Give step-by-step solution with explanation and final answer: generate the answer in englishuw [ we
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Give step-by-step solution with explanation and final answer:
generate the answer in english
uw [ we
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Asked by: gvr
Created at: 2025-06-19 18:38:12
Asked by: gvr
Created at: 2025-06-19 18:38:12
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Let's solve the problem step by step.
### **Step 1: Understanding the Problem**
We have a structure made of two dielectric layers:
- **Layer 1:** Thickness \( a_1 = 1 \) cm, dielectric constant \( \varepsilon_1 = 2 \), dielectric strength \( E_{d1} = 20 \) kV/cm.
- **Layer 2:** Thickness \( a_2 = 2 \) cm, dielectric constant \( \varepsilon_2 = 1 \), dielectric strength \( E_{d2} = 5 \) kV/cm.
- **Total applied voltage \( U = 50 \) kV.**
We are to check if this structure can safely operate under this voltage or if breakdown will occur.
---
### **Step 2: Electric Field Distribution**
For **series capacitors** (or dielectric layers in series), the electric displacement \( D \) is the same in both layers:
\[
D = \varepsilon_0 \varepsilon_1 E_1 = \varepsilon_0 \varepsilon_2 E_2
\]
\[
\Rightarrow \varepsilon_1 E_1 = \varepsilon_2 E_2
\]
\[
\Rightarrow E_1 = \frac{\varepsilon_2}{\varepsilon_1} E_2
\]
\[
\Rightarrow E_1 = \frac{1}{2} E_2
\]
---
### **Step 3: Voltage Across Each Layer**
The total voltage is the sum of voltages across each layer:
\[
U = U_1 + U_2 = E_1 a_1 + E_2 a_2
\]
But since \( E_1 = \frac{1}{2}E_2 \):
\[
U = \left(\frac{1}{2}E_2\right)a_1 + E_2 a_2
\]
\[
U = \frac{a_1}{2}E_2 + a_2 E_2
\]
\[
U = E_2 \left( \frac{a_1}{2} + a_2 \right)
\]
Substitute values:
- \( a_1 = 1 \) cm
- \( a_2 = 2 \) cm
- \( U = 50 \) kV
\[
50 = E_2 \left( \frac{1}{2} + 2 \right) = E_2 \times 2.5
\]
\[
E_2 = \frac{50}{2.5} = 20 \text{ kV/cm}
\]
Now, \( E_1 = \frac{1}{2}E_2 = \frac{1}{2} \times 20 = 10 \text{ kV/cm} \)
---
### **Step 4: Compare with Breakdown Strength**
- **Layer 1:** \( E_1 = 10 \) kV/cm < \( E_{d1} = 20 \) kV/cm (Safe)
- **Layer 2:** \( E_2 = 20 \) kV/cm > \( E_{d2} = 5 \) kV/cm (NOT SAFE)
---
### **Step 5: Conclusion**
- **Layer 2** will **break down** because the electric field exceeds its dielectric strength.
- **The material cannot safely operate at 50 kV.**
---
## **Final Answer**
**This material cannot safely operate at 50 kV. Layer 2 will break down because the electric field (20 kV/cm) exceeds its dielectric strength (5 kV/cm).**
---
**Summary Table:**
| Layer | Max Field (kV/cm) | Actual Field (kV/cm) | Safe? |
|---------|-------------------|----------------------|-------|
| Layer 1 | 20 | 10 | Yes |
| Layer 2 | 5 | 20 | No |
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