\text{Offset} = \text{Elevation (curve)} - \text{Elevation (tangent)}
\]
#### **22+00:**
\[
952.9470 - 952.8000 = 0.1470\,\text{ft}
\]
#### **23+00:**
\[
951.4920 - 950.5000 = 0.9920\,\text{ft}
\]
#### **24+00:**
\[
950.7910 - 948.2000 = 2.5910\,\text{ft}
\]
#### **25+00:**
\[
950.8440 - 945.9000 = 4.9440\,\text{ft}
\]
---
### **h. High/Low Point Station**
The high/low point occurs where the slope is zero:
\[
g_1 + \frac{A}{L} x = 0 \implies x = -\frac{g_1 L}{A}
\]
\[
x = -\frac{-0.0230 \times 425}{0.0320} = \frac{9.775}{0.0320} = 305.47\,\text{ft}
\]
\[
\text{Station} = \text{BVC Sta} + x = 21+37.50 + 305.47 = 21+37.50 + 3+05.47 = 24+42.97
\]
---
### **i. High/Low Point Elevation**
Plug \( x = 305.47 \) into the curve equation:
\[
y = 954.2375 - 0.0230 \times 305.47 + 0.00003765 \times (305.47)^2
\]
\[
= 954.2375 - 7.0258 + 3.501 = 950.7127\,\text{ft}
\]
---
### **j. Elevation at station 29+70.00**
Station 29+70.00 = 2970 ft
\[
x = 2970 - 2137.5 = 832.5\,\text{ft}
\]
But EVC is at 2562.5, so x = 832.5 is **beyond the EVC** (the curve only covers up to x = 425 ft). So at this station, the elevation is on the final tangent.
Final tangent equation (from EVC):
- Final tangent grade: \( g_2 = +0.0090 \)
- Elev at EVC \( y_{\text{EVC}} \):
\[
x_{\text{EVC}} = 425.0\,\text{ft}
\]
\[
y_{\text{EVC}} = 954.2375 - 0.0230 \times 425 + 0.00003765 \times 425^2
\]
\[
= 954.2375 - 9.775 + 6.803 \\
= 951.2655\,\text{ft}
\]
Distance from EVC to 29+70.00:
\[
2970 - 2562.5 = 407.5\,\text{ft}
\]
\[
y = y_{\text{EVC}} + g_2 \times (\text{distance from EVC})
\]
\[
= 951.2655 + 0.0090 \times 407.5 = 951.2655 + 3.6675 = 954.9330\,\text{ft}
\]
---
### **k. Elevation on the curve at a point 250.00 ft from the BVC**
\( x = 250.00 \) ft
\[
y = 954.2375 - 0.0230 \times 250.00 + 0.00003765 \times (250.00)^2
\]
\[
= 954.2375 - 5.75 + 2.353 = 950.8405\,\text{ft}
\]
---
# **Summary Table**
| Sta | x (ft) | Elev (Curve) | Elev (Tangent) | Offset |
|--------|--------|--------------|----------------|---------|
|22+00 | 62.5 | 952.95 | 952.80 | 0.147 |
|23+00 | 162.5 | 951.49 | 950.50 | 0.99 |
|24+00 | 262.5 | 950.79 | 948.20 | 2.59 |
|25+00 | 362.5 | 950.84 | 945.90 | 4.94 |
---
## **Final Answers**
### **e. Elevations on the curve at full stations**
- 22+00: **952.95 ft**
- 23+00: **951.49 ft**
- 24+00: **950.79 ft**
- 25+00: **950.84 ft**
### **f. Elevations on the tangents at full stations**
- 22+00: **952.80 ft**
- 23+00: **950.50 ft**
- 24+00: **948.20 ft**
- 25+00: **945.90 ft**
### **g. Tangent offsets at full stations**
- 22+00: **0.15 ft**
- 23+00: **0.99 ft**
- 24+00: **2.59 ft**
- 25+00: **4.94 ft**
### **h. High/low point station**
- **24+42.97**
### **i. High/low point elevation**
- **950.71 ft**
### **j. Elevation at station 29+70.00**
- **954.93 ft** (on the final tangent)
### **k. Elevation 250 ft from BVC**
- **950.84 ft**
---
**Let me know if you need the calculations for other stations or explanations for any particular step!**
Question:
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This is AI generated Response.
Asked by: Md Israrul Haque
Created at: 2025-08-26 00:15:59
Final Answer:
RenderedRaw Text
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