Let's break down the problem and solve it step by step. ### Step 1: Understand the Problem We are given a circle graph (pie chart) that shows the **percentages** of people in a certain country with different types of blood. We are to find the **odds against** a randomly selected person having **A+** blood. ### Step 2: Extract Data from the Table From your table (though it is a bit unclear), the relevant information seems to be: - AB: 4% - A−: 7% - A+: 36% - O−: 6% - O+: 45% - B−: 2% - B+: ? Let's assume the missing values are not needed for A+, or if needed, the total should sum to 100%. For now, let's focus on A+. - **A+ = 36%** ### Step 3: Find the Probability **Probability (A+) =** \[ \frac{\text{Number with A+}}{\text{Total number of people}} = \frac{36}{100} = 0.36 \] **Probability (not A+) =** \[ 1 - 0.36 = 0.64 \] ### Step 4: Find the Odds Against The **odds against** an event are: \[ \text{Odds against} = \frac{\text{Probability of not event}}{\text{Probability of event}} \] So, \[ \text{Odds against A+} = \frac{0.64}{0.36} \] To write as a ratio of whole numbers, divide both numbers by 0.04: \[ \frac{0.64}{0.36} = \frac{64}{36} = \frac{16}{9} \] So, the **odds against** are **16:9**. ### Step 5: Final Answer **Final Answer (in simplest form):** \[ \boxed{16:9} \] **Explanation:** If one person is selected at random, the odds against that person having A+ blood are **16:9**. This means, for every 16 people without A+ blood, there are 9 with A+ blood.