Give step-by-step solution with explanation and final answer:Graph y=sinxand y = [sin x] together. What are the domain and range of ‘sin x]?
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Graph the two functions. Choose the correct graph below.
OA. OB. oc. OD.
Y Q \Y Q y Q y
« & Q & .
-2x [23 -2n 2x [=] -2n pid [£1 -2x 23
Question:
Give step-by-step solution with explanation and final answer:Graph y=sinxand y = [sin x] together. What are the domain and range of ‘sin x]?
C=
Graph the two functions. Choose the correct graph below.
OA. OB. oc. OD.
Y Q \Y Q y Q y
« & Q & .
-2x [23 -2n 2x [=] -2n pid [£1 -2x 23
This is AI generated Response.
Asked by: sssssz
Created at: 2025-05-28 20:22:47
Final Answer:
RenderedRaw Text
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Let's solve the problem step-by-step:
### **Step 1: Understanding the Functions**
1. **\( y = \sin x \) (blue curve)**
- This is the standard sine function.
- **Domain**: \( x \in (-\infty, \infty) \)
- **Range**: \( y \in [-1, 1] \)
2. **\( y = \lceil \sin x \rceil \) (red curve)**
- This is the **ceiling function** applied to the sine function.
- The ceiling function, \( \lceil y \rceil \), gives the smallest integer greater than or equal to \( y \).
- For \( \sin x \), which ranges from -1 to 1, \( \lceil \sin x \rceil \) can take the values \(-1, 0, 1\):
- When \( -1 \leq \sin x < 0 \), \( \lceil \sin x \rceil = 0 \)
- When \( \sin x = 0 \), \( \lceil \sin x \rceil = 0 \)
- When \( 0 < \sin x < 1 \), \( \lceil \sin x \rceil = 1 \)
- When \( \sin x = 1 \), \( \lceil \sin x \rceil = 1 \)
- When \( \sin x = -1 \), \( \lceil \sin x \rceil = -1 \)
---
### **Step 2: Domain and Range of \( \lceil \sin x \rceil \)**
- **Domain:** \( (-\infty, \infty) \) (same as \(\sin x\))
- **Range:** \( \{-1, 0, 1\} \)
---
### **Step 3: Identifying the Correct Graph**
- The blue curve should be a smooth sine wave.
- The red curve should be a step function that jumps between \(-1\), \(0\), and \(1\):
- At \( \sin x = -1 \): red at \(-1\)
- For \( -1 < \sin x < 0 \): red at \(0\)
- For \( 0 < \sin x < 1 \): red at \(1\)
- At \( \sin x = 0 \): red at \(0\)
- At \( \sin x = 1 \): red at \(1\)
#### **Analyzing the Choices:**
- **Graph A:** The red step function jumps between 0 and 1, but does *not* go down to -1.
- **Graph B:** The red step function jumps between -1, 0, and 1. This matches our expectation.
- **Graph C:** The red step function jumps between 1 and 0, but appears to be shifted.
- **Graph D:** The red step function jumps between 1 and 0, but appears to be shifted as well.
**Therefore, the correct answer is:**
---
### **Final Answer**
**Correct graph: B**
---
**Domain of \( \lceil \sin x \rceil \):** \( (-\infty, \infty) \)
**Range of \( \lceil \sin x \rceil \):** \( \{-1, 0, 1\} \)
Question:
i need each option explanation along with the final Answer
This is AI generated Response.
Asked by: sssssz
Created at: 2025-05-28 20:23:31
Final Answer:
RenderedRaw Text
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Let's analyze each option carefully, explaining how each graph corresponds to the functions, and then identify the correct one.
---
### **Step 1: Understanding the functions**
- **\( y = \sin x \)**
- Is a smooth, periodic wave oscillating between \(-1\) and \(1\).
- **Domain:** All real numbers, \( (-\infty, \infty) \)
- **Range:** \( [-1, 1] \)
- **\( y = \lceil \sin x \rceil \)**
- Is the ceiling of \( \sin x \).
- Since \( \sin x \in [-1, 1] \), the ceiling function will take values:
- \(-1\) when \( \sin x = -1 \),
- \(0\) when \( -1 < \sin x \leq 0 \),
- \(1\) when \( 0 < \sin x \leq 1 \),
- At the endpoints, the ceiling jumps accordingly.
- **Range of \( \lceil \sin x \rceil \):** \( \{-1, 0, 1\} \)
---
### **Step 2: Expected graph features**
- The graph of \( y = \sin x \) is a smooth wave.
- The graph of \( y = \lceil \sin x \rceil \) will be a step function:
- **At points where \( \sin x = -1 \):** \( y = -1 \),
- **When \( \sin x \) is between \(-1\) and \(0\):** \( y = 0 \),
- **When \( \sin x \) is between \(0\) and \(1\):** \( y = 1 \),
- **At \( \sin x = 0 \):** \( y = 0 \),
- **At \( \sin x = 1 \):** \( y=1 \).
The red step function should have constant segments at these three values, jumping at points where \( \sin x \) crosses the thresholds.
---
### **Step 3: Analyzing the options**
#### **Option A:**
- The red graph appears as a step that only takes values 0 and 1.
- It **does not** go down to \(-1\).
- **Incorrect** because \( \lceil \sin x \rceil \) should also be \(-1\) at points where \( \sin x = -1 \).
---
#### **Option B:**
- The red graph jumps between \(-1\), \(0\), and \(1\).
- The step levels match the expected values:
- At \( \sin x = -1 \), red at \(-1\).
- When \( -1 < \sin x < 0 \), red at 0.
- When \( 0 < \sin x < 1 \), red at 1.
- At \( \sin x=0 \), red at 0.
- At \( \sin x=1 \), red at 1.
- The red steps align with the sine wave crossings.
- **Correct**.
---
#### **Option C:**
- The red steps appear shifted and only switch between 0 and 1.
- It **misses** the \(-1\) level.
- **Incorrect**.
---
#### **Option D:**
- Similar to C, but the steps are positioned differently.
- Also missing the \(-1\) level.
- **Incorrect**.
---
### **Final conclusion:**
The only graph that correctly displays the ceiling of the sine function with steps at \(-1\), 0, and 1 is **Option B**.
---
### **Final answer:**
**The correct graph is:**
**Option B**
---
### **Summary of domain and range of \( y = \lceil \sin x \rceil \):**
- **Domain:** \( (-\infty, \infty) \) (all real numbers)
- **Range:** \( \{-1, 0, 1\} \)
---
**Thus, the correct choice is: B.**
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