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Please convert the below content to rendered equations without any errors.Got it ? Let’s solve **each part step by step** and clearly arrive at the **simplified Boolean function**. --- ## **Given Question (from image)** **17. Simplify the function (F) together with the don’t care conditions and express the simplified function as:** * **(i) Sum of Products (SOP)** * **(ii) Sum of Minterms** --- ## **(a)** [ F(x,y,z)=\Sigma(0,1,4,5,6), \quad d(x,y,z)=\Sigma(2,3,7) ] ### **Step 1: Observe** * Total minterms for 3 variables = 8 → **0 to 7** * Given minterms + don’t cares cover **all minterms** ### **Step 2: Use don’t cares** Since all remaining minterms are don’t cares, we can group everything in the K-map. ### **Step 3: Simplification** Entire K-map becomes **1** [ \boxed{F = 1} ] ### **Final Answers** * **SOP:** (F = 1) * **Sum of minterms:** (\Sigma(0,1,2,3,4,5,6,7)) --- ## **(b)** [ F(A,B,C,D)=\Sigma(0,6,8,13,14), \quad d(A,B,C,D)=\Sigma(2,4,10) ] ### **Step 1: Plot on 4-variable K-map** * Use **1’s** for minterms * Use **X’s** for don’t cares ### **Step 2: Make largest possible groups** Using don’t cares, optimal groupings give: * Group 1 → (B'D') * Group 2 → (A'C) ### **Step 3: Write simplified function** [ \boxed{F = B'D' + A'C} ] ### **Step 4: Write as sum of minterms** Expand expression: * (B'D') → minterms: 0,2,8,10 * (A'C) → minterms: 6,14 [ \boxed{F = \Sigma(0,2,6,8,10,14)} ] --- ## **(c)** [ F(A,B,C,D)=\Sigma(5,6,7,12,14), \quad d(A,B,C,D)=\Sigma(3,9,11,15) ] ### **Step 1: K-map placement** * Mark **1’s** and **X’s** ### **Step 2: Grouping** Best groupings (using don’t cares): * Group 1 → (CD) * Group 2 → (BC) ### **Step 3: Simplified SOP** [ \boxed{F = CD + BC} ] ### **Step 4: Sum of minterms** * (CD) → 3,7,11,15 * (BC) → 6,7,14,15 Unique minterms: [ \boxed{F = \Sigma(3,6,7,11,14,15)} ] --- ## ✅ **Final Summary** | Part | Simplified SOP | Sum of Minterms | | ---- | -------------- | ------------------------ | | (a) | (1) | (\Sigma(0–7)) | | (b) | (B'D' + A'C) | (\Sigma(0,2,6,8,10,14)) | | (c) | (CD + BC) | (\Sigma(3,6,7,11,14,15)) | --- If you want, I can **draw the K-maps step-by-step** or **verify using Boolean algebra** too ?

Question:

Please convert the below content to rendered equations without any errors.Got it ? Let’s solve **each part step by step** and clearly arrive at the **simplified Boolean function**. --- ## **Given Question (from image)** **17. Simplify the function (F) together with the don’t care conditions and express the simplified function as:** * **(i) Sum of Products (SOP)** * **(ii) Sum of Minterms** --- ## **(a)** [ F(x,y,z)=\Sigma(0,1,4,5,6), \quad d(x,y,z)=\Sigma(2,3,7) ] ### **Step 1: Observe** * Total minterms for 3 variables = 8 → **0 to 7** * Given minterms + don’t cares cover **all minterms** ### **Step 2: Use don’t cares** Since all remaining minterms are don’t cares, we can group everything in the K-map. ### **Step 3: Simplification** Entire K-map becomes **1** [ \boxed{F = 1} ] ### **Final Answers** * **SOP:** (F = 1) * **Sum of minterms:** (\Sigma(0,1,2,3,4,5,6,7)) --- ## **(b)** [ F(A,B,C,D)=\Sigma(0,6,8,13,14), \quad d(A,B,C,D)=\Sigma(2,4,10) ] ### **Step 1: Plot on 4-variable K-map** * Use **1’s** for minterms * Use **X’s** for don’t cares ### **Step 2: Make largest possible groups** Using don’t cares, optimal groupings give: * Group 1 → (B'D') * Group 2 → (A'C) ### **Step 3: Write simplified function** [ \boxed{F = B'D' + A'C} ] ### **Step 4: Write as sum of minterms** Expand expression: * (B'D') → minterms: 0,2,8,10 * (A'C) → minterms: 6,14 [ \boxed{F = \Sigma(0,2,6,8,10,14)} ] --- ## **(c)** [ F(A,B,C,D)=\Sigma(5,6,7,12,14), \quad d(A,B,C,D)=\Sigma(3,9,11,15) ] ### **Step 1: K-map placement** * Mark **1’s** and **X’s** ### **Step 2: Grouping** Best groupings (using don’t cares): * Group 1 → (CD) * Group 2 → (BC) ### **Step 3: Simplified SOP** [ \boxed{F = CD + BC} ] ### **Step 4: Sum of minterms** * (CD) → 3,7,11,15 * (BC) → 6,7,14,15 Unique minterms: [ \boxed{F = \Sigma(3,6,7,11,14,15)} ] --- ## ✅ **Final Summary** | Part | Simplified SOP | Sum of Minterms | | ---- | -------------- | ------------------------ | | (a) | (1) | (\Sigma(0–7)) | | (b) | (B'D' + A'C) | (\Sigma(0,2,6,8,10,14)) | | (c) | (CD + BC) | (\Sigma(3,6,7,11,14,15)) | --- If you want, I can **draw the K-maps step-by-step** or **verify using Boolean algebra** too ?

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Asked by: jack
Created at: 2026-03-01 23:54:57

Final Answer:

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# Boolean Function Simplification — Rendered Equations --- ## (a) Given: \[ F(x,y,z) = \Sigma(,1,4,5,6), \quad d(x,y,z) = \Sigma(2,3,7) \] ### Solution - All minterms are either 1 or don't care. - Thus, the simplified function is: \[ F(x,y,z) = 1 \] **Sum of Products (SOP):** \[ F = 1 \] **Sum of Minterms:** \[ F(x,y,z) = \Sigma(,1,2,3,4,5,6,7) \] --- ## (b) Given: \[ F(A,B,C,D) = \Sigma(,6,8,13,14), \quad d(A,B,C,D) = \Sigma(2,4,10) \] ### Solution - Grouping with don't cares gives: - \( B'D' \) - \( A'C \) \[ F(A,B,C,D) = B'D' + A'C \] **Sum of Minterms:** - \( B'D' \) covers: \( ,2,8,10 \) - \( A'C \) covers: \( 6,14 \) \[ F(A,B,C,D) = \Sigma(,2,6,8,10,14) \] --- ## (c) Given: \[ F(A,B,C,D) = \Sigma(5,6,7,12,14), \quad d(A,B,C,D) = \Sigma(3,9,11,15) \] ### Solution - Grouping with don't cares gives: - \( CD \) - \( BC \) \[ F(A,B,C,D) = CD + BC \] **Sum of Minterms:** - \( CD \) covers: \( 3,7,11,15 \) - \( BC \) covers: \( 6,7,14,15 \) - Combine and remove duplicates: \( 3,6,7,11,14,15 \) \[ F(A,B,C,D) = \Sigma(3,6,7,11,14,15) \] --- ## Summary Table | Part | Simplified SOP | Sum of Minterms | |------|------------------------|--------------------------------| | (a) | \( 1 \) | \( \Sigma(,1,2,3,4,5,6,7) \) | | (b) | \( B'D' + A'C \) | \( \Sigma(,2,6,8,10,14) \) | | (c) | \( CD + BC \) | \( \Sigma(3,6,7,11,14,15) \) |

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