Red light with a vacuum wavelength of 620 nm is incident from air on a piece of glass (n = 1.52) covered with a thin film (n = 1.68) What is the minimum thickness of the film so that a constructive interference takes place? give final answer only
Question:
Red light with a vacuum wavelength of 620 nm is incident from air on a piece of glass (n = 1.52) covered with a thin film (n = 1.68) What is the minimum thickness of the film so that a constructive interference takes place? give final answer only
This is AI generated Response.
Asked by: manish kumar
Created at: 2026-01-16 07:56:32
Asked by: manish kumar
Created at: 2026-01-16 07:56:32
Final Answer:
Rendered
Raw Text
Did you like this answer?
**Minimum thickness of the film for constructive interference:**
$$
d = \frac{\lambda}{4n_{\text{film}}}
$$
where
\(\lambda = 620\,\text{nm}\) (wavelength in vacuum),
\(n_{\text{film}} = 1.68\) (refractive of the film).
**Final answer:**
$$
d = \frac{620\,\text{nm}}{4 \times 1.68} = 92.3\,\text{nm}
$$
📢 Instructions:
- Ask anything relatd to above question only.
- For new Question goto :
VIPSolutions