Make an order of magnitude estimate for the Reynolds number Re of a blood cell moving
through the circulatory system. You can assume the cell has a typical size. (Tip: you will
need to estimate the average speed of a blood cell in the bloodstream. It takes about a
minute for blood to circulate through the human body: what order of magnitude distance
does the blood travel in that time? Also, the density of water is 10% kg/m' and the
viscosity of water is 10-* Pa - 8.
Question:
Make an order of magnitude estimate for the Reynolds number Re of a blood cell moving
through the circulatory system. You can assume the cell has a typical size. (Tip: you will
need to estimate the average speed of a blood cell in the bloodstream. It takes about a
minute for blood to circulate through the human body: what order of magnitude distance
does the blood travel in that time? Also, the density of water is 10% kg/m' and the
viscosity of water is 10-* Pa - 8.
This is AI generated Response.
Asked by: Sahab Sharan
Created at: 2025-10-22 18:18:06
Final Answer:
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# Order of Magnitude Estimate of Reynolds Number for a Blood Cell
## Assumptions and Data
- **Typical size of a blood cell (diameter, \(d\))**:
\(d \approx 10\, \mu m = 10^{-5}\, m\)
- **Average circulation time for blood to pass through the body**:
\(t \approx 1\, \text{minute} = 60\, s\)
- **Distance traveled by blood in that time**:
\(L \approx \text{average blood velocity} \times t\)
- **Density of water**:
\(\rho \approx 10\ \times 100\, kg/m^3 =\, kg/m^3\)
- **Viscosity water**:
\(\eta \approx103}\, Pa \cdot s\)
## Step1: Estimate Blood Velocity
- Blood circulates roughly throughout the body, which is about \( \sim 1\, m \) in length.
- **Estimate of blood velocity \(v\)**:
\[
v \approx \frac{\text{distance traveled}}{\text{time}} \approx \frac{1\, m}{60\, s} \approx .0167\, m/s
\]
*(Order of magnitude: \(10^{-2}\, m/s\))*
## Step 2: Calculate Reynolds Number
\[
Re = \frac{\rho v d}{\eta}
\]
Plugging in the estimated values:
\[
Re \approx \frac{(100\, kg/m^3) \times (1.7 \times 10^{-2}\, m/s) \times (10^{-5}\, m)}{10^{-3}\, Pa \cdot s}
\]
\[
Re \approx \frac{(100) \times (1.7 \times 10^{-2}) \times (10^{-5})}{10^{-3}}
\]
\[
Re \approx \frac{(100) \times (1.7 \times 10^{-7})}{10^{-3}} = \frac{1.7 \times 10^{-5}}{10^{-3}} = 1.7 \times 10^{-2}
\]
## **Final Estimate**
\[
\boxed{
Re \sim 10^{-2}
}
\]
This indicates **laminar flow** around blood cells, consistent with physiological conditions.
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