Certainly! Let's start by writing down the matrix from the image: \[ A = \begin{bmatrix} 1 & 0 & 0 & 3 & 5 \\ 1 & 9 & 8 & 4 & 3 \\ 1 & 3 & 5 & 5 & 4 \\ 0 & 0 & 9 & 0 & 6 \\ 6 & 8 & 4 & 0 & 1 \\ \end{bmatrix} \] However, the problem statement does **not** specify the manipulations to perform yet. If you have further steps or questions (like transpose, sum, mean, max, rotation, etc.), **please specify** what operations you want for this matrix. ### Common operations with explanation: #### 1. **Transpose** Switch rows and columns: \[ A^T = \begin{bmatrix} 1 & 1 & 1 & 0 & 6 \\ 0 & 9 & 3 & 0 & 8 \\ 0 & 8 & 5 & 9 & 4 \\ 3 & 4 & 5 & 0 & 0 \\ 5 & 3 & 4 & 6 & 1 \\ \end{bmatrix} \] #### 2. **Sum of all elements** Add all elements together: \[ \text{Sum} = 1+0+0+3+5+1+9+8+4+3+1+3+5+5+4+0+0+9+0+6+6+8+4+0+1 = 95 \] #### 3. **Maximum element** Find the largest value: - Max = 9 #### 4. **Sum of each row** \[ \begin{align*} \text{Row 1:} &\ 1+0+0+3+5 = 9 \\ \text{Row 2:} &\ 1+9+8+4+3 = 25 \\ \text{Row 3:} &\ 1+3+5+5+4 = 18 \\ \text{Row 4:} &\ 0+0+9+0+6 = 15 \\ \text{Row 5:} &\ 6+8+4+0+1 = 19 \\ \end{align*} \] #### 5. **Sum of each column** \[ \begin{align*} \text{Col 1:} &\ 1+1+1+0+6 = 9 \\ \text{Col 2:} &\ 0+9+3+0+8 = 20 \\ \text{Col 3:} &\ 0+8+5+9+4 = 26 \\ \text{Col 4:} &\ 3+4+5+0+0 = 12 \\ \text{Col 5:} &\ 5+3+4+6+1 = 19 \\ \end{align*} \] --- **Please tell me which operation(s) you would like step-by-step solutions for!**