This is AI generated Response.
Asked by: Rahul
Created at: 2025-12-05 07:45:42
Final Answer:
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Let's proceed step by step, as you requested, for the given argument:
**Premises:**
1. ~H ⊃ B
2. ~H ⊃ D
3. ~(B • D)
**Conclusion:**
H
---
### **Step 1: Assume ~H (Indirect Proof / Reductio ad Absurdum)**
- **Assumption for Indirect Proof (AIP):**
Assume ~H.
**Explanation:**
We use indirect proof by assuming the negation of what we want to prove (i.e., assume ~H). If this leads to a contradiction, then H must be true.
---
### **Step 2: Derive B and D Using Modus Ponens, Then a Contradiction**
- **From premise 1 (~H ⊃ B) and our assumption (~H):**
By Modus Ponens, we get B.
- **From premise 2 (~H ⊃ D) and our assumption (~H):**
By Modus Ponens, we get D.
- **Now, combine B and D:**
By Conjunction, B • D.
- **But premise 3 says ~(B • D):**
We have a contradiction.
**Explanation:**
Assuming ~H leads us to both B and D, which gives us (B • D). But premise 3 says ~(B • D) is true, so our assumption (~H) must be false.
---
### **Final Answer**
#### **Therefore, H is true.**
**Summary:**
- **Step 1:** Assume ~H (AIP).
- **Step 2:** Derive B and D using premises 1 and 2, leading to a contradiction with premise 3.
- **Conclusion:** H (by Indirect Proof).
---
**Reference Lines:**
1. ~H ⊃ B (Premise)
2. ~H ⊃ D (Premise)
3. ~(B • D) (Premise)
4. ~H (Assumption for Indirect Proof)
5. B (Modus Ponens, 1, 4)
6. D (Modus Ponens, 2, 4)
7. B • D (Conjunction, 5, 6)
8. ~(B • D) (Premise, 3)
9. Contradiction (7, 8)
10. H (Indirect Proof, 4–9)
---
**Conclusion:**
**H** is the valid conclusion.
Question:
Please solved correct answer
This is AI generated Response.
Asked by: Rahul
Created at: 2025-12-05 07:46:24
Final Answer:
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# Deriving the Conclusion Using Rules of Inference
## **Premises**
1. \( \sim H \supset B \)
2. \( \sim H \supset D \)
3. \( \sim (B \cdot D) \)
## **Conclusion**
H
---
### **Step 1: Assume \( \sim H \) (Indirect Proof / Reductio ad Absurdum)**
- **Line 4:** Assume \( \sim H \).
**Explanation:**
We begin by assuming the negation of what we wish to prove (i.e., \( \sim H \)). If this assumption leads to a contradiction, we can conclude that H must be true.
---
### **Step 2: Derive B and D, Leading to a Contradiction**
- **Line 5:** From premise 1 and assumption \( \sim H \):
By **Modus Ponens**, we conclude \( B \) (from lines 1 and 4).
- **Line 6:** From premise 2 and assumption \( \sim H \):
By **Modus Ponens**, we conclude \( D \) (from lines 2 and 4).
- **Line 7:** Combine B and D:
\( B \cdot D \) (by **Conjunction**, from lines 5 and 6).
- **Line 8:** Reference premise 3:
\( \sim (B \cdot D) \) (premise).
- **Line 9:** Contradiction:
We have \( B \cdot D \) and \( \sim (B \cdot D) \). This is a contradiction.
**Explanation:**
The assumption \( \sim H \) allows us to derive both \( B \) and \( D \), leading to \( B \cdot D \). However, since premise 3 states \( \sim (B \cdot D) \), this creates a contradiction, indicating that our initial assumption must be false.
---
### **Final Answer**
#### **Therefore, H is true.**
**Summary of Steps:**
- **Step 1:** Assume \( \sim H \) (AIP).
- **Step 2:** Derive \( B \) and \( D \) using premises 1 and 2, leading to a contradiction with premise 3.
---
### **Reference Lines**
1. \( \sim H \supset B \) (Premise)
2. \( \sim H \supset D \) (Premise)
3. \( \sim (B \cdot D) \) (Premise)
4. \( \sim H \) (Assumption for Indirect Proof)
5. \( B \) (Modus Ponens, 1, 4)
6. \( D \) (Modus Ponens, 2, 4)
7. \( B \cdot D \) (Conjunction, 5, 6)
8. \( \sim (B \cdot D) \) (Premise, 3)
9. Contradiction (7, 8)
10. H (Indirect Proof, 4–9)
---
**Conclusion:**
**H** is the valid conclusion.
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