Give step-by-step solution with explanation and final answer:Aparcle moves song a path gen by 7() (cos int, 1). Sketch th curve ig the nea € (ord on [28,58] (pom)
Question:
Give step-by-step solution with explanation and final answer:
Aparcle moves song a path gen by 7() (cos int, 1). Sketch th curve ig the
nea € (ord on [28,58] (pom)
This is AI generated Response.
Asked by: sssssz
Created at: 2025-05-28 21:34:50
Asked by: sssssz
Created at: 2025-05-28 21:34:50
Final Answer:
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Did you like this answer?
Let's break down the problem step by step:
---
### **Given**
A particle moves along a path given by:
\[
\vec{r}(t) = \langle 4\cos t,\, 4\sin t,\, 3t \rangle
\]
with \( t \in [0,4\pi] \) or \( t \in [-2\pi,2\pi] \).
We need to **sketch the curve**.
---
### **Step 1: Understanding the Path**
- The \(x\) and \(y\) components are:
\[
x(t) = 4\cos t,\quad y(t) = 4\sin t
\]
These describe a circle of **radius 4** in the \(xy\)-plane as \(t\) goes from \(0\) to \(2\pi\).
- The \(z\) component is:
\[
z(t) = 3t
\]
As \(t\) increases, \(z\) increases linearly.
**This is a helix:** The particle moves in a circle of radius 4, while moving upward (or downward) with \(z = 3t\).
---
### **Step 2: Parameter Interval**
- If \( t \in [0, 4\pi] \):
- \( x \) and \( y \) complete **two full circles** (since one circle for \(0\) to \(2\pi\)).
- \( z \) goes from \(0\) to \(3(4\pi) = 12\pi\).
- If \( t \in [-2\pi, 2\pi] \):
- Also covers two full circles, but \(z\) goes from \(-6\pi\) to \(6\pi\).
---
### **Step 3: Sketching the Curve**
#### **1. Projection onto the \(xy\)-plane:**
- The curve projects to a circle of radius 4.
#### **2. Helix in 3D:**
- As \(t\) increases, the point moves counterclockwise around the circle (since \(\cos t\), \(\sin t\)), but at the same time, \(z\) increases linearly, forming a **helix** that wraps around the cylinder \(x^2 + y^2 = 16\).
#### **3. Key Points:**
- At \(t = 0\): \((4, 0, 0)\)
- At \(t = \pi/2\): \((0, 4, 3\pi/2)\)
- At \(t = \pi\): \((-4, 0, 3\pi)\)
- At \(t = 3\pi/2\): \((0, -4, 9\pi/2)\)
- At \(t = 2\pi\): \((4, 0, 6\pi)\) — one full turn
- At \(t = 4\pi\): \((4, 0, 12\pi)\) — two full turns
---
### **Step 4: Final Answer (Description and Sketch)**
#### **Final Answer:**
The particle traces a helix of radius 4 centered on the \(z\)-axis, with a vertical spacing of \(3 \cdot 2\pi = 6\pi\) per turn. For \(t \in [0, 4\pi]\), the helix starts at \((4,0,0)\) and finishes at \((4,0,12\pi)\) after two full turns.
#### **Sketch (Description):**
1. Draw the \(z\)-axis vertically.
2. Draw a cylinder of radius 4 about the \(z\)-axis.
3. Mark the starting point at \((4,0,0)\).
4. Draw a spiral (helix) that wraps counterclockwise (when viewed from above), rising as \(z\) increases, making **two full turns** by \(z = 12\pi\).
5. The projection onto the \(xy\)-plane is a circle.
---
**In summary**:
The path is a helix around the cylinder \(x^2 + y^2 = 16\) with pitch \(6\pi\) (vertical distance per turn), making two turns as \(z\) goes from \(0\) to \(12\pi\).
---
#### **Optional: Parametric Plot Example (for visualization)**
If you want to plot this in, say, Python (matplotlib):
```python
import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
t = np.linspace(0, 4*np.pi, 500)
x = 4 * np.cos(t)
y = 4 * np.sin(t)
z = 3 * t
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.plot(x, y, z)
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_zlabel('z')
plt.show()
```
---
Let me know if you would like the sketch itself!
Question:
i need detailed calculations along with the final Answer
This is AI generated Response.
Asked by: sssssz
Created at: 2025-05-28 21:40:15
Asked by: sssssz
Created at: 2025-05-28 21:40:15
Final Answer:
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Raw Text
Did you like this answer?
Certainly! Let's go through a detailed step-by-step solution, including the calculations, to understand and sketch the given curve.
---
### **Given:**
The particle moves along the path parameterized by:
\[
\vec{r}(t) = \langle 4\cos t,\, 4\sin t,\, 3t \rangle
\]
with \( t \in [0, 4\pi] \).
---
### **Step 1: Understand the components of the motion**
- **\(x(t) = 4\cos t\)**
- **\(y(t) = 4\sin t\)**
- **\(z(t) = 3t\)**
---
### **Step 2: Describe the projection onto the \(xy\)-plane**
The \(x\) and \(y\) components define a circle:
\[
x^2 + y^2 = (4\cos t)^2 + (4\sin t)^2 = 16 \cos^2 t + 16 \sin^2 t = 16 (\cos^2 t + \sin^2 t) = 16
\]
**This is a circle of radius 4** centered at the origin in the \(xy\)-plane.
---
### **Step 3: Describe the \(z\)-component**
The height varies linearly:
\[
z(t) = 3t
\]
- When \(t=0\), \(z=0\).
- When \(t=4\pi\),
\[
z = 3 \times 4\pi = 12\pi
\]
which is approximately \(12 \times 3.1416 \approx 37.699\).
---
### **Step 4: Understanding the motion**
- As \(t\) increases from \(0\) to \(4\pi\), the particle completes **two full revolutions** around the circle (since one full revolution occurs over \(t\) from 0 to \(2\pi\)).
- The particle moves **upward** along the \(z\)-axis from 0 to \(12\pi \approx 37.7\).
- The path traces a **helix** wrapped around a cylinder of radius 4.
---
### **Step 5: Key points**
Let's find some specific points on the path:
| \(t\) | \(x(t)\) | \(y(t)\) | \(z(t)\) | Description |
|--------|-----------|-----------|--------|--------------|
| 0 | \(4 \cos 0=4\) | \(4 \sin 0=0\) | \(0\) | Starting point at \((4,0,0)\) |
| \(\pi/2\) | \(4 \cos \pi/2=0\) | \(4 \sin \pi/2=4\) | \(3 \times \pi/2 \approx 4.712\) | Quarter turn, top point at \((0,4,4.712)\) |
| \(\pi\) | \(-4\) | 0 | \(3 \pi \approx 9.425\) | Half turn, at \((-4,0,9.425)\) |
| \(3\pi/2\) | 0 | \(-4\) | \(3 \times 3\pi/2 \approx 14.137\) | Three-quarters turn, at \((0,-4,14.137)\) |
| \(2\pi\) | \(4\) | 0 | \(6 \pi \approx 18.85\) | Full turn, back to \((4,0,18.85)\) |
Similarly, for \(t=4\pi\):
\[
x=4 \cos 4\pi=4,\quad y=4 \sin 4\pi=0,\quad z=3 \times 4\pi=12\pi \approx 37.699
\]
which indicates the particle completes **two full revolutions** in the \(xy\)-plane, rising from \(z=0\) to \(z \approx 37.7\).
---
### **Step 6: Sketching the curve**
- **Projection onto the \(xy\)-plane:** circle of radius 4 centered at the origin.
- **Vertical motion:** linear increase in \(z\) from 0 to \(12\pi\).
- **Path shape:** a **helix** wrapping around the cylinder of radius 4, with **two turns**.
---
### **Final summary:**
- **The path is a helix** with:
- **Radius:** 4
- **Number of turns:** 2 (from \(t=0\) to \(t=4\pi\))
- **Vertical rise per turn:** \( \frac{12\pi}{2} = 6\pi \approx 18.85 \)
- **Equation of the curve:**
\[
x=4\cos t,\quad y=4\sin t,\quad z=3t,\quad t \in [0, 4\pi]
\]
---
### **Visual sketch instructions:**
1. Draw the \(xy\)-plane with a circle of radius 4.
2. Mark the starting point at \((4,0,0)\).
3. Sketch a spiral wrapping around the cylinder, ascending linearly, completing two full revolutions from \(z=0\) to approximately 37.7.
4. Indicate the height increases linearly with \(t\).
---
**This detailed step-by-step process should help you understand and visualize the curve!**
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