solve completely with complete elaboration , Calculate the required press tonnage to blank a 3 0 mm diameter circle from 2 mm thick mild steel sheet with shear strength of 3 0 0 MPa.
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solve completely with complete elaboration , Calculate the required press tonnage to blank a 3 0 mm diameter circle from 2 mm thick mild steel sheet with shear strength of 3 0 0 MPa.
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Asked by: manish kumar
Created at: 2025-12-18 10:19:55
Asked by: manish kumar
Created at: 2025-12-18 10:19:55
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# Calculating Required Press Tonnage for Blanking
We are given:
- **Blank diameter (\(d\))**: 30 mm
- **Sheet thickness (\(t\))**: 2 mm
- **Shear strength of material (\(\tau\))**: 300 MPa
Let's solve step by step.
---
## 1. **Determine the Force Required (Shear Force Formula)**
The force required to blank a circular sheet (assuming the material is sheared along the circumference) is:
\[
F = \text{Perimeter} \times \text{Thickness} \times \text{Shear Strength}
\]
Where:
- **Perimeter of the blank** (\(P\)): \(P = \pi d\)
- **Thickness** (\(t\)): sheet thickness
- **Shear Strength** (\(\tau\)): as given
Plug in values:
- \(d = 30\,\text{mm} = .03\,\text{m}\)
- \(t = 2\,\text{mm} = .002\,\text{m}\)
- \(\tau = 300\,\text{MPa} = 300 \times 10^6\,\text{N/m}^2\)
First, calculate the perimeter:
\[
P = \pi d = \pi \times 30\,\text{mm} = \pi \times .03\,\text{m} \approx .0942\,\text{m}
\]
Now, calculate the force:
\[
F = P \times t \times \tau
\]
\[
F = .0942\,\text{m} \times .002\,\text{m} \times 300 \times 10^6\,\text{N/m}^2
\]
\[
F = .0942 \times .002 \times 300 \times 10^6
\]
\[
F = .0001884 \times 300 \times 10^6
\]
\[
F = 56,520\,\text{N}
\]
---
## 2. **Convert Force to Tonnes (Press Tonnage)**
1 tonne-force (\(\text{tf}\)) \(= 9,806\,\text{N}\) (approx 10,000 N for rough calculations, but use precise value for accuracy).
\[
\text{Tonnage} = \frac{F}{9,806}
\]
\[
\text{Tonnage} = \frac{56,520}{9,806}
\]
\[
\text{Tonnage} \approx 5.76\,\text{tonnes}
\]
---
## 3. **Summary Table**
| Parameter | Value |
|-------------------|-------------------|
| Diameter (\(d\)) | 30 mm |
| Thickness (\(t\)) | 2 mm |
| Shear Strength (\(\tau\)) | 300 MPa |
| Shear Force (\(F\)) | 56,520 N |
| Required Tonnage | 5.76 tonnes |
---
## 4. **Conclusion**
**The required press tonnage to blank a 30 mm diameter circle from 2 mm thick mild steel sheet with a shear strength of 300 MPa is approximately 5.8 tonnes.**
---
### Diagram (for reference)

*Alt text: Diagram showing blanking of a circular disc from a metal sheet, indicating punch diameter and thickness.*
---
## **Notes**
- Always round up the tonnage slightly for safety. In practice, a 6-ton or 10-ton press would be chosen.
- If material properties or actual cutting conditions differ, recalculate accordingly.
- Add a safety factor as per industry standards (commonly 1.2–1.5 times calculated force).
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