Let's solve the problem step by step: ### **Question Recap** > Consider a blackbody at 300K with maximum emissive power. Calculate the wavelength (μm) of the emissions. ### **Relevant Formula** Use **Wien's Displacement Law**: \[ \lambda_{max} = \frac{b}{T} \] Where: - \(\lambda_{max}\) = Wavelength of maximum emission (in meters) - \(b = 2.898 \times 10^{-3} \ \text{m·K}\) (Wien's constant) - \(T\) = Temperature in Kelvin ### **Calculation** Given \(T = 300 K\): \[ \lambda_{max} = \frac{2.898 \times 10^{-3}}{300} \] \[ \lambda_{max} = 9.66 \times 10^{-6} \ \text{m} \] Convert meters to micrometers (\(1 \ \mu m = 10^{-6} \ \text{m}\)): \[ \lambda_{max} = 9.66 \ \mu m \] ### **Correct Option** - **9.7 μm** ### **Final Answer** The correct answer is: > **9.7 μm**