Solve correct optionET NT Re oe a : Ena ee
Question:
Solve correct option
ET
NT Re
oe a
: Ena
ee
This is AI generated Response.
Asked by: Raju
Created at: 2025-10-28 10:29:11
Asked by: Raju
Created at: 2025-10-28 10:29:11
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Given data:
- Thermal conductivity, \(k = 205 \, \text{W/m}circ \text{C}\)
- Thickness of the layer, \(d = 25 \, \text{mm} = .025 \, \text{m}\)
- Temperature difference, \(\Delta T = 27^\circ \text{C} - ^\circ \text{C} = 27^\circ \text{C}\)
The heat flux \(Q\) through the layer (assuming steady state conduction) can be found using Fourier's law:
\[
Q = \frac{k \times \Delta T}{d}
\]
Substituting the values:
\[
Q = \frac{205 \times 27}{.025} = \frac{5535}{.025} = 221400 \, \text{W/m}^2
\]
The question asks for the heat flux value, which matches closest to **30** in the options.
**Correct option: 30**
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