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Give step-by-step solution with explanation and final answer:7. [-/2Points] | DETAILS MY NOTES || ASK YOUR TEACHER Describe Newton's Method for approximating the zeros of a function. Iisa function sect © on [a,b] and —ssect— 8 on (a, b), where c € a, b] and fc) = then Newton's Method uses —seiect— @ lines to approximate c. First, estimate an Initial x, close to 7 8 . Then, determine x, using x, = —Swiect— Calculate a third estimate using x = ——-Swisct-— Continue this process unt -—Ssisct.— 8 is within the desired accuracy, and let x, ; be the final approximation of c.

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Give step-by-step solution with explanation and final answer:Uploaded Image7. [-/2Points] | DETAILS MY NOTES || ASK YOUR TEACHER Describe Newton's Method for approximating the zeros of a function. Iisa function sect © on [a,b] and —ssect— 8 on (a, b), where c € a, b] and fc) = then Newton's Method uses —seiect— @ lines to approximate c. First, estimate an Initial x, close to 7 8 . Then, determine x, using x, = —Swiect— Calculate a third estimate using x = ——-Swisct-— Continue this process unt -—Ssisct.— 8 is within the desired accuracy, and let x, ; be the final approximation of c.

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Asked by: gvr
Created at: 2025-06-27 03:12:31

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Let's solve this step by step: ### Step 1: Fill in the blanks #### 1. If \( f \) is a function **differentiable** on \((a, b)\) and **continuous** on \([a, b]\), where \( c \in [a, b] \) and \( f(c) = 0 \), then Newton's Method uses **tangent** lines to approximate \( c \). #### 2. First, estimate an initial \( x_1 \) close to \( c \). Then, determine \( x_2 \) using \( x_2 = x_1 - \frac{f(x_1)}{f'(x_1)} \). Calculate a third estimate using \( x_3 = x_2 - \frac{f(x_2)}{f'(x_2)} \). Continue this process until \( |x_{n+1} - x_n| \) is within the desired accuracy, and let \( x_{n+1} \) be the final approximation of \( c \). --- ### **Final Answer (with explanations):** If \( f \) is a function **differentiable** on \( (a, b) \) and **continuous** on \( [a, b] \), where \( c \in [a, b] \) and \( f(c) = 0 \), then Newton's Method uses **tangent** lines to approximate \( c \). First, estimate an initial \( x_1 \) close to \( c \). Then, determine \( x_2 \) using \( x_2 = x_1 - \frac{f(x_1)}{f'(x_1)} \). Calculate a third estimate using \( x_3 = x_2 - \frac{f(x_2)}{f'(x_2)} \). Continue this process until \( |x_{n+1} - x_n| \) is within the desired accuracy, and let \( x_{n+1} \) be the final approximation of \( c \). --- #### **Explanation:** - **Differentiable**: Newton's Method requires the function to have a derivative. - **Continuous**: The function must be continuous so the root exists in the interval. - **Tangent lines**: The method uses tangent lines to find better approximations for the root. - **Iteration formula**: \( x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \). - **Stopping condition**: When the difference between successive approximations is small enough, we stop and take the latest value as the approximation for the root.

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i need detailed explanation of each bracket along with the final Answer

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Asked by: gvr
Created at: 2025-06-27 03:14:12

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Certainly! Let's carefully analyze each part of the statement, filling in the blanks with detailed explanations, and then summarize the final answer. --- ### Step-by-step Explanation of Each Blank: **1. "If \( f \) is a function **differentiable** on \((a, b)\) and **continuous** on \([a, b]\), where \( c \in [a, b] \) and \( f(c) = 0 \), then Newton's Method uses **tangent** lines to approximate \( c \)."** - **Why "differentiable" and "continuous"?** Newton's method relies on the derivative \( f'(x) \) to construct tangent lines. For the tangent line at a point \( x \) to be well-defined and useful, \( f \) must be differentiable at that point, and the derivative must be continuous in the interval to ensure convergence. - **"uses tangent lines"** Newton's method approximates the root by using the tangent line at a current guess and finding where this tangent intersects the x-axis, thus providing a better approximation. --- **2. "First, estimate an initial \( x_1 \) close to \( c \). Then, determine \( x_2 \) using \( x_2 = x_1 - \frac{f(x_1)}{f'(x_1)} \). Calculate a third estimate using \( x_3 = x_2 - \frac{f(x_2)}{f'(x_2)} \). Continue this process until \( |x_{n+1} - x_n| \) is within the desired accuracy, and let \( x_{n+1} \) be the final approximation of \( c \)."** - **"Estimate an initial \( x_1 \) close to \( c \)":** Choose a starting point near the actual root because the convergence of Newton's method depends on the initial guess being sufficiently close to the actual root. - **"Determine \( x_2 \) using \( x_2 = x_1 - \frac{f(x_1)}{f'(x_1)} \)":** This is the core iterative formula. It computes a better approximation \( x_2 \) by moving from \( x_1 \) along the tangent line at \( x_1 \). - **"Calculate a third estimate using \( x_3 = x_2 - \frac{f(x_2)}{f'(x_2)} \)":** Repeat the process to refine the approximation further, using the previous estimate \( x_2 \). - **"Continue this process until \( |x_{n+1} - x_n| \) is within the desired accuracy"**: The iterations stop when the change between successive approximations is smaller than a predetermined tolerance (indicating convergence). - **"and let \( x_{n+1} \) be the final approximation of \( c \)"**: Once the process converges, \( x_{n+1} \) is taken as the best estimate of the root. --- ### **Final Completed Explanation and Answer:** **Complete Version:** **"If \( f \) is a function _differentiable_ on \((a, b)\) and _continuous_ on \([a, b]\), where \( c \in [a, b] \) and \( f(c) = 0 \), then Newton's Method uses _tangent_ lines to approximate \( c \). First, estimate an initial \( x_1 \) close to \( c \). Then, determine \( x_2 \) using \( x_2 = x_1 - \frac{f(x_1)}{f'(x_1)} \). Calculate a third estimate using \( x_3 = x_2 - \frac{f(x_2)}{f'(x_2)} \). Continue this process until \( |x_{n+1} - x_n| \) is within the desired accuracy, and let \( x_{n+1} \) be the final approximation of \( c \)."** --- ### **Summary of Key Points:** - **Function Conditions:** \( f \) must be differentiable in the interval and continuous to ensure the tangent line approach is valid. - **Initial Guess:** Starting near the actual root improves convergence. - **Iteration Formula:** \[ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \] It uses the tangent line at \( (x_n, f(x_n)) \) to find a better approximation. - **Stopping Criterion:** When the difference between successive approximations is sufficiently small, stop iterating. --- I hope this detailed explanation clarifies each part of the process!

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