Part A
.
(
2
0
points
)
An assembly plant purchases
2
0
,
0
0
0
air filters per year. Fixed order cost is $
6
0
0
.
The company uses an inventory holding cost rate of
0
.
4
per year. The vendor has offered the following price schedule: For the first
3
0
0
units, the unit purchase cost is $
1
0
.
Any additional units can be purchased at $
5
per unit. For example, if you purchase
3
0
1
units, your total purchase cost will be $
3
,
0
0
5
.
What are the optimal order quantity and the corresponding optimal total cost per unit time?
Question:
Part A
.
(
2
0
points
)
An assembly plant purchases
2
0
,
0
0
0
air filters per year. Fixed order cost is $
6
0
0
.
The company uses an inventory holding cost rate of
0
.
4
per year. The vendor has offered the following price schedule: For the first
3
0
0
units, the unit purchase cost is $
1
0
.
Any additional units can be purchased at $
5
per unit. For example, if you purchase
3
0
1
units, your total purchase cost will be $
3
,
0
0
5
.
What are the optimal order quantity and the corresponding optimal total cost per unit time?
This is AI generated Response.
Asked by: Veera manikanta
Created at: 2025-09-04 05:23:10
Final Answer:
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Let's break down the problem step by step:
### **Given Data**
- **Annual demand, \(D\)**: 20,000 units/year
- **Order cost, \(S\)**: \$600 per order
- **Holding cost rate, \(h\)**: 0.4 per year (i.e., 40% of unit cost per year)
- **Price schedule**:
- First 300 units in any order: \$10/unit
- Units beyond 300: \$5/unit
If you order \(Q\) units:
- If \(Q \leq 300\): All units cost \$10/unit
- If \(Q > 300\): First 300 units at \$10, remaining \(Q-300\) at \$5
---
### **Step 1: Express Purchase Cost per Order**
If you order \(Q\) units:
- **If \(Q \leq 300\):** Total purchase cost = \(10Q\)
- **If \(Q > 300\):** Total purchase cost = \(10 \times 300 + 5 \times (Q-300) = 3000 + 5(Q-300) = 5Q + 1500\)
So, average unit price for \(Q > 300\):
\[
\text{Average unit price} = \frac{5Q + 1500}{Q}
\]
---
### **Step 2: Economic Order Quantity (EOQ) Approach**
Let’s first ignore the price break and find EOQ as if the price per unit is constant.
#### **Case 1: All units at \$10 (if order size ≤ 300 units)**
- Holding cost per unit per year: \(hC = 0.4 \times 10 = \$4\)
- EOQ formula:
\[
Q^* = \sqrt{\frac{2DS}{hC}} = \sqrt{\frac{2 \times 20000 \times 600}{4}} = \sqrt{\frac{24,000,000}{4}} = \sqrt{6,000,000} \approx 2449.49
\]
- But this is **much greater than 300**, so this case is not possible if we want to use EOQ.
#### **Case 2: Price Break (\$5/unit for Q > 300)**
- Holding cost per unit per year: \(hC = 0.4 \times 5 = \$2\)
- EOQ formula:
\[
Q^* = \sqrt{\frac{2DS}{hC}} = \sqrt{\frac{2 \times 20000 \times 600}{2}} = \sqrt{\frac{24,000,000}{2}} = \sqrt{12,000,000} \approx 3464.1
\]
- This is **greater than 300**, so this order quantity is feasible for the discount.
---
### **Step 3: Total Cost Calculation**
The **Total Cost per Year** is:
\[
\text{Total Cost} = \text{Purchase Cost} + \text{Order Cost} + \text{Holding Cost}
\]
Where:
- Purchase Cost = \(D \times \) (average price per unit)
- Order Cost = \(\frac{D}{Q} \times S\)
- Holding Cost = Average inventory \(\times\) Holding cost per unit = \(\frac{Q}{2} \times hC\)
#### **Case 1: Order Q ≤ 300 (All at \$10/unit)**
Try \(Q = 300\):
- Purchase cost: \(20,000 \times 10 = \$200,000\)
- Order cost: \(20,000/300 \times 600 = 66.67 \times 600 = \$40,000\)
- Holding cost: \(300/2 \times 4 = 150 \times 4 = \$600\)
- **Total cost:** \(200,000 + 40,000 + 600 = \$240,600\)
#### **Case 2: Order Q = EOQ ≈ 3464 (Price break for units > 300)**
- Average price per unit:
\[
\text{Total purchase cost per cycle} = 300 \times 10 + (3464-300) \times 5 = 3000 + 3164 \times 5 = 3000 + 15,820 = \$18,820
\]
\[
\text{Average price per unit} = 18,820/3464 \approx \$5.43
\]
- Yearly purchase cost: \(20,000 \times 5.43 = \$108,600\)
- Order cost: \(20,000/3464 \times 600 = 5.77 \times 600 = \$3,462\)
- Holding cost: \(3464/2 \times 2 = 1,732 \times 2 = \$3,464\)
- **Total cost:** \(108,600 + 3,462 + 3,464 = \$115,526\)
#### **Case 3: Order Q just above 300 (say, 301 units)**
- Total purchase cost per cycle: \(300 \times 10 + 1 \times 5 = 3,005\)
- Average price per unit: \(3,005/301 \approx \$9.9867\)
- Yearly purchase cost: \(20,000 \times 9.9867 = \$199,734\)
- Order cost: \(20,000/301 \times 600 = 66.445 \times 600 = \$39,867\)
- Holding cost: \(301/2 \times 2 = 150.5 \times 2 = \$301\)
- **Total cost:** \(199,734 + 39,867 + 301 = \$239,902\)
---
### **Step 4: Conclusion**
- Ordering at EOQ (3464 units) gives total annual cost of **\$115,526**.
- Ordering at Q = 300 or Q = 301 costs over \$239,000.
- **Optimal order quantity is 3,464 units, using the price break.**
---
## **Final Answers**
### **Optimal Order Quantity:**
\[
\boxed{3,464 \text{ units (rounded to the nearest unit)}}
\]
### **Corresponding Optimal Total Cost per Year:**
\[
\boxed{\$115,526}
\]
---
### **Summary Table**
| Order Quantity | Unit Cost | Total Annual Cost |
|:--------------:|:------------------:|:----------------:|
| 300 | \$10 | \$240,600 |
| 301 | \$9.99 | \$239,902 |
| **3464** | **\$(5 + small avg)** | **\$115,526** |
- **Order 3,464 units each time and pay \$5 for units above the first 300 each order.**
- **Order cost, holding cost, and purchase cost sum to \$115,526 per year.**
If you have follow-up questions or need a breakdown by cost component or cycle, let me know!
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