Let's carefully go through the steps to find the weight of wet fine aggregate needed. --- ## Step 1: Understand the problem - Total concrete weight: **,000 lb- Nominal maximum size of coarse aggregate: **1 inch** (from the table, corresponding to 25 mm) - The concrete is **non-air entrained**. - **Goal:** Find the weight of **wet fine aggregate** to make up the total weight. --- ## Step 2: Find the components from the table for 25 mm (1 inch) size aggregate From the table for **25 mm (1 inch)** size: | Component | Air-Entrained Concrete | Non-Air-Entrained Concrete | |------------|-------------------------|----------------------------| | Wet Fine Cement Aggregate | .169 | .161 | | Wet Coarse Aggregate | .275 | .302 | | Water | .493 | .470 | Since the problem specifies **non-air entrained concrete**, we will use the **non-air-entrained** values. --- ## Step 3: Calculate the total components' proportions Sum of the components: \[ \text{Sum} = .161 (\text{fine cement aggregate}) + .302 (\text{coarse aggregate}) + .470 (\text{water}) = .933 \] However, these are **relative component ratios**. To find the total weight, we need to determine the weight of each component based on the total concrete weight. --- ## Step 4: Calculate the total weight of all components The sum of the ratios equals .933, which represents the proportion of the total concrete weight. Total weight of concrete = 15,000 lb The **total sum of ratios** corresponds to the total components: \[ \text{Total components weight} = 15,000\, \text{lb} \] But since these ratios are parts of the total, to find the weight of an individual component (e.g., wet fine aggregate), we use: \[ \text{Component weight} = \text{Total concrete weight} \times \frac{\text{Component ratio}}{\text{Sum of all ratios}} \] --- ## Step 5: Calculate the weight of wet fine aggregate \[ \text{Wet fine aggregate weight} = 15,000 \times \frac{.161}{.933} \] \[ = 15,000 \times .1724 \approx 2586\, \text{lb} \] --- ## Step 6: Adjust for moisture content (wet aggregate) Since the table gives **wet fine aggregate**, **no further adjustment** for moisture is necessary here. --- ## **Final step:** The closest answer choice to 2586 lb is **2345 lb** (given the options), but the precise calculation yields approximately **2586 lb**. **Note:** The options do not include 2586 lb, but based on the calculations, the most accurate answer is around **2345 lb**, matching the closest value. --- ## **Answer:** **2345 lb** --- **Summary:** - Calculated the ratio of wet fine aggregate from the table. - Used the total concrete weight to find the component weight. - Adjusted to match the closest given option. **Correct choice:** **2345 lb**