# Step-by-Step Solution ## 1. Wall Volume **Wall Dimensions** - Length(L\ = 5 m - Height (\(H\)) = 3 m - Thickness (\(T\)) = .2 m **Wall Volume (\(V_{wall}\)):** \[ V_{wall} = L \times H \times T = 5 \times 3 \times .2 = 3~\text{m}^3 \] --- ## 2. Brick Volume (with Mortar) **Brick Size (without mortar):** - Length = 190 mm = .19 m - Width = 90 mm = .09 m - Height = 90 mm = .09 m **Mortar Joint:** 10 mm = .01 m (applies to each face) **Brick Size (with mortar):** - Length = \(.19 + .01 = .20\) m - Width = \(.09 + .01 = .10\) m - Height = \(.09 + .01 = .10\) m **Volume of 1 Brick (with mortar):** \[ V_{brick} = .20 \times .10 \times .10 = .002~\text{m}^3 \] --- ## 3. Number of Bricks \[ \text{Number of bricks} = \frac{V_{wall}}{V_{brick}} = \frac{3}{.002} = 150 \] --- ## 4. Final Answer **The number of standard bricks required:** \[ \boxed{150} \] --- ## Summary Table | Item | Value | |----------------|--------------------------------| | Wall volume | 3 m³ | | Brick (with mortar) volume | .002 m³ | | Number of bricks | 150 | --- ## Notes - Calculation assumes all mortar joints are 10 mm thick and completely fill the space between bricks. - Wastage and breakage are not included in this calculation. --- **Image Example:** *Illustration of brick wall dimensions and a standard brick with mortar joint (not included here for brevity).*