Give step-by-step solution with explanation and final answer:
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Design a mix proportioning for a concrete of M
4
0
grade by IS Code
(
1
0
2
6
2
:
2
0
0
9
)
as per following data: Type of Cement
=
OPC
4
3
of specific gravity of
3
.
1
5
Slump
=
1
5
0
mm Type of coarse aggregate
=
crushed angular aggregate
2
0
mm
(
specific gravity of
2
.
7
4
)
Type of fine aggregate
=
zone
1
–
sand with specific gravity of
2
.
7
4
.
Exposure
=
Severe
(
for RCC
)
Method of concrete placing
=
Pumping Degree of supervision
=
Good Chemical Admixture
=
Super
-
plasticizer
Question:
Give step-by-step solution with explanation and final answer:
VIPSearch
Google
Advanced AI Help
Design a mix proportioning for a concrete of M
4
0
grade by IS Code
(
1
0
2
6
2
:
2
0
0
9
)
as per following data: Type of Cement
=
OPC
4
3
of specific gravity of
3
.
1
5
Slump
=
1
5
0
mm Type of coarse aggregate
=
crushed angular aggregate
2
0
mm
(
specific gravity of
2
.
7
4
)
Type of fine aggregate
=
zone
1
–
sand with specific gravity of
2
.
7
4
.
Exposure
=
Severe
(
for RCC
)
Method of concrete placing
=
Pumping Degree of supervision
=
Good Chemical Admixture
=
Super
-
plasticizer
This is AI generated Response.
Asked by: naveen
Created at: 2025-10-10 07:51:36
Final Answer:
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# Step-by-Step Solution: Concrete Mix Design for M40 (IS 10262:2009)
## Given Data
- **Grade of Concrete:** M40 (Characteristic strength = 40 MPa)
- **Cement Type:** OPC 43, Specific gravity = 3.15
- **Slump:** 150 mm (for pumping)
- **Coarse Aggregate:** Crushed angular, 20 mm nominal max size, Specific gravity = 2.74
- **Fine Aggregate:** Zone I sand, Specific gravity = 2.74
- **Exposure:** Severe (for RCC)
- **Method of Placing:** Pumping
- **Degree of Supervision:** Good
- **Chemical Admixture:** Super-plasticizer
---
## 1. **Target Mean Strength**
According to IS 10262:2009, Target Mean Strength:
\[
\text{Target Mean Strength (f_{ck,target})} = f_{ck} + 1.65 \times S
\]
- \( f_{ck} \) = 40 MPa
- Standard deviation \( S \) (for M40, Table 1 of IS 10262) = 5. MPa
\[
f_{ck,target} = 40 + 1.65 \times 5 = 48.25\ \text{MPa}
\]
---
## 2. **Selection of Water-Cement Ratio**
- Table 5 of IS 456: Max w/c for severe exposure (RCC) = **.45**
- For high strength and super-plasticizer, assume **w/c = .38** (lower values typical for M40, adjust as per trial).
---
## 3. **Selection of Water Content**
- Table 2 IS 10262: For 20 mm aggregate, water content = **186 kg/m³** (for 25-50 mm slump)
- For 150 mm slump (pumping), **increase by ~3% per 25 mm above 50 mm**:
- Extra slump required = \( 150-50 = 100 \) mm
- Increment steps = \( 100/25 = 4 \)
- Increase = \( 4 \times 3\% = 12\% \)
- Adjusted water = \( 186 \times 1.12 = 208.3 \) kg/m³
- **With super-plasticizer, reduce water by up to 20%**:
- \( 208.3 \times .8 = 166.6 \) kg/m³
- **Adopted water content: 167 kg/m³**
---
## 4. **Cement Content**
\[
\text{Cement Content} = \frac{\text{Water}}{w/c} = \frac{167}{.38} = 439.5\ \text{kg/m}^3
\]
- IS 456 (Table 5): Min cement for severe exposure = **320 kg/m³ (max 450 kg/m³)**
- **Adopted cement content: 440 kg/m³** (within limit)
---
## 5. **Proportion of Aggregates**
### Volume of Concrete
- Total volume = 1 m³
- Volume of cement = \( \frac{440}{3.15 \times 100} = .140 \) m³
- Volume of water = \( \frac{167}{1 \times 100} = .167 \) m³
- Assume super-plasticizer dosage = 1% by mass of cement:
- \( .01 \times 440 = 4.4 \) kg
- Specific gravity (assume) = 1.20
- Volume = \( \frac{4.4}{1.2 \times 100} = .0037 \) m³
- Volume of all admixtures = .0037 m³
\[
\text{Volume of aggregates} = 1 - (.140 + .167 + .0037) = .689\ \text{m}^3
\]
---
### Aggregate Proportion (Table 3 IS 10262:2009)
- For 20 mm size, zone I sand, volume of coarse aggregate per unit volume = **.62**
- For pumping, **reduce coarse aggregate by 10%**:
- \( .62 \times .9 = .558 \)
- Volume of fine aggregate = \( 1 - .558 = .442 \)
---
### Mass of Aggregates
#### Coarse Aggregate
\[
\text{Mass} = \text{Volume} \times \text{Volume of aggregates} \times \text{Specific Gravity} \times 100
\]
\[
= .558 \times .689 \times 2.74 \times 100 = 1052\ \text{kg/m}^3
\]
#### Fine Aggregate
\[
= .442 \times .689 \times 2.74 \times 100 = 834\ \text{kg/m}^3
\]
---
## 6. **Summary of Mix Proportion (Per m³)**
| Material | Quantity (kg/m³) |
|-------------------|-----------------|
| Cement (OPC 43) | 440 |
| Water | 167 |
| Fine Aggregate | 834 |
| Coarse Aggregate | 1052 |
| Super-plasticizer | 4.4 |
### **Ratio (by mass):**
\[
\text{Cement} : \text{Fine Agg.} : \text{Coarse Agg.} = 440 : 834 : 1052 = 1 : 1.90 : 2.39
\]
## 7. **Final Mix Proportion**
\[
\boxed{
\text{Cement} : \text{Fine Agg.} : \text{Coarse Agg.} :: 1 : 1.90 : 2.39\ \text{by mass},\ w/c = .38,\ \text{Superplasticizer}: 1\% \ \text{of cement}
}
\]
---
## 8. **Notes**
- **Adjustments** may be needed based on trial mixes and actual site conditions.
- All aggregates assumed in SSD condition; if not, adjust for moisture content.
- Always check workability and strength with trial batches.
---
## 9. **References**
- IS 10262:2009 _Concrete Mix Proportioning – Guidelines_
- IS 456:200 _Plain and Reinforced Concrete – Code of Practice_
---
**Example Calculation Table:**
| Material | Quantity (kg/m³) | Specific Gravity | Volume (m³) |
|-------------------------|------------------|------------------|-------------|
| Cement (OPC 43) | 440 | 3.15 | .140 |
| Water | 167 | 1.00 | .167 |
| Fine Aggregate (Zone I) | 834 | 2.74 | .304 |
| Coarse Aggregate | 1052 | 2.74 | .384 |
| Super-plasticizer | 4.4 | 1.20 | .0037 |
---
**Final Answer:**
\[
\boxed{
\begin{array}{l}
\text{Mix Proportion by mass:} \\
\text{Cement : Fine Aggregate : Coarse Aggregate = 1 : 1.90 : 2.39,} \\
\text{Water-cement ratio} = .38, \\
\text{Water content} = 167\ \text{kg/m}^3, \\
\text{Cement content} = 440\ \text{kg/m}^3, \\
\text{Super-plasticizer} = 1\% \text{ of cement by mass}
\end{array}
}
\]
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