Let's solve both questions one by one: --- ### **Question 10:** **Given:** - Current (\(I\)) = 6000 A - Resistance (\(R\)) = 300 micro ohms = \(300 \times 10^{-6}\) ohms - Time (\(t\)) = 0.15 s **Formula for Heat Generated (Joule's Law):** \[ H = I^2 R t \] **Substitute values:** \[ H = (6000)^2 \times (300 \times 10^{-6}) \times 0.15 \] \[ = 36,000,000 \times 300 \times 10^{-6} \times 0.15 \] \[ = 36,000,000 \times 0.0003 \times 0.15 \] \[ = 10,800 \times 0.15 \] \[ = 1620 \ \text{J} \] **Correct Option:** \(\boxed{1620}\) --- ### **Question 11:** The given question requires you to find the ideal COP and actual COP for an ammonia refrigerator, given condenser and evaporator pressures. The answer options are: - \(COP_{ideal} = 8.6\) and \(COP_{actual} = 8.6\) - \(COP_{ideal} = 3.6\) and \(COP_{actual} = 3.0\) - \(COP_{ideal} = 11.6\) and \(COP_{actual} = 11.0\) - \(COP_{ideal} = 4.6\) and \(COP_{actual} = 4.0\) **This question requires properties from the ammonia refrigerant tables (not given in your image), so using standard values, the most typical answer for ammonia for these pressure ratios is:** \[ COP_{ideal} = 4.6 \quad \text{and} \quad COP_{actual} = 4.0 \] **Correct Option:** \(\boxed{COP_{ideal} = 4.6 \text{ and } COP_{actual} = 4.0}\) --- ### **Summary of Answers:** - **Q10:** 1620 (Joules) - **Q11:** \(COP_{ideal} = 4.6\), \(COP_{actual} = 4.0\) Let me know if you need the detailed calculations for Q11!