please solve this problem step by stepETRE |
A Faraday pail consists of a'small cylinder within allarge cylinder, where the ends of the cylinders are
open. The inner and outer cylinders have|a height of 16.74cm and 19.63cm, respectively, aswell as
an inner and outer diameter of 7.97cm and 13.83cm, respectively. Determine the percent difference
(9%) between the Capacitance, assuming the parallel plate model and the cylindrical capacitor model.
For the parallel plate model, assume the area is the average area between the two cylinders. The
distance between the cylinders 'd" is the outer radius. subtracted from the inner radius.
| i
Area Equation: 4 — 27rh Ha ith li
| | (AA
ferelelbite Modell LL cee HA
IEEE
Cylindrical Capacitor Model: Ceytinder = mE 3) HH HHH
HHH Fes RATER) 1 i
rey AMEE 1
Question:
please solve this problem step by stepETRE |
A Faraday pail consists of a'small cylinder within allarge cylinder, where the ends of the cylinders are
open. The inner and outer cylinders have|a height of 16.74cm and 19.63cm, respectively, aswell as
an inner and outer diameter of 7.97cm and 13.83cm, respectively. Determine the percent difference
(9%) between the Capacitance, assuming the parallel plate model and the cylindrical capacitor model.
For the parallel plate model, assume the area is the average area between the two cylinders. The
distance between the cylinders 'd" is the outer radius. subtracted from the inner radius.
| i
Area Equation: 4 — 27rh Ha ith li
| | (AA
ferelelbite Modell LL cee HA
IEEE
Cylindrical Capacitor Model: Ceytinder = mE 3) HH HHH
HHH Fes RATER) 1 i
rey AMEE 1
This is AI generated Response.
Asked by: Mohin
Created at: 2025-10-17 21:55:33
Final Answer:
RenderedRaw Text
Did you like this answer?
Let's solve the problem step by step.
---
## **Given Values**
- **Height of inner cylinder, \( h_1 \)**: 16.74 cm
- **Height of outer cylinder, \( h_2 \)**: 19.63 cm
- **Diameter of inner cylinder, \( d_1 \)**: 7.97 cm
- **Diameter of outer cylinder, \( d_2 \)**: 13.83 cm
- **Permittivity of free space, \( \epsilon_ \)**: \( 8.854 \times 10^{-12} \) F/m
---
## **Step 1: Convert All Units to Meters**
- \( h_1 = .1674 \) m
- \( h_2 = .1963 \) m
- \( d_1 = .0797 \) m
- \( d_2 = .1383 \) m
---
## **Step 2: Radii and Average Height**
- Inner radius: \( r_1 = \frac{d_1}{2} = .03985 \) m
- Outer radius: \( r_2 = \frac{d_2}{2} = .06915 \) m
- Average height:
\( h_\text{avg} = \frac{h_1 + h_2}{2} = \frac{.1674 + .1963}{2} = .18185 \) m
---
## **Step 3: Parallel Plate Model**
### **Area**
- \( A_\text{avg} = 2\pi r_\text{avg} h_\text{avg} \)
- Where \( r_\text{avg} = \frac{r_1 + r_2}{2} = \frac{.03985 + .06915}{2} = .0545 \) m
\[
A_\text{avg} = 2 \pi \cdot .0545 \cdot .18185 \approx .0623 \text{ m}^2
\]
### **Distance**
- \( d = r_2 - r_1 = .06915 - .03985 = .0293 \) m
### **Capacitance**
\[
C_\text{parallel} = \frac{\epsilon_ A_\text{avg}}{d} = \frac{8.854 \times 10^{-12} \times .0623}{.0293}
\]
\[
C_\text{parallel} \approx \frac{5.515 \times 10^{-13}}{.0293} \approx 1.88 \times 10^{-11} \text{ F}
\]
---
## **Step 4: Cylindrical Capacitor Model**
\[
C_\text{cylinder} = \frac{2\pi \epsilon_ h_\text{avg}}{\ln(r_2/r_1)}
\]
- \( \ln(r_2/r_1) = \ln(.06915/.03985) = \ln(1.735) \approx .551 \)
\[
C_\text{cylinder} = \frac{2\pi \cdot 8.854 \times 10^{-12} \cdot .18185}{.551}
\]
\[
= \frac{1.011 \times 10^{-11}}{.551} \approx 1.83 \times 10^{-11} \text{ F}
\]
---
## **Step 5: Percent Difference**
\[
\text{Percent Difference} = \frac{|C_\text{parallel} - C_\text{cylinder}|}{C_\text{cylinder}} \times 100\%
\]
\[
= \frac{|1.88 \times 10^{-11} - 1.83 \times 10^{-11}|}{1.83 \times 10^{-11}} \times 100\%
\]
\[
= \frac{.05 \times 10^{-11}}{1.83 \times 10^{-11}} \times 100\%
\]
\[
\approx 2.73\%
\]
---
## **Final Answers**
- \( C_\text{parallel} \approx 1.88 \times 10^{-11} \) F
- \( C_\text{cylinder} \approx 1.83 \times 10^{-11} \) F
- **Percent Difference**: **2.73%**
---
Let me know if you'd like to see the calculations in more detail!
Question:
please give me the solution without any render equation errors with proper units
This is AI generated Response.
Asked by: Mohin
Created at: 2025-10-17 21:56:52
Final Answer:
RenderedRaw Text
Did you like this answer?
# Step-by-Step Solution to the Capacitor Problem
## Given Values
- **Height of inner cylinder, \( h_1 \)**: 16.74 cm
- **Height of outer cylinder, \( h_2 \)**: 19.63 cm
- **Diameter of inner cylinder, \( d_1 \)**: 7.97 cm
- **Diameter of outer cylinder, \( d_2 \)**: 13.83 cm
- **Permittivity of free space, \( \epsilon_0 \)**: \( 8.854 \times 10^{-12} \text{ F/m} \)
## Step 1: Convert All Units to Meters
- \( h_1 = 0.1674 \) m
- \( h_2 = 0.1963 \) m
- \( d_1 = 0.0797 \) m
- \( d_2 = 0.1383 \) m
## Step 2: Calculate Radii and Average Height
- **Inner radius**:
\( r_1 = \frac{d_1}{2} = 0.03985 \) m
- **Outer radius**:
\( r_2 = \frac{d_2}{2} = 0.06915 \) m
- **Average height**:
\( h_{\text{avg}} = \frac{h_1 + h_2}{2} = \frac{0.1674 + 0.1963}{2} = 0.18185 \) m
## Step 3: Calculate Capacitance Using Parallel Plate Model
### Area Calculation
- **Average radius**:
\( r_{\text{avg}} = \frac{r_1 + r_2}{2} = \frac{0.03985 + 0.06915}{2} = 0.0545 \) m
- **Area**:
\[
A_{\text{avg}} = 2\pi r_{\text{avg}} h_{\text{avg}}
\]
\[
A_{\text{avg}} = 2 \pi (0.0545)(0.18185) \approx 0.0623 \text{ m}^2
\]
### Distance Calculation
- **Distance between cylinders**:
\[
d = r_2 - r_1 = 0.06915 - 0.03985 = 0.0293 \text{ m}
\]
### Capacitance Calculation
\[
C_{\text{parallel}} = \frac{\epsilon_0 A_{\text{avg}}}{d} = \frac{8.854 \times 10^{-12} \times 0.0623}{0.0293}
\]
Calculating:
\[
C_{\text{parallel}} \approx \frac{5.515 \times 10^{-13}}{0.0293} \approx 1.88 \times 10^{-11} \text{ F}
\]
## Step 4: Calculate Capacitance Using Cylindrical Capacitor Model
### Capacitance Formula
\[
C_{\text{cylinder}} = \frac{2\pi \epsilon_0 h_{\text{avg}}}{\ln(r_2/r_1)}
\]
### Natural Logarithm Calculation
\[
\ln\left(\frac{r_2}{r_1}\right) = \ln\left(\frac{0.06915}{0.03985}\right) \approx \ln(1.735) \approx 0.551
\]
### Capacitance Calculation
\[
C_{\text{cylinder}} = \frac{2\pi (8.854 \times 10^{-12}) (0.18185)}{0.551}
\]
Calculating:
\[
C_{\text{cylinder}} \approx \frac{1.011 \times 10^{-11}}{0.551} \approx 1.83 \times 10^{-11} \text{ F}
\]
## Step 5: Calculate Percent Difference
### Percent Difference Formula
\[
\text{Percent Difference} = \frac{|C_{\text{parallel}} - C_{\text{cylinder}}|}{C_{\text{cylinder}}} \times 100\%
\]
### Calculation
\[
= \frac{|1.88 \times 10^{-11} - 1.83 \times 10^{-11}|}{1.83 \times 10^{-11}} \times 100\%
\]
\[
= \frac{0.05 \times 10^{-11}}{1.83 \times 10^{-11}} \times 100\%
\]
\[
\approx 2.73\%
\]
## Final Answers
- **Capacitance (Parallel Plate Model)**: \( C_{\text{parallel}} \approx 1.88 \times 10^{-11} \text{ F} \)
- **Capacitance (Cylindrical Model)**: \( C_{\text{cylinder}} \approx 1.83 \times 10^{-11} \text{ F} \)
- **Percent Difference**: **2.73%**
Feel free to ask if you need further clarification or additional calculations!
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