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Give step-by-step solution with explanation and final answer:~ Problem #7. + The figure shows a gripper mechanism. Classify it according to the Grashof and Barker criteria. A Boy C @ —— tT =e — =P | |» TS mm 30 mm

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Give step-by-step solution with explanation and final answer:Uploaded Image~ Problem #7. + The figure shows a gripper mechanism. Classify it according to the Grashof and Barker criteria. A Boy C @ —— tT =e — =P | |» TS mm 30 mm

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Asked by: manish kumar
Created at: 2025-09-02 21:21:26

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Let's solve the problem step-by-step. ### **Step 1: Identify the Links** From the diagram, let's label the four-bar linkage: - **Link 1 (Ground Link):** \( BG \) (fixed frame, distance between pivots \( B \) and \( G \)) - **Link 2 (Input/Crank):** \( AB \) (handle, rotates about \( B \)) - **Link 3 (Coupler):** \( DF \) (connects pivot \( D \) to \( F \)) - **Link 4 (Output/Rocker):** \( CF \) (jaw, rotates about \( G \)) ### **Step 2: Measure the Link Lengths** From the diagram (all measurements are in mm): - **AB = 70 mm** - **BC = 70 mm** - **CD = 70 mm** - **DF = 30 mm** - **CF = 30 mm** - **FG = 30 mm** But for four-bar analysis, let's focus on the four-bar loop: - **AB = 70 mm** (Input) - **BC = 30 mm** (Coupler) - **CF = 30 mm** (Output) - **FA = 70 mm** (Fixed frame or ground link) So, the four links are: - **s (shortest):** 30 mm (BC or CF) - **l (longest):** 70 mm (AB or FA) - **p = 30 mm** - **q = 70 mm** ### **Step 3: Grashof’s Criterion** Grashof’s Law: For a four-bar mechanism with link lengths \( s \), \( l \), \( p \), \( q \) (where \( s \) = shortest, \( l \) = longest), the condition is: \[ s + l \leq p + q \] Here: - \( s = 30 \) - \( l = 70 \) - \( p = 30 \) - \( q = 70 \) Calculate both sides: - \( s + l = 30 + 70 = 100 \) - \( p + q = 30 + 70 = 100 \) So, \[ s + l = p + q \] **According to Grashof's law:** - If \( s + l < p + q \): At least one link can make a full revolution (Grashof mechanism). - If \( s + l = p + q \): It is a special case called a "change-point" mechanism. - If \( s + l > p + q \): No link can make a full revolution (Non-Grashof mechanism). **In this case:** This is a **change-point mechanism**. ### **Step 4: Barker's Classification** Barker’s classification is about the inversion of the four-bar linkage: - **If the shortest link is fixed:** Double-crank (both links can rotate 360°). - **If the link adjacent to the shortest is fixed:** Crank-rocker (one rotates, other rocks). - **If the link opposite the shortest is fixed:** Double-rocker (both rock). Here, the fixed link (frame) is one of the longest links (70 mm), and the shortest links (30 mm) are not fixed. **Thus, by Barker's criteria:** This mechanism is a **double-rocker**. --- ## **Final Classification** ### **According to Grashof’s Law:** - **Change-point mechanism** (since \( s + l = p + q \)) ### **According to Barker’s Criteria:** - **Double-rocker mechanism** --- ### **Summary Table** | Criteria | Classification | |------------------|-----------------------| | Grashof's Law | Change-point | | Barker's Criteria| Double-rocker | --- **Final Answer:** **The given gripper mechanism is a change-point mechanism according to Grashof’s law and a double-rocker mechanism according to Barker’s criteria.**

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