In class, we computed the degeneracy pressure for a white dwarf with ρ = 1.4 × 106 g cm−3 . Assume that the white dwarf is pure carbon-12. (a) What is the velocity of the electrons implied by the Heisenberg Uncertainty Principle (just use the relation for momentum to velocity you learned in your mechanics class). Is the justification 1 of using the non-relativistic expression valid here? (b) What is the spacing between electrons in this white dwarf? give answer in 3 step with explanation at the end of each step and final answer at the end
Question:
In class, we computed the degeneracy pressure for a white dwarf with ρ = 1.4 × 106 g cm−3 . Assume that the white dwarf is pure carbon-12. (a) What is the velocity of the electrons implied by the Heisenberg Uncertainty Principle (just use the relation for momentum to velocity you learned in your mechanics class). Is the justification 1 of using the non-relativistic expression valid here? (b) What is the spacing between electrons in this white dwarf? give answer in 3 step with explanation at the end of each step and final answer at the end
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Asked by: amu
Created at: 2025-07-27 04:14:04
Final Answer:
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Sure! Let's solve each part step by step.
---
### **Step 1: Find the Number Density of Electrons**
**Given:**
- Density, \(\rho = 1.4 \times 10^6 \, \text{g/cm}^3\)
- The white dwarf is **pure carbon-12** (\({}^{12}\)C: 6 protons, 6 neutrons, 6 electrons per atom).
**Find:**
- Number density of **electrons**, \(n_e\).
**Calculation:**
1. **Molar mass of C-12:** \(12\, \text{g/mol}\)
2. **Number of atoms per cm³:**
\[
n_\text{C} = \frac{\rho}{12\,\text{g/mol}} \times N_A
\]
where \(N_A = 6.022 \times 10^{23} \, \text{mol}^{-1}\) (Avogadro's number).
\[
n_\text{C} = \frac{1.4 \times 10^6}{12} \times 6.022 \times 10^{23}
\]
\[
= 1.167 \times 10^5 \times 6.022 \times 10^{23}
\]
\[
= 7.03 \times 10^{28} \text{ atoms/cm}^3
\]
3. **Number of electrons per atom:** 6 (for C-12)
\[
n_e = n_C \times 6 = 7.03 \times 10^{28} \times 6 = 4.22 \times 10^{29} \text{ electrons/cm}^3
\]
**End of Step 1 Explanation:**
We found the number density of electrons in the white dwarf to be \(n_e \approx 4.2 \times 10^{29} \, \text{cm}^{-3}\).
---
### **Step 2: Electron Spacing and Heisenberg Uncertainty Principle**
#### **(b) Spacing between electrons**
The mean spacing between electrons, \(d\), is given by:
\[
d = n_e^{-1/3}
\]
\[
d = (4.2 \times 10^{29})^{-1/3} \text{ cm}
\]
Calculate the cube root:
- \(\log_{10}(4.2 \times 10^{29}) = \log_{10}(4.2) + 29 = 0.623 + 29 = 29.623\)
- \(\frac{29.623}{3} = 9.874\)
- \(10^{9.874} \approx 7.5 \times 10^{9}\)
- \(d = 1 / 7.5 \times 10^{-10} \, \text{cm} = 1.33 \times 10^{-10} \,\text{cm}\)
So,
\[
d \approx 1.3 \times 10^{-10} \text{ cm} = 1.3 \, \text{Å}
\]
**End of Step 2 Explanation:**
The mean spacing between electrons is about \(1.3 \times 10^{-10}\) cm, or \(1.3\) Ångström.
---
### **Step 3: Electron Velocity from Heisenberg Uncertainty Principle**
The **uncertainty in position** is on the order of the spacing, \(d\). By the **Heisenberg Uncertainty Principle**:
\[
\Delta x \, \Delta p \sim \hbar
\]
\[
\Delta p \sim \frac{\hbar}{d}
\]
- \(\hbar = 1.055 \times 10^{-27}\) erg·s
- \(d = 1.3 \times 10^{-10}\) cm
\[
\Delta p \sim \frac{1.055 \times 10^{-27}}{1.3 \times 10^{-10}}
= 8.12 \times 10^{-18} \text{ g cm/s}
\]
**Electron velocity:**
\[
p = mv \implies v = \frac{p}{m}
\]
Electron mass \(m_e = 9.11 \times 10^{-28}\) g
\[
v = \frac{8.12 \times 10^{-18}}{9.11 \times 10^{-28}} = 8.92 \times 10^{9} \, \text{cm/s}
\]
\[
v = 8.9 \times 10^9 \text{ cm/s}
\]
**Compare with the speed of light (\(c = 3.0 \times 10^{10}\) cm/s):**
\[
\frac{v}{c} = \frac{8.9 \times 10^9}{3.0 \times 10^{10}} \approx 0.30
\]
So, the electron velocity is about **30% the speed of light**.
#### **Justification: Is non-relativistic approximation valid?**
Generally, the non-relativistic approximation is valid if \(v \ll c\). Here, \(v \approx 0.3c\), so relativistic corrections start becoming important, and the non-relativistic formula is not strictly valid.
**End of Step 3 Explanation:**
The typical electron velocity is about \(0.3c\), so relativistic effects are becoming important, and the non-relativistic approximation is not strictly valid.
---
## **Final Answers**
### (a) **Velocity of electrons from Heisenberg Uncertainty Principle:**
\[
v \approx 8.9 \times 10^9 \, \text{cm/s} \approx 0.3c
\]
**Non-relativistic approximation is not strictly valid** since \(v\) is a significant fraction of \(c\).
### (b) **Spacing between electrons:**
\[
d \approx 1.3 \times 10^{-10} \, \text{cm}
\]
---
**Summary of steps:**
1. Found the number density of electrons (\(n_e \approx 4.2 \times 10^{29}\) cm\(^{-3}\)).
2. Calculated the mean spacing between electrons (\(d \approx 1.3 \times 10^{-10}\) cm).
3. Used the uncertainty principle to estimate electron velocity (\(v \approx 0.3c\)), and concluded non-relativistic formulas are not strictly valid here.
Question:
tell concept used in answering the question in paragraph form in very brief
This is AI generated Response.
Asked by: amu
Created at: 2025-07-27 04:15:05
Final Answer:
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To answer the question, I first calculated the electron number density in the white dwarf using its mass density and the atomic composition of carbon-12, leading to a high electron density. Next, I estimated the average spacing between electrons by taking the inverse cube root of this density, which gives the typical distance between neighboring electrons. Then, applying the Heisenberg Uncertainty Principle, I related the uncertainty in position (the electron spacing) to a momentum uncertainty, which I converted into an electron velocity. Comparing this velocity to the speed of light indicated that electrons move at a significant fraction of \(c\), making relativistic effects important and thus questioning the validity of a purely non-relativistic approach.
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