Give step-by-step solution with explanation and final answer:Problem 3 : Present the rationale for whether each of the following filters are: a) Linear, b) Time Invariant, c) Stable, and d) Dynamic. Lym) =xmxm-1) IL. ym) =u(m-1a™Vxm) forla|
Question:
Give step-by-step solution with explanation and final answer:
Problem 3 : Present the rationale for whether each of the following filters are: a) Linear, b) Time Invariant, c)
Stable, and d) Dynamic.
Lym) =xmxm-1)
IL. ym) =u(m-1a™Vxm) forla|
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Asked by: Abhishek
Created at: 2025-09-21 11:23:27
Asked by: Abhishek
Created at: 2025-09-21 11:23:27
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# Problem 3: Filter Properties Analysis
Let's analyze each filter for the following properties:
- **Linearity**
- **Time Invariance**
- **Stability**
- **Dynamism (Static or Dynamic)**
---
## I. \( y(n) = x(n)x(n-1) \)
### a) **Linearity**
- **Test:** For linearity, the system must satisfy additivity and homogeneity.
- **Check:**
\( y_1(n) = x_1(n)x_1(n-1) \)
\( y_2(n) = x_2(n)x_2(n-1) \)
For input \( a x_1(n) + b x_2(n) \):
\[
y(n) = [a x_1(n) + b x_2(n)][a x_1(n-1) + b x_2(n-1)]
\]
This expands to cross-terms, so **not linear**.
### b) **Time Invariant**
- **Test:** Substitute \( x(n-k) \) as input.
- **Check:**
Input \( x(n-k) \):
\[
y(n) = x(n-k)x(n-k-1)
\]
Output is delayed by \( k \). So, **time-invariant**.
### c) **Stable**
- **Test:** BIBO (Bounded Input, Bounded Output).
- **Check:**
Product of two bounded signals is bounded. **Stable**.
### d) **Dynamic**
- **Test:** Output depends on past/future inputs.
- **Check:**
Depends on \( x(n) \) and \( x(n-1) \). **Dynamic**.
---
## II. \( y(n) = u(n-1)\alpha^{(n-1)}x(n) \), \( |\alpha| < 1 \)
### a) **Linearity**
- **Check:** Directly proportional to \( x(n) \), so **linear**.
### b) **Time Invariant**
- **Check:**
For \( x(n-k) \):
\[
y(n) = u(n-1)\alpha^{(n-1)}x(n-k)
\]
For time-invariant system, delay must only shift output. Here, the step and exponent are functions of \( n \), not \( n-k \).
Therefore, **not time-invariant**.
### c) **Stable**
- **Check:**
\( u(n-1) \) is 1 for \( n \geq 1 \), and \( |\alpha| < 1 \) makes the coefficient bounded.
So, **stable**.
### d) **Dynamic**
- **Check:**
Output depends only on present input \( x(n) \). **Static**.
---
## III. \( y(n) = u(n)\cos(x(n)) \)
### a) **Linearity**
- **Check:**
Cosine is non-linear. **Not linear**.
### b) **Time Invariant**
- **Check:**
\( x(n-k) \) yields \( y(n) = u(n)\cos(x(n-k)) \), while delaying output gives \( u(n-k)\cos(x(n-k)) \).
Thus, **not time-invariant**.
### c) **Stable**
- **Check:**
Cosine of any real number is bounded by [-1, 1], \( u(n) \) is 0 or 1. So, **stable**.
### d) **Dynamic**
- **Check:**
Only depends on \( x(n) \). **Static**.
---
## **Summary Table**
| System | Linear | Time Invariant | Stable | Dynamic |
|--------------------------------------|:------:|:--------------:|:------:|:-------:|
| \( y(n) = x(n)x(n-1) \) | No | Yes | Yes | Yes |
| \( y(n) = u(n-1)\alpha^{n-1}x(n) \) | Yes | No | Yes | No |
| \( y(n) = u(n)\cos(x(n)) \) | No | No | Yes | No |
---
### **Explanation Provided Above** for each step and property. Let me know if you need a breakdown of each test!
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