Please solve this problem step by step correctly[6] ‘Write the unit of current. Define the two common types of current with appropriate figure.
(i) A stove clement draws 15 A when connected to a 240-V line. How long does it take to
consume 60 kJ?
(ii) Ina household, a 120-W personal computer (PC) is run for 4 h/day, while a 60-W bulb runs
for 8 h/day. If the utility company charges $0.12/kWh, calculate how much the household
pays per year on the PC and the bulb.
Question:
Please solve this problem step by step correctly[6] ‘Write the unit of current. Define the two common types of current with appropriate figure.
(i) A stove clement draws 15 A when connected to a 240-V line. How long does it take to
consume 60 kJ?
(ii) Ina household, a 120-W personal computer (PC) is run for 4 h/day, while a 60-W bulb runs
for 8 h/day. If the utility company charges $0.12/kWh, calculate how much the household
pays per year on the PC and the bulb.
This is AI generated Response.
Asked by: Jack
Created at: 2025-10-08 06:49:31
Final Answer:
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Let's solve each part step by step:
---
## (i) **Unit of Current and Types of Current**
### **Unit of Current**
- The unit of electric current is the **ampere (A)**.
### **Two Common Types of Current**
1. **Direct Current (DC):**
- **Definition:** Electric current flows in one direction only.
- **Source Example:** Batteries.
- **Figure:**
```
DC: ──────────→
```
2. **Alternating Current (AC):**
- **Definition:** Electric current changes direction periodically.
- **Source Example:** Mains electricity (household supply).
- **Figure:**
```
AC: ~~~~~~~ (sinusoidal wave)
```
---
## (ii) **Stove Element Power Consumption**
Given:
- Current, \( I = 15\, \text{A} \)
- Voltage, \( V = 240\, \text{V} \)
- Energy to be consumed, \( E = 60\, \text{kJ} = 60,000\, \text{J} \)
### **Step 1: Calculate Power**
\[
P = V \times I = 240\, \text{V} \times 15\, \text{A} = 360\, \text{W}
\]
### **Step 2: Calculate Time to Consume 60 kJ**
\[
E = P \times t \implies t = \frac{E}{P}
\]
\[
t = \frac{60,000\, \text{J}}{360\, \text{W}} = 16.67\, \text{seconds}
\]
**Answer:**
It takes **16.67 seconds** to consume 60 kJ.
---
## (iii) **Annual Cost of Running PC and Bulb**
**Given:**
- PC: \( 120\, \text{W} \) for 4 h/day
- Bulb: \( 60\, \text{W} \) for 8 h/day
- Energy cost: $.12/kWh
### **Step 1: Daily Energy Used**
- PC: \( 120\, \text{W} \times 4\, \text{h} = 480\, \text{Wh} = .48\, \text{kWh} \)
- Bulb: \( 60\, \text{W} \times 8\, \text{h} = 480\, \text{Wh} = .48\, \text{kWh} \)
- Total per day: \( .48 + .48 = .96\, \text{kWh} \)
### **Step 2: Annual Energy Used**
\[
\text{Annual Energy} = .96\, \text{kWh/day} \times 365\, \text{days} = 350.4\, \text{kWh}
\]
### **Step 3: Annual Cost**
\[
\text{Annual Cost} = 350.4\, \text{kWh} \times \$.12/\text{kWh} = \$42.05
\]
**Answer:**
The household pays **\$42.05 per year** to run the PC and the bulb.
---
### **Summary Table**
| Appliance | Power (W) | Hours/Day | kWh/Day | kWh/Year | Cost/Year ($) |
|-----------|-----------|-----------|---------|----------|--------------|
| PC | 120 | 4 | .48 | 175.2 | 21.02 |
| Bulb | 60 | 8 | .48 | 175.2 | 21.02 |
| **Total** | | | .96 | 350.4 | 42.05 |
---
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