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Give step-by-step solution with explanation and final answer:| set on epost te 30 shor, tect oo dow rE. ie x (m) I - d 23 ud t . (sec) 55

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Give step-by-step solution with explanation and final answer:Uploaded Image| set on epost te 30 shor, tect oo dow rE. ie x (m) I - d 23 ud t . (sec) 55

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Asked by: Gurusharan
Created at: 2025-06-28 06:33:08

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Let's analyze the **position vs. time** graph to determine when the object is **slowing down**. ### Step 1: Understanding Slowing Down - An object **slows down** when its **velocity** and **acceleration** have **opposite signs** (i.e., one is positive, the other is negative). ### Step 2: Determine Velocity and Acceleration from Position-Time Graph - **Velocity** is the **slope** of the position-time graph. - **Acceleration** is the **slope of the velocity** (i.e., whether the slope of the position-time graph is increasing or decreasing). ### Step 3: Analyze the Graph #### 0 to 1 second: - Slope (velocity) is **negative** (downward line). - The slope is **constant** (straight line), so **acceleration is zero**. #### 1 to 2 seconds: - Slope is **negative** (still going down). - The slope is getting **less steep** (towards 2 seconds), so **acceleration is positive** (velocity is becoming less negative). - **Velocity (negative)** and **acceleration (positive)**: **Slowing down!** #### At \( t = 1.5 \) seconds: - This is **in the middle of 1 and 2 seconds**. - The correct answer is likely to be **1.5 seconds**. #### 2 to 3 seconds: - Slope (velocity) is **increasing**, becomes **zero** at \( t = 2.5 \) s (the bottom of the curve), then **positive** after. - Slope is **increasing** (acceleration is positive). - **Velocity and acceleration both positive** after 2.5 s, so it's **speeding up**. #### 3 to 4 seconds: - Slope (velocity) is **negative** again. - The slope is **getting steeper in the negative direction** (acceleration negative). - **Both negative**: Speeding up, not slowing down. ### Step 4: Final Answer The object is **slowing down** at **1.5 seconds**. --- ### **Final Answer:** **1.5 seconds** (Option: 1.5)

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