Give step-by-step solution with explanation and final answer:7. (mat Te contr fp 1c: Ka 2710 a Ya ~The ath ae emp 16 pon 17 5548 ad 345m Thm and dace sop 1 E34 ad 7S Coc i nt nd sae om Sono pith ond om pot 810 sm compre hem 8 kl ww | Zrii | * if Ga ee
Question:
Give step-by-step solution with explanation and final answer:
7. (mat Te contr fp 1c: Ka 2710 a Ya ~The ath
ae emp 16 pon 17 5548 ad 345m Thm and dace
sop 1 E34 ad 7S Coc i nt nd sae om
Sono pith ond om pot 810 sm compre hem
8 kl
ww |
Zrii |
* if
Ga
ee
This is AI generated Response.
Asked by: VARRI NAVEEN
Created at: 2025-09-27 07:39:16
Asked by: VARRI NAVEEN
Created at: 2025-09-27 07:39:16
Final Answer:
Rendered
Raw Text
Did you like this answer?
Let's break down the problem step by step.
---
## **Given Data**
- **Coordinates of point 16:**
\( X_{16} = 2227.819 \) m
\( Y_{16} = 3335.821 \) m
- **From 16 to 17:**
- **Azimuth:** \( 166^\circ 55' 48'' \)
- **Distance:** \( 769.745 \) m
- **From 16 to 18:**
- **Azimuth:** \( 226^\circ 23' 24'' \)
- **Distance:** \( 598.532 \) m
---
## **Step 1: Compute Coordinates for Points 17 and 18**
### **Formulas**
\[
\Delta X = D \cdot \sin(\theta)
\]
\[
\Delta Y = D \cdot \cos(\theta)
\]
Where \( \theta \) is the azimuth (in decimal degrees, converted to radians).
---
### **A. Coordinates for Point 17**
#### **Convert Azimuth to Decimal Degrees**
\[
166^\circ 55' 48'' = 166 + \frac{55}{60} + \frac{48}{360} = 166.930^\circ
\]
#### **Convert to Radians**
\[
\theta_{16 \to 17} = 166.930^\circ \times \frac{\pi}{180} = 2.9143 \text{ radians}
\]
#### **Compute ΔX and ΔY**
\[
\Delta X_{16 \to 17} = 769.745 \times \sin(166.930^\circ)
\]
\[
\Delta Y_{16 \to 17} = 769.745 \times \cos(166.930^\circ)
\]
\[
\sin(166.930^\circ) \approx .22744
\]
\[
\cos(166.930^\circ) \approx -.97379
\]
\[
\Delta X_{16 \to 17} = 769.745 \times .22744 = 175.006 \text{ m}
\]
\[
\Delta Y_{16 \to 17} = 769.745 \times (-.97379) = -749.799 \text{ m}
\]
\[
X_{17} = X_{16} + \Delta X_{16 \to 17} = 2227.819 + 175.006 = 2402.825 \text{ m}
\]
\[
Y_{17} = Y_{16} + \Delta Y_{16 \to 17} = 3335.821 - 749.799 = 2586.022 \text{ m}
\]
---
### **B. Coordinates for Point 18**
\[
226^\circ 23' 24'' = 226 + \frac{23}{60} + \frac{24}{360} = 226.39^\circ
\]
\[
\theta_{16 \to 18} = 226.39^\circ \times \frac{\pi}{180} = 3.952 \text{ radians}
\]
\[
\sin(226.39^\circ) \approx -.6286
\]
\[
\cos(226.39^\circ) \approx -.7777
\]
\[
\Delta X_{16 \to 18} = 598.532 \times (-.6286) = -376.323 \text{ m}
\]
\[
\Delta Y_{16 \to 18} = 598.532 \times (-.7777) = -465.251 \text{ m}
\]
\[
X_{18} = 2227.819 + (-376.323) = 1851.496 \text{ m}
\]
\[
Y_{18} = 3335.821 + (-465.251) = 287.570 \text{ m}
\]
---
## **Step 2: Calculate Azimuth and Distance**
### **From 17 to 18**
\[
\Delta X = X_{18} - X_{17} = 1851.496 - 2402.825 = -551.329 \text{ m}
\]
\[
\Delta Y = Y_{18} - Y_{17} = 287.570 - 2586.022 = 284.548 \text{ m}
\]
#### **Distance**
\[
D_{17 \to 18} = \sqrt{(-551.329)^2 + (284.548)^2}
\]
\[
D_{17 \to 18} = \sqrt{304963.3 + 81069.6} = \sqrt{386032.9} \approx 621.3 \text{ m}
\]
#### **Azimuth**
\[
\theta = \arctan\left(\frac{\Delta X}{\Delta Y}\right)
\]
\[
\arctan\left(\frac{-551.329}{284.548}\right) \approx -62.93^\circ
\]
But this is in the 2nd quadrant (since ΔX negative, ΔY positive):
\[
\text{Azimuth} = 180^\circ + (-62.93^\circ) = 117.07^\circ
\]
But azimuths are measured from North (clockwise):
\[
\theta = \arctan2(\Delta X, \Delta Y)
\]
\[
\theta = \arctan2(-551.329, 284.548) = -62.93^\circ
\]
Since ΔX negative, ΔY positive, the angle is in the 2nd quadrant (between 90° and 180°):
\[
\text{Azimuth} = 360^\circ + (-62.93^\circ) = 297.07^\circ
\]
But let's check:
- ΔX negative, ΔY positive: 2nd quadrant azimuth = 180 - |θ|
- θ = 62.93°, so Azimuth = 180 - 62.93 = **117.07°**
### **From 18 to 17**
Just reverse ΔX and ΔY:
\[
\Delta X = X_{17} - X_{18} = 2402.825 - 1851.496 = 551.329 \text{ m}
\]
\[
\Delta Y = Y_{17} - Y_{18} = 2586.022 - 287.570 = -284.548 \text{ m}
\]
\[
\theta = \arctan2(551.329, -284.548)
\]
This is positive X, negative Y: 4th quadrant.
\[
\arctan2(551.329, -284.548) = 117.07^\circ
\]
So, Azimuth = 360 - 62.93 = **297.07°**
---
## **Step 3: Compare**
- **From 17 to 18:** Distance ≈ 621.3 m, Azimuth ≈ 117.07°
- **From 18 to 17:** Distance ≈ 621.3 m, Azimuth ≈ 297.07°
These azimuths differ by 180°, as expected.
---
## **Final Answers**
### **Coordinates**
- \( (X_{17}, Y_{17}) = (2402.825, 2586.022) \)
- \( (X_{18}, Y_{18}) = (1851.496, 287.570) \)
### **From 17 to 18**
- **Distance:** \( 621.3 \) m
- **Azimuth:** \( 117.07^\circ \)
### **From 18 to 17**
- **Distance:** \( 621.3 \) m
- **Azimuth:** \( 297.07^\circ \)
### **Comparison**
- The distances are the same.
- The azimuths differ by 180°.
📢 Instructions:
- Ask anything relatd to above question only.
- For new Question goto :
VIPSolutions