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Give step-by-step solution with explanation and final answer: Recall that profit equals revenue minus cost. For the revenue and cost functions shown, answer parts ( a ) through ( e ) below. R ( x ) = 4 2 0 x - 2 x 2 and C ( x ) = 1 0 0 x 9 8 0 0 , with 0 ≤ x ≤ 1 5 0 a ) Find the break - even point. The break - even point ( s ) is ( are ) x = ◻ . Type an integer or decimal rounded to one decimal place as needed. Use a comma to separate answers as needed. )33 gee Ha §17 |e 13 8 i : i : i I oll i l wr . i

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Give step-by-step solution with explanation and final answer: Recall that profit equals revenue minus cost. For the revenue and cost functions shown, answer parts ( a ) through ( e ) below. R ( x ) = 4 2 0 x - 2 x 2 and C ( x ) = 1 0 0 x 9 8 0 0 , with 0 ≤ x ≤ 1 5 0 a ) Find the break - even point. The break - even point ( s ) is ( are ) x = ◻ . Type an integer or decimal rounded to one decimal place as needed. Use a comma to separate answers as needed. )Uploaded Image33 gee Ha §17 |e 13 8 i : i : i I oll i l wr . i

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Asked by: anil
Created at: 2025-09-29 08:41:08

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Let's solve the break-even point step by step. ### **Step 1: Set Revenue Equal to Cost** The break-even point occurs when revenue equals cost: \[ R(x) = C(x) \] Given: \[ R(x) = 420x 2x^2 \] \[ C(x) = 100x + 980 \] Set them equal to each other: \[ 420x - 2x^2 = 100x + 980 \] --- ### **Step 2: Rearrange the Equation** Bring all terms to one side: \[ 420x - 2x^2 - 100x - 980 = \] \[ (420x - 100x) - 2x^2 - 980 = \] \[ 320x - 2x^2 - 980 = \] Multiply both sides by -1 to make the quadratic term positive: \[ 2x^2 - 320x + 980 = \] --- ### **Step 3: Solve the Quadratic Equation** This is a quadratic equation in the form \( ax^2 + bx + c = \): - \( a = 2 \) - \( b = -320 \) - \( c = 980 \) Use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Plug in the values: \[ x = \frac{-(-320) \pm \sqrt{(-320)^2 - 4 \cdot 2 \cdot 980}}{2 \cdot 2} \] \[ x = \frac{320 \pm \sqrt{102400 - 78400}}{4} \] \[ x = \frac{320 \pm \sqrt{24000}}{4} \] --- ### **Step 4: Simplify** \[ \sqrt{24000} \approx 154.9 \] So, \[ x_1 = \frac{320 + 154.9}{4} = \frac{474.9}{4} = 118.7 \] \[ x_2 = \frac{320 - 154.9}{4} = \frac{165.1}{4} = 41.3 \] --- ### **Step 5: State the Break-Even Points** **Final Answer:** \[ \boxed{41.3, 118.7} \] - **These are the break-even points, rounded to one decimal place.** - Both values are within the given range \( \leq x \leq 150\).

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