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Imagine you have a sound file that is 2 . 2 seconds long and sampled at 1 6 0 0 0 samples a second that you break into windows that are . 0 3 sec long. How many samples occur in each window? ( Round to the nearest whole number. )

Question:

Imagine you have a sound file that is 2 . 2 seconds long and sampled at 1 6 0 0 0 samples a second that you break into windows that are . 0 3 sec long. How many samples occur in each window? ( Round to the nearest whole number. )

This is AI generated Response.
Asked by: Nehal Anurag
Created at: 2025-09-10 11:00:57

Final Answer:

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# Calculating Number of Samples per Window Given: - **Sampling rate:** 16,000 samples/second - **Window length:** 0.03 seconds ## Calculation Number of samples in each window: \[ \text{Samples per window} = \text{Window length (sec)} \times \text{Sampling rate (samples/sec)} \] \[ = 0.03 \times 16,000 = 480 \] ## Answer **Each window contains 480 samples.**

Question:

step by step with explanation

This is AI generated Response.
Asked by: Nehal Anurag
Created at: 2025-09-10 11:02:06

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# Step-by-Step Calculation of Samples per Window To determine how many samples occur in each window of a sound file, we will follow these steps: ## Given Information - **Sampling Rate:** 16,000 samples per second - **Window Length:** 0.03 seconds ## Step 1: Understand the Formula The number of samples in a window can be calculated using the formula: \[ \text{Samples per window} = \text{Window length (sec)} \times \text{Sampling rate (samples/sec)} \] ## Step 2: Substitute the Values Now, we substitute the values into the formula: \[ \text{Samples per window} = 0.03 \, \text{sec} \times 16,000 \, \text{samples/sec} \] ## Step 3: Perform the Calculation Now we perform the multiplication: \[ 0.03 \times 16,000 = 480 \] ## Conclusion After rounding to the nearest whole number, we find: **Each window contains 480 samples.**

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