Give step-by-step solution with explanation and final answer:beet k Hy 8 Hit dl H ix nN : Hi :
Question:
Give step-by-step solution with explanation and final answer:
beet k
Hy 8
Hit dl
H ix
nN :
Hi :
This is AI generated Response.
Asked by: Venkatesh
Created at: 2025-09-18 05:53:03
Asked by: Venkatesh
Created at: 2025-09-18 05:53:03
Final Answer:
Rendered
Raw Text
Did you like this answer?
Let's break down and solve the **"finding the explosion"** problem step by step.
---
### **Problem Restatement**
**Three microphones** recorded an explosion.
- The sound reached the microphone at **site A** **2.5 seconds** later than it reached the microphone at **site B**, and **1.5 seconds** after site C.
- Sites A and B are **0.75 mile apart** and sites A and C are **1.3 miles apart**.
- **Estimate the location** of the explosion **within 10 feet**, giving **distance and direction from site A**.
- **Assume sound moves at 1100 ft/sec**.
---
### **Step 1: Assign Variables and Coordinates**
Let:
- The location of the explosion be at point \( (x, y) \).
- Site **A** at \( (0, 0) \).
- Site **B** at \( (d_1, 0) \), with \( d_1 = 0.75 \) miles.
- Site **C** at \( (x_C, y_C) \), with \( AC = 1.3 \) miles.
- For simplicity, let's place C along the y-axis: \( (0, d_2) \), with \( d_2 = 1.3 \) miles.
**Convert miles to feet:**
- 1 mile = 5280 feet.
- \( d_1 = 0.75 \times 5280 = 3960 \) ft.
- \( d_2 = 1.3 \times 5280 = 6864 \) ft.
So:
- **A**: \( (0, 0) \)
- **B**: \( (3960, 0) \)
- **C**: \( (0, 6864) \)
---
### **Step 2: Set Up Equations for Sound Arrival Times**
Let the explosion occur at \( (x, y) \).
Let the time for sound to reach A be \( t_A \), B be \( t_B \), and C be \( t_C \).
\[
t_A = \frac{\sqrt{x^2 + y^2}}{1100}
\]
\[
t_B = \frac{\sqrt{(x - 3960)^2 + y^2}}{1100}
\]
\[
t_C = \frac{\sqrt{x^2 + (y - 6864)^2}}{1100}
\]
Given:
- \( t_A = t_B + 2.5 \)
- \( t_A = t_C + 1.5 \)
---
### **Step 3: Write System of Equations**
#### **Equation 1 (A vs B):**
\[
\frac{\sqrt{x^2 + y^2}}{1100} = \frac{\sqrt{(x-3960)^2 + y^2}}{1100} + 2.5
\]
\[
\sqrt{x^2 + y^2} = \sqrt{(x-3960)^2 + y^2} + 1100 \times 2.5
\]
\[
\sqrt{x^2 + y^2} = \sqrt{(x - 3960)^2 + y^2} + 2750
\]
#### **Equation 2 (A vs C):**
\[
\frac{\sqrt{x^2 + y^2}}{1100} = \frac{\sqrt{x^2 + (y-6864)^2}}{1100} + 1.5
\]
\[
\sqrt{x^2 + y^2} = \sqrt{x^2 + (y - 6864)^2} + 1100 \times 1.5
\]
\[
\sqrt{x^2 + y^2} = \sqrt{x^2 + (y - 6864)^2} + 1650
\]
---
### **Step 4: Simplify and Solve (Algebraically)**
#### **Equation 1**
Let \( S = \sqrt{x^2 + y^2} \):
\[
S = \sqrt{(x-3960)^2 + y^2} + 2750
\]
\[
S - 2750 = \sqrt{(x-3960)^2 + y^2}
\]
Square both sides:
\[
(S - 2750)^2 = (x-3960)^2 + y^2
\]
\[
S^2 - 2 \times 2750 \times S + 2750^2 = (x-3960)^2 + y^2
\]
But \( S^2 = x^2 + y^2 \), so:
\[
x^2 + y^2 - 5500S + 7562500 = x^2 - 2 \times 3960 \times x + 3960^2 + y^2
\]
\[
x^2 + y^2 - 5500S + 7562500 = x^2 + y^2 - 7920x + 15681600
\]
\[
-5500S + 7562500 = -7920x + 15681600
\]
\[
5500S + 7920x = 15681600 - 7562500
\]
\[
5500S + 7920x = 8129100
\]
---
#### **Equation 2**
Let \( S = \sqrt{x^2 + y^2} \):
\[
S = \sqrt{x^2 + (y-6864)^2} + 1650
\]
\[
S - 1650 = \sqrt{x^2 + (y-6864)^2}
\]
Square both sides:
\[
(S - 1650)^2 = x^2 + (y-6864)^2
\]
\[
S^2 - 2 \times 1650 \times S + 1650^2 = x^2 + y^2 - 2 \times 6864 \times y + 6864^2
\]
\[
x^2 + y^2 - 3300S + 2722500 = x^2 + y^2 - 13728y + 47114304
\]
\[
-3300S + 2722500 = -13728y + 47114304
\]
\[
3300S + 13728y = 47114304 - 2722500
\]
\[
3300S + 13728y = 44391804
\]
---
### **Step 5: Substitute and Solve (Numerical Approach)**
**We have:**
1. \( 5500S + 7920x = 8129100 \)
2. \( 3300S + 13728y = 44391804 \)
But \( S = \sqrt{x^2 + y^2} \).
Let’s solve this system numerically.
#### **Guess and refine**
Let's use an estimation and substitution approach.
##### **Express x and y in terms of S:**
From (1):
\[
7920x = 8129100 - 5500S \implies x = \frac{8129100 - 5500S}{7920}
\]
From (2):
\[
13728y = 44391804 - 3300S \implies y = \frac{44391804 - 3300S}{13728}
\]
But \( S = \sqrt{x^2 + y^2} \).
Let’s try a value for \( S \):
#### **Try S = 6000**
- \( x = \frac{8129100 - 5500 \times 6000}{7920} = \frac{8129100 - 33000000}{7920} = \frac{-24870900}{7920} \approx -3142 \) ft
- \( y = \frac{44391804 - 3300 \times 6000}{13728} = \frac{44391804 - 19800000}{13728} = \frac{24591804}{13728} \approx 1791 \) ft
Compute \( S \):
\[
S^2 = (-3142)^2 + (1791)^2 = 9871764 + 3209761 = 13081525
\]
\[
S = \sqrt{13081525} \approx 3616
\]
But we guessed S = 6000, so let's try S = 4000.
#### **Try S = 4000**
- \( x = \frac{8129100 - 5500 \times 4000}{7920} = \frac{8129100 - 22000000}{7920} = \frac{-13870900}{7920} \approx -1751 \)
- \( y = \frac{44391804 - 3300 \times 4000}{13728} = \frac{44391804 - 13200000}{13728} = \frac{31191804}{13728} \approx 2272 \)
\[
S^2 = (-1751)^2 + (2272)^2 = 3068001 + 5161984 = 8229985
\]
\[
S = \sqrt{8229985} \approx 2868
\]
Still too low. Try S = 5000.
#### **Try S = 5000**
- \( x = \frac{8129100 - 5500 \times 5000}{7920} = \frac{8129100 - 27500000}{7920} = \frac{-19370900}{7920} \approx -2447 \)
- \( y = \frac{44391804 - 3300 \times 5000}{13728} = \frac{44391804 - 16500000}{13728} = \frac{27891804}{13728} \approx 2032 \)
\[
S^2 = (-2447)^2 + (2032)^2 = 5990409 + 4129024 = 10119433
\]
\[
S = \sqrt{10119433} \approx 3182
\]
The values for S are much lower than our guess. Try S = 3000.
#### **Try S = 3000**
- \( x = \frac{8129100 - 5500 \times 3000}{7920} = \frac{8129100 - 16500000}{7920} = \frac{-8370900}{7920} \approx -1057 \)
- \( y = \frac{44391804 - 3300 \times 3000}{13728} = \frac{44391804 - 9900000}{13728} = \frac{34491804}{13728} \approx 2512 \)
\[
S^2 = (-1057)^2 + (2512)^2 = 1117849 + 6300144 = 7417993
\]
\[
S = \sqrt{7417993} \approx 2724
\]
Let’s try S = 2000.
#### **Try S = 2000**
- \( x = \frac{8129100 - 5500 \times 2000}{7920} = \frac{8129100 - 11000000}{7920} = \frac{-2860900}{7920} \approx -361 \)
- \( y = \frac{44391804 - 3300 \times 2000}{13728} = \frac{44391804 - 6600000}{13728} = \frac{37791804}{13728} \approx 2753 \)
\[
S^2 = (-361)^2 + (2753)^2 = 130321 + 7578709 = 7709030
\]
\[
S = \sqrt{7709030} \approx 2776
\]
It looks like our guess for S needs to be between 2700 and 3200.
Let’s try S = 2800.
#### **Try S = 2800**
- \( x = \frac{8129100 - 5500 \times 2800}{7920} = \frac{8129100 - 15400000}{7920} = \frac{-7270900}{7920} \approx -918 \)
- \( y = \frac{44391804 - 3300 \times 2800}{13728} = \frac{44391804 - 9240000}{13728} = \frac{35151804}{13728} \approx 2561 \)
\[
S^2 = (-918)^2 + (2561)^2 = 842724 + 6550721 = 7393445
\]
\[
S = \sqrt{7393445} \approx 2718
\]
#### **Try S = 3200**
- \( x = \frac{8129100 - 5500 \times 3200}{7920} = \frac{8129100 - 17600000}{7920} = \frac{-9460900}{7920} \approx -1195 \)
- \( y = \frac{44391804 - 3300 \times 3200}{13728} = \frac{44391804 - 10560000}{13728} = \frac{33831804}{13728} \approx 2464 \)
\[
S^2 = (-1195)^2 + (2464)^2 = 1428025 + 6071296 = 7499321
\]
\[
S = \sqrt{7499321} \approx 2739
\]
#### **Try S = 4000**
Already tried; found S ≈ 2868.
So, the answer for S is around 2700–2800
📢 Instructions:
- Ask anything relatd to above question only.
- For new Question goto :
VIPSolutions