## Given - Resistance, \( R = 50\,\Omega \) - Voltage, \( V = 240\,\text{V} \) ## Step 1: Calculate the Current Ohm’s Law: \[ I = \frac{V}{R} \] Substitute given values: \[ I = \{240}{50} = 4.8\,\text{A} \] ## Step 2: Calculate the Power Dissipated Power dissipated in a resistor: \[ P = V \times I \] Substitute the values: \[ P = 240 \times 4.8 = 1152\,\text{W} \] Alternatively, use \( P = I^2R \): \[ P = (4.8)^2 \times 50 = 23.04 \times 50 = 1152\,\text{W} \] ## Final Answers - **Current (\( I \))**: \( \boxed{4.8\,\text{A}} \) - **Power (\( P \))**: \( \boxed{1152\,\text{W}} \) --- **Note:** - The answers you provided (48 A and 11520 W) are incorrect. The correct answers are 4.8 A and 1152 W. - Double-check the resistance value (50 Ω, not 5 Ω) and calculations.