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Asked by: Yatin
Created at: 2025-09-05 17:30:39
Final Answer:
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---
## **1. Draw MSL Pressure Isobars Every 4 mb**
**Step-by-step:**
- **Identify Pressure Values:** The numbers plotted at each station are the MSL pressures in mb.
- **Choose Isobar Values:** Select a starting value, e.g., 1000 mb, and then draw isobars at intervals of 4 mb (e.g., 996, 1000, 1004, 1008, 1012, etc.).
- **Draw Isobars:** Connect points of equal pressure smoothly. Isobars should not cross each other.
- **Sketch Example:**
- If you see 245 at one station and 241 at a nearby station, the 244 mb isobar passes between them.
*(Since I can't physically draw on your image, you would print or use a digital tool to connect these pressure values with lines.)*
---
## **2. Sketch Geostrophic and Surface Wind Directions**
**Geostrophic Wind:**
- **Direction:** Parallel to isobars, with low pressure on the left (in the Northern Hemisphere).
- **Indicate with:** Blue arrows.
**Surface Wind:**
- **Direction:** Crosses isobars at a slight angle toward lower pressure due to friction, typically 20-30° from the isobar direction toward low pressure.
- **Indicate with:** Green arrows.
**Where to Draw:**
- Pick several locations on the map, especially near tightly packed isobars, and sketch blue arrows parallel to isobars, green arrows at a slight angle toward lower pressure.
---
## **3. Compute Geostrophic Wind Speed at 45ºN (Isobars 250 km Apart)**
**Formula:**
\[
V_g = \frac{1}{f \rho} \left| \frac{\Delta p}{\Delta n} \right|
\]
But commonly:
\[
V_g = \frac{g}{f} \cdot \frac{\Delta Z}{\Delta n}
\]
For surface maps (pressure):
\[
V_g = \frac{1}{f \rho} \cdot \frac{\Delta p}{\Delta n}
\]
**Simplified for pressure:**
\[
V_g \approx \frac{\Delta p}{f \rho \Delta n}
\]
Where:
- \(\Delta p\) = pressure difference (4 mb = 400 Pa)
- \(\Delta n\) = distance between isobars (250 km = 250,000 m)
- \(\rho\) = air density (1.225 kg/m³)
- \(f\) = Coriolis parameter \( = 2\Omega \sin \phi \) (\(\Omega = 7.292 \times 10^{-5}\) s⁻¹)
**At \(45^\circ N\):**
- \(\sin 45^\circ = 0.7071\)
- \(f = 2 \times 7.292 \times 10^{-5} \times 0.7071 \approx 1.03 \times 10^{-4}\) s⁻¹
**Plug in values:**
\[
V_g = \frac{400}{1.03 \times 10^{-4} \times 1.225 \times 250,000}
\]
Calculate denominator:
\[
1.03 \times 10^{-4} \times 1.225 \times 250,000 = 31.56
\]
Calculate \(V_g\):
\[
V_g = \frac{400}{31.56} \approx 12.7 \text{ m/s}
\]
---
## **4. Compute Geostrophic Wind Speed at 30ºN (Same Isobar Spacing)**
**At \(30^\circ N\):**
- \(\sin 30^\circ = 0.5\)
- \(f = 2 \times 7.292 \times 10^{-5} \times 0.5 = 7.292 \times 10^{-5}\) s⁻¹
**Plug in values:**
\[
V_g = \frac{400}{7.292 \times 10^{-5} \times 1.225 \times 250,000}
\]
Calculate denominator:
\[
7.292 \times 10^{-5} \times 1.225 \times 250,000 = 22.35
\]
Calculate \(V_g\):
\[
V_g = \frac{400}{22.35} \approx 17.9 \text{ m/s}
\]
---
## **Summary Table**
| Latitude | Coriolis \(f\) (s⁻¹) | Wind Speed (m/s) |
|----------|----------------------|------------------|
| 45ºN | \(1.03 \times 10^{-4}\) | 12.7 |
| 30ºN | \(7.29 \times 10^{-5}\) | 17.9 |
---
## **Final Answers:**
1. **Draw isobars every 4 mb on the map by connecting stations of equal pressure.**
2. **Draw blue arrows parallel to isobars (geostrophic wind), green arrows at a slight angle across isobars toward lower pressure (surface wind).**
3. **Geostrophic wind speed at 45ºN with 4 mb isobars 250 km apart: ≈ 12.7 m/s**
4. **Geostrophic wind speed at 30ºN with same spacing: ≈ 17.9 m/s**
If you need a visual sketch or want to see arrows drawn on the map, let me know and I can annotate the image for you!
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