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Give step-by-step solution with explanation and final answer:Problem 3 : Present the rationale for whether each of the following filters are: a) Linear, b) Time Invariant, c) Stable, and d) Dynamic. Lym) =xmxm-1) IL. ym) =u(m-1a™Vxm) forla|

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Give step-by-step solution with explanation and final answer:Uploaded ImageProblem 3 : Present the rationale for whether each of the following filters are: a) Linear, b) Time Invariant, c) Stable, and d) Dynamic. Lym) =xmxm-1) IL. ym) =u(m-1a™Vxm) forla|

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Asked by: Abhishek
Created at: 2025-09-21 11:23:27

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# Problem 3: Filter Properties Analysis Let's analyze each filter for the following properties: - **Linearity** - **Time Invariance** - **Stability** - **Dynamism (Static or Dynamic)** --- ## I. \( y(n) = x(n)x(n-1) \) ### a) **Linearity** - **Test:** For linearity, the system must satisfy additivity and homogeneity. - **Check:** \( y_1(n) = x_1(n)x_1(n-1) \) \( y_2(n) = x_2(n)x_2(n-1) \) For input \( a x_1(n) + b x_2(n) \): \[ y(n) = [a x_1(n) + b x_2(n)][a x_1(n-1) + b x_2(n-1)] \] This expands to cross-terms, so **not linear**. ### b) **Time Invariant** - **Test:** Substitute \( x(n-k) \) as input. - **Check:** Input \( x(n-k) \): \[ y(n) = x(n-k)x(n-k-1) \] Output is delayed by \( k \). So, **time-invariant**. ### c) **Stable** - **Test:** BIBO (Bounded Input, Bounded Output). - **Check:** Product of two bounded signals is bounded. **Stable**. ### d) **Dynamic** - **Test:** Output depends on past/future inputs. - **Check:** Depends on \( x(n) \) and \( x(n-1) \). **Dynamic**. --- ## II. \( y(n) = u(n-1)\alpha^{(n-1)}x(n) \), \( |\alpha| < 1 \) ### a) **Linearity** - **Check:** Directly proportional to \( x(n) \), so **linear**. ### b) **Time Invariant** - **Check:** For \( x(n-k) \): \[ y(n) = u(n-1)\alpha^{(n-1)}x(n-k) \] For time-invariant system, delay must only shift output. Here, the step and exponent are functions of \( n \), not \( n-k \). Therefore, **not time-invariant**. ### c) **Stable** - **Check:** \( u(n-1) \) is 1 for \( n \geq 1 \), and \( |\alpha| < 1 \) makes the coefficient bounded. So, **stable**. ### d) **Dynamic** - **Check:** Output depends only on present input \( x(n) \). **Static**. --- ## III. \( y(n) = u(n)\cos(x(n)) \) ### a) **Linearity** - **Check:** Cosine is non-linear. **Not linear**. ### b) **Time Invariant** - **Check:** \( x(n-k) \) yields \( y(n) = u(n)\cos(x(n-k)) \), while delaying output gives \( u(n-k)\cos(x(n-k)) \). Thus, **not time-invariant**. ### c) **Stable** - **Check:** Cosine of any real number is bounded by [-1, 1], \( u(n) \) is 0 or 1. So, **stable**. ### d) **Dynamic** - **Check:** Only depends on \( x(n) \). **Static**. --- ## **Summary Table** | System | Linear | Time Invariant | Stable | Dynamic | |--------------------------------------|:------:|:--------------:|:------:|:-------:| | \( y(n) = x(n)x(n-1) \) | No | Yes | Yes | Yes | | \( y(n) = u(n-1)\alpha^{n-1}x(n) \) | Yes | No | Yes | No | | \( y(n) = u(n)\cos(x(n)) \) | No | No | Yes | No | --- ### **Explanation Provided Above** for each step and property. Let me know if you need a breakdown of each test!

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