Give step-by-step solution with explanation and final answer:E ji SE Sis SiS i i £ ek
Question:
Give step-by-step solution with explanation and final answer:
E ji
SE
Sis
SiS
i
i £
ek
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Asked by: gvr
Created at: 2025-07-26 02:28:32
Asked by: gvr
Created at: 2025-07-26 02:28:32
Final Answer:
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Let's break down and solve the two parts one by one:
---
## **Part 1: Translate the integral into rectangular coordinates**
Given:
\[
\int_{0}^{2\pi}\int_{0}^{3}\int_{0}^{4} r \cos(θ) \, dr \, dθ \, dz
\]
This is an integral in **cylindrical coordinates**. The variables are:
- \( r \) = radius (distance from \( z \)-axis)
- \( θ \) = angle (from \( x \)-axis)
- \( z \) = height
### **Step 1: Identify the bounds and function**
- \( r \) from 0 to 3
- \( θ \) from 0 to \( 2\pi \)
- \( z \) from 0 to 4
- The function is \( r \cos θ \)
### **Step 2: Convert function to rectangular coordinates**
Recall the conversions:
- \( x = r \cos θ \)
- \( y = r \sin θ \)
- \( r = \sqrt{x^2 + y^2} \)
- \( θ = \tan^{-1}(y/x) \)
- \( z = z \)
So, \( r \cos θ = x \).
### **Step 3: Convert the bounds**
- \( r \) from 0 to 3: This describes a circle of radius 3 in the \( xy \)-plane.
- \( θ \) from 0 to \( 2\pi \): Full circle.
- \( z \) from 0 to 4: Standard.
So, the region in rectangular coordinates is:
- \( x^2 + y^2 \leq 9 \)
- \( 0 \leq z \leq 4 \)
### **Step 4: The integral in rectangular coordinates**
The volume element in cylindrical is \( r dr dθ dz \), and in rectangular is \( dx\,dy\,dz \).
So, the integral becomes:
\[
\int_{z=0}^{4} \int_{x^2+y^2 \leq 9} x \, dx \, dy \, dz
\]
---
## **Part 2: Translate the point \((-7, 7, 4)\) from rectangular to cylindrical coordinates**
Given:
- \( x = -7 \)
- \( y = 7 \)
- \( z = 4 \)
### **Step 1: Convert to cylindrical coordinates**
Formulas:
- \( r = \sqrt{x^2 + y^2} \)
- \( θ = \tan^{-1}(y/x) \)
- \( z = z \)
Calculate:
- \( r = \sqrt{(-7)^2 + (7)^2} = \sqrt{49 + 49} = \sqrt{98} = 7\sqrt{2} \)
- \( θ = \tan^{-1}\left(\frac{7}{-7}\right) = \tan^{-1}(-1) \)
Note: \((x, y) = (-7, 7)\) is in the **second quadrant**. For \(\tan^{-1}(-1)\), the principal value is \(-\frac{\pi}{4}\), but in the second quadrant, add \(\pi\):
\[
θ = \pi - \frac{\pi}{4} = \frac{3\pi}{4}
\]
So, the cylindrical coordinates are:
\[
(r, θ, z) = (7\sqrt{2}, \frac{3\pi}{4}, 4)
\]
---
## **Final Answers**
### **1. Integral in rectangular coordinates:**
\[
\boxed{
\int_{z=0}^{4} \int_{x^2+y^2 \leq 9} x \, dx \, dy \, dz
}
\]
### **2. Point in cylindrical coordinates:**
\[
\boxed{
(7\sqrt{2},\ \frac{3\pi}{4},\ 4)
}
\]
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