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Asked by: Veera manikanta
Created at: 2025-08-22 21:36:31
Final Answer:
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Let's break down the solution step by step:
### **Given Data**
- Mass of wheel assembly linkage (\( m \)): **50 kg**
- Radius of inertia (\( r_g \)): **0.4 m**
- Engine linkage angular speed (\( \omega \)): **3 rad/s (CCW)**
- Angular acceleration (\( \alpha \)): **10 rad/s²**
- Mass moments of inertia:
- \( I_2 = 0.263 \) kg·m²
- \( I_3 = 0.860 \) kg·m²
- \( I_4 = 6.063 \) kg·m²
### **Step 1: Calculate the Total Moment of Inertia**
The total moment of inertia (\( I_{total} \)) about the axis of rotation is the sum of all the links involved:
\[
I_{total} = I_2 + I_3 + I_4
\]
\[
I_{total} = 0.263 + 0.860 + 6.063 = 7.186 \text{ kg·m}^2
\]
### **Step 2: Calculate the Torque Required for Angular Acceleration**
The torque (\( \tau \)) needed to accelerate the system is:
\[
\tau_{acceleration} = I_{total} \times \alpha
\]
\[
\tau_{acceleration} = 7.186 \times 10 = 71.86 \text{ Nm}
\]
### **Step 3: Calculate the Torque Required to Overcome Rotational Inertia of the Wheel Assembly**
The wheel assembly mass is 50 kg and its radius of gyration is 0.4 m:
\[
I_{assembly} = m \cdot r_g^2 = 50 \times (0.4)^2 = 50 \times 0.16 = 8 \text{ kg·m}^2
\]
Add this to the total moment of inertia:
\[
I_{total, new} = 7.186 + 8 = 15.186 \text{ kg·m}^2
\]
\[
\tau_{acceleration, new} = I_{total, new} \times \alpha = 15.186 \times 10 = 151.86 \text{ Nm}
\]
### **Step 4: Calculate the Torque Required to Overcome the Gravity Force on the Wheel Assembly**
The force due to gravity:
\[
F_g = m \cdot g = 50 \times 9.81 = 490.5 \text{ N}
\]
This force acts at the center of gravity, which is 0.4 m from the axis.
\[
\tau_{gravity} = F_g \times r_g = 490.5 \times 0.4 = 196.2 \text{ Nm}
\]
### **Step 5: Calculate the Total Required Torque**
Sum the torque required for acceleration and to counteract gravity:
\[
\tau_{required} = \tau_{acceleration, new} + \tau_{gravity}
\]
\[
\tau_{required} = 151.86 + 196.2 = 348.06 \text{ Nm}
\]
---
## **Final Answer**
### **The torque required to be applied by the engine is:**
\[
\boxed{348 \text{ Nm}}
\]
### **Explanation:**
- We summed up the moments of inertia of all components, including the wheel assembly.
- Calculated the torque for desired angular acceleration.
- Added the torque required to hold the mass of the wheel assembly against gravity.
- The total is the required engine torque.
**If you need a more detailed force analysis through the mechanism or have a specific link where the torque is applied, let me know!**
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