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Asked by: Alok Kumar
Created at: 2025-05-24 19:45:01

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Let's analyze the given reaction: The starting compound is a **benzoin** derivative (benzyl phenyl ketone): **Structure:** - Two benzene rings attached to a central carbon, which is attached to a COCH3 group. - In chemical notation: **C6H5-CH(C6H5)-COCH3** **Reagent:** **HBr** (Hydrobromic acid) --- ### **Expected Reaction** This compound contains a carbonyl group (ketone) adjacent to a benzylic carbon (the carbon attached to two phenyl groups). **With HBr:** - The most reactive site is the **benzylic position** (the carbon attached to two phenyl groups). - HBr can cause cleavage at this site, especially if there is a possibility for resonance-stabilized carbocation formation. #### **Mechanism** 1. **Protonation of the carbonyl oxygen** (increases electrophilicity). 2. **Cleavage of the C-CO bond** to form a resonance-stabilized benzhydryl cation (**Ph2C⁺**). 3. **Nucleophilic attack by Br⁻** to form **benzhydryl bromide** (**Ph2CHBr**). 4. The other fragment is **acetaldehyde** (**CH3CHO**). #### **Products:** 1. **Benzhydryl bromide** (**Diphenylmethyl bromide**, Ph2CHBr) 2. **Acetaldehyde** (**CH3CHO**) --- ### **Final Answer:** The reaction yields **benzhydryl bromide** and **acetaldehyde**. #### **Chemical Equation:** ``` Ph-CH(COCH3)-Ph + HBr → Ph2CHBr + CH3CHO ``` #### **Product structures:** - **Ph2CHBr:** A central carbon attached to two benzene rings and a bromine atom. - **CH3CHO:** Acetaldehyde. --- **Summary Table:** | Reactant | Reagent | Product 1 | Product 2 | |----------------------------------|---------|-------------------|---------------| | Ph-CH(COCH3)-Ph | HBr | Ph2CHBr | CH3CHO | Let me know if you need the mechanism step-by-step or a drawn structure!

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