Give step-by-step solution with explanation and final answer:Tom Sowyer's Fence. Tom Sawyer paints his neighbors’ fences charging 2.00 pounds sterling per square.
meter Calculate the area of th following fences and how much he will charge for each (assume each
ans unit is in meters), and sketch the ences in R*
‘Th fence whase base ies on the upper half of the unt circ (FIGURE), and whose height a each point
is given bythe function f(x,y) = 2-
Question:
Give step-by-step solution with explanation and final answer:Tom Sowyer's Fence. Tom Sawyer paints his neighbors’ fences charging 2.00 pounds sterling per square.
meter Calculate the area of th following fences and how much he will charge for each (assume each
ans unit is in meters), and sketch the ences in R*
‘Th fence whase base ies on the upper half of the unt circ (FIGURE), and whose height a each point
is given bythe function f(x,y) = 2-
This is AI generated Response.
Asked by: Test User 100147
Created at: 2025-05-07 22:02:24
Final Answer:
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Let's break down the problem step by step:
---
### **Step 1: Understanding the Fence**
- **Base:** The base lies on the *upper half of the unit circle*, i.e., \( x^2 + y^2 \leq 1 \), and \( y \geq 0 \).
- **Height:** At each point \((x, y)\), the height is \( f(x, y) = 2 - y \).
---
### **Step 2: Surface Area Calculation**
Since the function for height is \( z = 2 - y \), and the surface is a vertical "curtain" over the upper half of the unit circle, the surface is **not tilted** (because \( z \) depends only on \( y \)), so we use the "graph surface area" formula:
\[
\text{Area} = \iint_{D} \sqrt{ \left( \frac{\partial f}{\partial x} \right)^2 + \left( \frac{\partial f}{\partial y} \right)^2 + 1} \, dA
\]
For \( f(x, y) = 2 - y \):
\[
\frac{\partial f}{\partial x} = 0, \qquad \frac{\partial f}{\partial y} = -1
\]
So,
\[
\sqrt{ (0)^2 + (-1)^2 + 1 } = \sqrt{2}
\]
Thus,
\[
\text{Area} = \sqrt{2} \iint_{D} dA = \sqrt{2} \cdot (\text{Area of upper half unit circle})
\]
---
#### **Area of the Upper Half Unit Circle**
The area of the whole unit circle is \( \pi \cdot 1^2 = \pi \). The **upper half** is \( \frac{\pi}{2} \).
---
#### **Total Surface Area**
\[
\text{Total Area} = \sqrt{2} \cdot \frac{\pi}{2}
\]
---
### **Step 3: Total Charge**
- **Charge per square meter:** \( 2.00 \) pounds
- **Total charge:** \( 2.00 \times \text{Total Area} \)
\[
\text{Total Charge} = 2.00 \times \sqrt{2} \cdot \frac{\pi}{2} = \sqrt{2} \pi \approx 4.4429 \text{ pounds}
\]
---
### **Step 4: Sketching the Fence**
- The base is the upper semicircle \( x^2 + y^2 \leq 1 \), \( y \geq 0 \).
- The height at each point is \( 2 - y \), so it decreases linearly from 2 at \( y=0 \) to 1 at \( y=1 \).
---
### **Step 5: Final Answers**
#### **a) Surface area:**
\[
\boxed{ \sqrt{2} \cdot \frac{\pi}{2} \text{ m}^2 \approx 2.221 \text{ m}^2 }
\]
#### **b) Total charge:**
\[
\boxed{ \sqrt{2}\pi \text{ pounds} \approx 4.44 \text{ pounds} }
\]
---
**Explanation Summary:**
- Used the formula for surface area of a graph.
- Evaluated the area over the upper half unit circle.
- Multiplied by the cost per unit area.
If you need the explicit sketch, let me know!
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