Solve the question as stated with a graph and solve the question in 2 steps with examples and the final answer.Q1: (14 Mark)
For loaded beam shown in figure (1), Draw S.F. and B
.M. diagrams for the beam, stating the main values
and find the maximum compression and tension stress
which can setup in the beam.
(All dimensions in mm)
Figure (1)
Question:
Solve the question as stated with a graph and solve the question in 2 steps with examples and the final answer.Q1: (14 Mark)
For loaded beam shown in figure (1), Draw S.F. and B
.M. diagrams for the beam, stating the main values
and find the maximum compression and tension stress
which can setup in the beam.
(All dimensions in mm)
Figure (1)
This is AI generated Response.
Asked by: Mack
Created at: 2025-12-24 20:27:42
Final Answer:
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# Solution to Q1: Shear Force (S.F.) and Bending Moment (B.M.) Diagrams
## Step 1: **Draw S.F. and B.M. Diagrams**
**Note:**
The question refers to "Figure (1)", but the image of the beam is not provided. For demonstration, let's assume a simply supported beam of length \( L = 400 \) mm with a point load \( P = 20 \) kN at the center. (You can replace these values with the actual values from your figure.)
### **Example Beam:**
- **Length, \( L \) = 400 mm**
- **Point load, \( P \) = 20 kN at center (200 mm from each support)**
#### **A. Calculate Reactions at Supports**
For a simply supported beam with central load:
\[
R_A = R_B = \frac{P}{2} = \frac{20\,\text{kN}}{2} = 10\,\text{kN}
\]
#### **B. Shear Force Diagram (S.F.)**
- From A to load: S.F. = \( +10 \) kN
- Just right of load: S.F. = \( +10 - 20 = -10 \) kN
- From load to B: S.F. = \( -10 \) kN
#### **C. Bending Moment Diagram (B.M.)**
- At supports (A and B): \( M = \)
- At center (under load):
\[
M_{\text{max}} = R_A \times \frac{L}{2} = 10\,\text{kN} \times 2\,\text{m} = 20\,\text{kN}\cdot\text{m} = 20,000\,\text{Nm}
\]
---
### **Diagrams**
#### Shear Force Diagram (S.F.)
```
S.F. (kN)
| ________
10| |
| |
|_______|_________
-10 200 400 (mm)
(load)
```
#### Bending Moment Diagram (B.M.)
```
B.M. (Nm)
| /\
| / \
| / \
|________/ \__________
200 400 (mm)
(Max M=20,000 Nm)
```
---
## Step 2: **Find Maximum Compression and Tension Stress**
### **A. Maximum Bending Stress Formula**
\[
\sigma_{\text{max}} = \frac{M_{\text{max}} \cdot y}{I}
\]
- \( M_{\text{max}} \): Maximum moment (Nm)
- \( y \): Distance from neutral axis to outer fiber (mm)
- \( I \): Moment of inertia (mm\(^4\))
### **B. Example Calculation**
Assume beam cross-section:
- **Width, \( b = 100 \) mm**
- **Height, \( h = 200 \) mm**
\[
I = \frac{b h^3}{12} = \frac{100 \times (200)^3}{12} = 66,666,667\,\text{mm}^4
\]
\[
y = \frac{h}{2} = 100\,\text{mm}
\]
\[
\sigma_{\text{max}} = \frac{20,000,000\,\text{Nmm} \times 100\,\text{mm}}{66,666,667\,\text{mm}^4}
= 30\,\text{N/mm}^2
\]
---
### **Final Answers**
- **Maximum Shear Force**: \( 10 \) kN (at supports, just before/after load)
- **Maximum Bending Moment**: \( 20,000 \) Nm (at center)
- **Maximum Bending Stress**: \( 30\,\text{N/mm}^2 \) (Compression at top fiber, tension at bottom fiber)
---
## **Summary Table**
| Parameter | Value | Location |
|----------------------------|---------------|------------------|
| Max Shear Force (S.F.) | \(10\) kN | At supports |
| Max Bending Moment (B.M.) | \(20,000\) Nm | At beam center |
| Max Compression/Tension | \(30\) N/mm² | Top/Bottom fiber |
---
**Note:** Replace example values with actual values from your specific figure for your answer.
---
**[Insert your diagram here, matching your beam's actual loading and supports]**
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