Give step-by-step solution with explanation and final answer: Determine Phase Relationships of Currents of a Parallel RC circuit
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Give step-by-step solution with explanation and final answer: Determine Phase Relationships of Currents of a Parallel RC circuit
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Asked by: Aman
Created at: 2025-11-13 00:18:23
Asked by: Aman
Created at: 2025-11-13 00:18:23
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# Phase Relationships of Currents in a Parallel RC Circuit
A parallel RC circuit consists of a resistor (R) and a capacitor (C) connected in parallel across an AC voltage source.
## 1. Circuit Description
- **Applied voltage:** \( v(t) = V_m \sin(\omega t) \)
- **Resistor current:** \( i_R \)
- **Capacitor current:** \( i_C \)
- **Total current:** \( i_{total} \)
## 2. Currents Through Each Branch
### Resistor Branch
- Voltage across resistor: \( v_R(t) = v(t) \)
- Ohm’s Law:
\[
i_R(t) = \frac{v(t)}{R} = \frac{V_m}{R} \sin(\omega t)
\]
- **Phase relationship:** The resistor current is **in phase** with the voltage.
### Capacitor Branch
- Voltage across capacitor: \( v_C(t) = v(t) \)
- Capacitor current:
\[
i_C(t) = C \frac{dv(t)}{dt} = C \frac{d}{dt}[V_m \sin(\omega t)] = V_m \omega C \cos(\omega t)
\]
or
\[
i_C(t) = V_m \omega C \sin\left(\omega t + 90^\circ\right)
\]
- **Phase relationship:** The current through the capacitor **leads** the voltage by \( 90^\circ \).
## 3. Total Current
- The total current is the sum of the resistor and capacitor currents:
\[
i_{total}(t) = i_R(t) + i_C(t)
\]
- This total current **leads** the voltage by an angle \( \theta \), where
\[
\tan\theta = \frac{I_C}{I_R} = \omega RC
\]
where
\( I_C = V_m \omega C \) and \( I_R = \frac{V_m}{R} \).
## 4. Phasor Diagram

*Alt: Phasor diagram showing voltage along the horizontal axis, resistor current in phase, and capacitor current leading by 90 degrees.*
- \( i_R \): Along the voltage phasor (in phase)
- \( i_C \): 90° ahead of voltage (vertical, upward)
- \( i_{total} \): Vector sum, leads voltage by angle \( \theta \) (between ° and 90°)
## 5. Summary Table
| Quantity | Phase Relation to Voltage |
|------------------|---------------------------------------|
| \( i_R \) | In phase (\( ^\circ \)) |
| \( i_C \) | Leads by \( 90^\circ \) |
| \( i_{total} \) | Leads by \( \theta = \tan^{-1}(\omega RC) \) |
## 6. **Final Answer**
- **Resistor current (\( i_R \))** is in phase with the voltage.
- **Capacitor current (\( i_C \))** leads the voltage by \( 90^\circ \).
- **Total current (\( i_{total} \))** leads the voltage by an angle \( \theta = \tan^{-1}(\omega RC) \), which is between ° and 90° depending on the values of \( R \), \( C \), and frequency (\( \omega \)).
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