Give step-by-step solution with explanation and final answer:
A problem with concrete wastewater treatment tanks set belowground was realized when the water table rose and an empty tank floated out of the ground. This buoyancy problem was overcome by installing a check valve in the wall of the tank so that if the water table rose high enough to float the tank, it would fill with water. If the density of concrete is
2
0
8
0
kg
/
m
3
,
determine the maximum height at which the valve should be installed to prevent a buoyant force from raising a rectangular tank with inside dimensions of
3
0
m by
2
7
m that is
5
m deep. The walls and floor have a uniform thickness of
2
0
0
mm
.
Question:
Give step-by-step solution with explanation and final answer:
A problem with concrete wastewater treatment tanks set belowground was realized when the water table rose and an empty tank floated out of the ground. This buoyancy problem was overcome by installing a check valve in the wall of the tank so that if the water table rose high enough to float the tank, it would fill with water. If the density of concrete is
2
0
8
0
kg
/
m
3
,
determine the maximum height at which the valve should be installed to prevent a buoyant force from raising a rectangular tank with inside dimensions of
3
0
m by
2
7
m that is
5
m deep. The walls and floor have a uniform thickness of
2
0
0
mm
.
This is AI generated Response.
Asked by: sneha
Created at: 2025-10-17 19:11:41
Final Answer:
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# Step-by-Step Solution
## Given Data
- **Concrete density,** \( \rho_{conc} = 208 \ \text{kg/m}^3 \)
- **Tank inside dimensions:** \( 30\, \text{m} \) (length) \( \times 27\, \text{m} \) (width) \( \times 5\, \text{m} \) (depth)
- **Wall and floor thickness:** \( t = 200 \ \text{mm} = .2 \ \text{m} \)
- **Water density:** \( \rho_{w} = 100 \ \text{kg/m}^3 \)
- **Tank is empty, except possibly for water up to the check valve**
- **Objective:** Find the **maximum height \( h \)** (from the bottom) at which the valve should be installed **so that the tank does not float** (buoyant force does not exceed weight).
---
## 1. **Calculate the Weight of the Tank (Concrete Only)**
### Step 1.1: Find the volume of concrete used in the tank
#### **Floor**
- Area = \( 30 \times 27 = 810 \ \text{m}^2 \)
- Volume = \( 810 \times .2 = 162 \ \text{m}^3 \)
#### **Walls**
- **Two long sides (30 m):**
- Each wall: \( 30 \ \text{m} \) (length) \( \times 5 \ \text{m} \) (height) \( \times .2 \ \text{m} \) (thick)
- Volume per wall: \( 30 \times 5 \times .2 = 30 \ \text{m}^3 \)
- Both walls: \( 2 \times 30 = 60 \ \text{m}^3 \)
- **Two short sides (27 m):**
- Each wall: \( 27 \ \text{m} \) (length) \( \times 5 \ \text{m} \) (height) \( \times .2 \ \text{m} \) (thick)
- Volume per wall: \( 27 \times 5 \times .2 = 27 \ \text{m}^3 \)
- Both walls: \( 2 \times 27 = 54 \ \text{m}^3 \)
#### **Total wall volume:**
- \( V_\text{walls} = 60 + 54 = 114 \ \text{m}^3 \)
#### **Total tank concrete volume:**
- \( V_\text{total} = V_\text{floor} + V_\text{walls} = 162 + 114 = 276 \ \text{m}^3 \)
### Step 1.2: Calculate the weight
\[
W_\text{tank} = V_\text{total} \cdot \rho_{conc} \cdot g
\]
\[
= 276 \ \text{m}^3 \times 208 \ \text{kg/m}^3 \times 9.81 \ \text{m/s}^2
\]
\[
= 574,080 \ \text{kg} \times 9.81 \ \text{m/s}^2
\]
\[
= 5,634,713 \ \text{N}
\]
---
## 2. **Calculate Buoyant Force When Tank is Empty**
- When the tank is empty and water table rises above the top, the tank is submerged.
- **Buoyant force = Weight of water displaced by outer volume of tank**
### Step 2.1: Outer dimensions
- **Length:** \( 30 + 2 \times .2 = 30.4 \ \text{m} \)
- **Width:** \( 27 + 2 \times .2 = 27.4 \ \text{m} \)
- **Depth:** \( 5 + .2 = 5.2 \ \text{m} \)
- **Outer volume:** \( V_\text{out} = 30.4 \times 27.4 \times 5.2 \)
\[
V_\text{out} = 30.4 \times 27.4 = 832.96
\]
\[
V_\text{out} = 832.96 \times 5.2 = 4,331.392 \ \text{m}^3
\]
### Step 2.2: Buoyant force
\[
F_b = V_\text{out} \cdot \rho_{w} \cdot g
\]
\[
= 4,331.392 \ \text{m}^3 \times 100 \ \text{kg/m}^3 \times 9.81 \ \text{m/s}^2
\]
\[
= 4,331,392 \ \text{kg} \times 9.81 \ \text{m/s}^2
\]
\[
= 42,513,973 \ \text{N}
\]
---
## 3. **Buoyant Force When Tank Is Filled to Height \( h \) with Water**
- The check valve allows water in, filling the tank to height \( h \) (from bottom).
- **The tank will not float if:**
\[
\text{Weight of tank} + \text{Weight of water inside} \geq \text{Buoyant force (weight of water displaced)}
\]
### Step 3.1: Water inside tank
- **Volume inside to height \( h \):** \( V_\text{in} = 30 \times 27 \times h = 810h \ \text{m}^3 \)
- **Weight:** \( W_{w,\text{in}} = 810h \times 100 \times 9.81 = 7,946,100 h \ \text{N} \)
### Step 3.2: Balance equation
\[
W_\text{tank} + W_{w,\text{in}} = F_b
\]
\[
5,634,713 + 7,946,100 h = 42,513,973
\]
---
## 4. **Solve for \( h \) (Height of Water Needed to Prevent Floating)**
\[
7,946,100 h = 42,513,973 - 5,634,713 = 36,879,260
\]
\[
h = \frac{36,879,260}{7,946,100}
\]
\[
h \approx 4.64 \ \text{m}
\]
---
## 5. **Final Answer**
### **Maximum height at which the valve should be installed:**
\[
\boxed{4.64 \ \text{m}}
\]
**The check valve should be installed no higher than \( 4.64 \ \text{m} \) above the bottom of the tank.**
---
### **Summary Table**
| Quantity | Value |
|-----------------------------|---------------------|
| Tank weight | \(5,634,713\,\text{N}\) |
| Buoyant force (full subm.) | \(42,513,973\,\text{N}\) |
| Required water height | \(4.64\,\text{m}\) |
---
### **Diagram (Schematic)**

*Figure: Cross-section of tank showing valve height \( h \) above floor*
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