Give step-by-step solution with explanation and final answer:Problem 5 : : Obtain the Fourier representation for the following signals a) x(n) ={.-10,203, B 0,1,0310203,..} _ 3 b) ym ={..321232123212,..}
Question:
Give step-by-step solution with explanation and final answer:
Problem 5 : : Obtain the Fourier representation for the following signals
a) x(n) ={.-10,203, B 0,1,0310203,..}
_ 3
b) ym ={..321232123212,..}
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Asked by: Abhishek
Created at: 2025-09-21 14:29:33
Asked by: Abhishek
Created at: 2025-09-21 14:29:33
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Let's solve each part step by step.
---
## **a) \( x(n) = \{ ..., 1, 0, 2, 0, 3, \underline{1}, 0, 1, 0, 3, 1, 0, 2, 0, 3, ... \} \)**
### **Step 1: Identify the Period \( N \)**
Let's find the period by checking the repeating pattern:
- Sequence: \( 1, 0, 2, 0, 3 \)
- Sequence after next 5: \( 1, 0, 2, 0, 3 \)
So, **period \( N = 5 \)**.
### **Step 2: Write One Period**
Let's write one period starting from \( n = 0 \):
- \( x(0) = 1 \)
- \( x(1) = 0 \)
- \( x(2) = 2 \)
- \( x(3) = 0 \)
- \( x(4) = 3 \)
### **Step 3: Discrete-Time Fourier Series (DTFS) Coefficients**
For a periodic sequence with period \( N \):
\[
X(k) = \frac{1}{N} \sum_{n=0}^{N-1} x(n) e^{-j \frac{2\pi}{N} k n}
\]
where \( k = 0, 1, ..., N-1 \).
#### **Compute \( X(k) \):**
\[
X(k) = \frac{1}{5} \left[ x(0) + x(1)e^{-j\frac{2\pi}{5}k} + x(2)e^{-j\frac{4\pi}{5}k} + x(3)e^{-j\frac{6\pi}{5}k} + x(4)e^{-j\frac{8\pi}{5}k} \right]
\]
Substitute values:
- \( x(0) = 1 \)
- \( x(1) = 0 \)
- \( x(2) = 2 \)
- \( x(3) = 0 \)
- \( x(4) = 3 \)
\[
X(k) = \frac{1}{5} \left[ 1 + 0 + 2e^{-j\frac{4\pi}{5}k} + 0 + 3e^{-j\frac{8\pi}{5}k} \right]
\]
\[
X(k) = \frac{1}{5} \left[ 1 + 2e^{-j\frac{4\pi}{5}k} + 3e^{-j\frac{8\pi}{5}k} \right]
\]
---
## **b) \( y(n) = \{ ..., 3, 2, 1, 2, \underline{3}, 2, 1, 2, 3, 2, 1, 2, ... \} \)**
### **Step 1: Identify the Period \( N \)**
Let's check the repeating pattern:
- \( 3, 2, 1, 2 \)
- Next: \( 3, 2, 1, 2 \)
- So, **period \( N = 4 \)**
### **Step 2: Write One Period**
Starting from \( n = 0 \):
- \( y(0) = 3 \)
- \( y(1) = 2 \)
- \( y(2) = 1 \)
- \( y(3) = 2 \)
### **Step 3: DTFS Coefficients**
\[
Y(k) = \frac{1}{4} \sum_{n=0}^{3} y(n) e^{-j \frac{2\pi}{4} k n}
\]
Substitute values:
\[
Y(k) = \frac{1}{4} \left[ 3 + 2e^{-j\frac{2\pi}{4}k} + 1e^{-j\frac{4\pi}{4}k} + 2e^{-j\frac{6\pi}{4}k} \right]
\]
\[
Y(k) = \frac{1}{4} \left[ 3 + 2e^{-j\frac{\pi}{2}k} + e^{-j\pi k} + 2e^{-j\frac{3\pi}{2}k} \right]
\]
---
## **Final Answers**
### **a)**
\[
\boxed{
X(k) = \frac{1}{5} \left[ 1 + 2e^{-j\frac{4\pi}{5}k} + 3e^{-j\frac{8\pi}{5}k} \right], \quad k = 0,1,2,3,4
}
\]
### **b)**
\[
\boxed{
Y(k) = \frac{1}{4} \left[ 3 + 2e^{-j\frac{\pi}{2}k} + e^{-j\pi k} + 2e^{-j\frac{3\pi}{2}k} \right], \quad k = 0,1,2,3
}
\]
If you need the explicit numerical values for each \( k \), let me know!
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