Provide answer in 100 words7:25 N RB. 80%a
(©) & i] bo .
“vr 1 vP Pr v1 L111
“111 vr 1 L111
“1 1 111111
2a 1 1 1 11 1 ES
1#1 , English(India) j J
9 II ® Vv

Question

Provide answer in 100 words7:25 N RB. 80%a
(©) & i] bo .
“vr 1 vP Pr v1 L111
“111 vr 1 L111
“1 1 111111
2a 1 1 1 11 1 ES
1#1 , English(India) j J
9 II ® Vv

VIPSolutions · Accepted Answer

To form a 6-digit number using the digits 1, 2, 3, 4, 5, and 6 without repeating any digit, we need to arrange all 6 digits in every possible order. This is a permutation problem. The number of ways to arrange 6 distinct digits is 6! (6 factorial).  
6! = 6 × 5 × 4 × 3 × 2 × 1 = 720  
Therefore, there are **720 distinct 6-digit numbers** that can be formed using the digits 1, 2, 3, 4, 5, and 6 without repeating any digit.

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Provide answer in 100 words7:25 N RB. 80%a (©) & i] bo . “vr 1 vP Pr v1 L111 “111 vr 1 L111 “1 1 111111 2a 1 1 1 11 1 ES 1#1 , English(India) j J 9 II ® Vv

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