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Asked by: Gurubindra Singh
Created at: 2025-08-20 19:22:26
Final Answer:
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Given matrix A = [2 1 ; 3 4]
Step 1: Find the determinant of A.
Determinant = (2 * 4) - (1 * 3) = 8 - 3 = 5
Step 2: Swap the elements on the main diagonal and change the signs of the off-diagonal elements.
So, swap 2 and 4, and change the sign of 1 and 3:
This gives the matrix [4 -1 ; -3 2]
Step 3: Divide each element by the determinant.
So, the inverse A^-1 = [4/5 -1/5 ; -3/5 2/5]
Step 4: Verify by multiplying A and A^-1 to get the identity matrix:
Multiply [2 1 ; 3 4] by [4/5 -1/5 ; -3/5 2/5]:
First row: (2 * 4/5) + (1 * -3/5) = 8/5 - 3/5 = 1
(2 * -1/5) + (1 * 2/5) = -2/5 + 2/5 = 0
Second row: (3 * 4/5) + (4 * -3/5) = 12/5 - 12/5 = 0
(3 * -1/5) + (4 * 2/5) = -3/5 + 8/5 = 1
So we get the identity matrix [1 0 ; 0 1].
Final answer:
The inverse of matrix A is [4/5 -1/5 ; -3/5 2/5].
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