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Question:
i need detailed calculations along with the final Answersa
220138 Br —
\ NL o i as TIS erie ars hari cot. The tows ant wisn actly vs wore \
Piste il Figure 1. Parts Moved Between Work Centers. SE \
3 Ee ES E—— 4 \
8 2s 2] ol 3 SE \
5 2 ° = EE) Le
0 0 Eh
CL oa Re GR o & 3
) Soe oe 4
[Fraues 2 Exinting Unyout SERIE Ce
oS Fe Be | Bo
0 ——a— -
= Fore exsing yo, ho cumatie To xian” ‘movamant cou «eet (ene youe pants a whole rumba Si
5 | Bess on hfs shun i 10 mat cn sho spc th cotransport evn
Be
Based cn 2 ows shown ho ati, on sd pec ht cones A and] brit 1 sch hey fave te send ors rr mo =
$e ain io rove th yout ota hl “movement ost can cd. Furcal ectons or A and ave bee fe. th rey ARERR at sos
botwoen them is Han
A iC EEEG J
3 ————————— ge
The cumulative distance based on tho ovoral movement of parts between work contr fo this Layout = fot (eter your response a a whole rumba). LL
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fx)
This is AI generated Response.
Asked by: Test User 100103
Created at: 2025-05-06 08:25:20
Final Answer:
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Let's break down the problem step by step with all calculations shown:
---
### **Given Data**
#### **Parts Moved Between Work Centers (Flow Matrix)**
| | A | B | C | D |
|-----|-----|-----|-----|-----|
| **A** | - | 325 | 600 | 50 |
| **B** | 420 | - | 200 | 0 |
| **C** | 0 | 0 | - | 750 |
| **D** | 0 | 0 | 0 | - |
#### **Existing Layout**
A ---30'--- B ---30'--- C ---30'--- D
---
## **a) Cumulative "Load x Distance" or "Movement Cost"**
For the existing layout, calculate the total movement cost:
- **Distance between adjacent centers = 30 feet**
- **Distance between centers separated by one center = 60 feet**
- **Distance between centers at the ends = 90 feet**
Let's create a distance matrix for the current layout:
| | A | B | C | D |
|-----|-----|-----|-----|-----|
| A | 0 | 30 | 60 | 90 |
| B | 30 | 0 | 30 | 60 |
| C | 60 | 30 | 0 | 30 |
| D | 90 | 60 | 30 | 0 |
Now, sum up all **Flow x Distance** for each pair (from the flow matrix):
#### **A to Others**
- A → B: 325 moves × 30 ft = 9,750
- A → C: 600 moves × 60 ft = 36,000
- A → D: 50 moves × 90 ft = 4,500
#### **B to Others**
- B → A: 420 moves × 30 ft = 12,600
- B → C: 200 moves × 30 ft = 6,000
- B → D: 0 moves × 60 ft = 0
#### **C to Others**
- C → A: 0 moves × 60 ft = 0
- C → B: 0 moves × 30 ft = 0
- C → D: 750 moves × 30 ft = 22,500
#### **D to Others**
- D → A: 0
- D → B: 0
- D → C: 0
Now, sum all these values:
- 9,750 (A→B)
- 36,000 (A→C)
- 4,500 (A→D)
- 12,600 (B→A)
- 6,000 (B→C)
- 0 (B→D)
- 0 (C→A)
- 0 (C→B)
- 22,500 (C→D)
- 0 (D→A, D→B, D→C)
**Total Movement Cost = 9,750 + 36,000 + 4,500 + 12,600 + 6,000 + 22,500 = 91,350**
**Answer (a):**
Cumulative "load x distance" or "movement cost" = **91,350**
---
## **Center Pair with Highest and Second Highest Moves**
### **Based on the flow matrix:**
- **C → D:** 750 moves (highest)
- **A → C:** 600 moves (second highest)
So, centers **C and D** should be next to each other (highest), and **A and B** should be next (second highest).
---
## **b) Improved Layout**
Given: **A and D locations are fixed.** Need to find optimal positions for B and C.
**Pairs with highest moves should be adjacent:**
- C and D (750 moves)
- A and B (420 moves from B to A + 325 moves from A to B = 745, but A to C is 600, which is still high)
But since C and D should be adjacent (highest), and A and B should be adjacent (second highest), test both possible placements of B and C between A and D.
### **Possible Layouts:**
1. **A - B - C - D**
2. **A - C - B - D**
Let's calculate the movement cost for both:
---
### **Layout 1: A - B - C - D**
Distances:
- A to B = 30
- A to C = 60
- A to D = 90
- B to C = 30
- B to D = 60
- C to D = 30
Let’s repeat the calculations:
#### **A to Others**
- A → B: 325 × 30 = 9,750
- A → C: 600 × 60 = 36,000
- A → D: 50 × 90 = 4,500
#### **B to Others**
- B → A: 420 × 30 = 12,600
- B → C: 200 × 30 = 6,000
- B → D: 0 × 60 = 0
#### **C to Others**
- C → A: 0 × 60 = 0
- C → B: 0 × 30 = 0
- C → D: 750 × 30 = 22,500
**Total = 9,750 + 36,000 + 4,500 + 12,600 + 6,000 + 22,500 = 91,350**
---
### **Layout 2: A - C - B - D**
Distances:
- A to C = 30
- A to B = 60
- A to D = 90
- C to B = 30
- C to D = 60
- B to D = 30
#### **A to Others**
- A → B: 325 × 60 = 19,500
- A → C: 600 × 30 = 18,000
- A → D: 50 × 90 = 4,500
#### **B to Others**
- B → A: 420 × 60 = 25,200
- B → C: 200 × 30 = 6,000
- B → D: 0 × 30 = 0
#### **C to Others**
- C → A: 0 × 30 = 0
- C → B: 0 × 30 = 0
- C → D: 750 × 60 = 45,000
**Total = 19,500 + 18,000 + 4,500 + 25,200 + 6,000 + 45,000 = 118,200**
---
### **Best Layout**
- **A - B - C - D**: 91,350
- **A - C - B - D**: 118,200
So, **A - B - C - D** gives the lowest cost.
### **Where should B and C be located?**
- The work center that should be between A and D is **B** (i.e., the layout is: A - B - C - D).
---
## **Final Answers**
### a) Existing layout cumulative "movement cost":
**91,350**
### b) Based on the flows:
- Centers that should be next to each other (**highest moves**): **C and D**
- Centers that should be next to each other (**second highest**): **A and B**
- The work center that should be between A and D: **B**
- Cumulative distance based on improved layout: **91,350** feet
---
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