Give step-by-step solution with explanation and final answer:JOEL 2 fH E TE 4 = = = i % 3 iy E E HA E c i k H
Question:
Give step-by-step solution with explanation and final answer:
JOEL
2 fH
E TE
4 = = = i %
3 iy E E
HA
E c i
k H
This is AI generated Response.
Asked by: hhhh
Created at: 2025-05-27 18:04:59
Asked by: hhhh
Created at: 2025-05-27 18:04:59
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Let's solve the differential equation step-by-step:
### **Given:**
\[
\frac{dy}{dx} = 2e^{3x}
\]
with the initial condition:
\[
y(1.03) = 11.88
\]
We need to find \( y(0.88) \) and \( y(1.50) \).
---
## **Step 1: Integrate the Differential Equation**
\[
\frac{dy}{dx} = 2e^{3x}
\]
Integrate both sides with respect to \( x \):
\[
\int dy = \int 2e^{3x} dx
\]
The right side:
\[
\int 2e^{3x} dx = 2 \int e^{3x} dx = 2 \cdot \frac{1}{3}e^{3x} = \frac{2}{3}e^{3x}
\]
So,
\[
y = \frac{2}{3}e^{3x} + C
\]
---
## **Step 2: Apply Initial Condition**
Given \( y(1.03) = 11.88 \):
\[
11.88 = \frac{2}{3}e^{3 \times 1.03} + C
\]
Calculate \( e^{3 \times 1.03} \):
\[
3 \times 1.03 = 3.09
\]
\[
e^{3.09} \approx 21.976
\]
\[
\frac{2}{3} \times 21.976 \approx 14.65
\]
So,
\[
11.88 = 14.65 + C
\]
\[
C = 11.88 - 14.65 = -2.77
\]
---
## **Step 3: Final Solution**
\[
\boxed{y(x) = \frac{2}{3}e^{3x} - 2.77}
\]
---
## **Step 4: Evaluate at Given Points**
### (a) \( x = 0.88 \):
\[
y(0.88) = \frac{2}{3}e^{3 \times 0.88} - 2.77
\]
Calculate:
\[
3 \times 0.88 = 2.64
\]
\[
e^{2.64} \approx 14.03
\]
\[
\frac{2}{3} \times 14.03 \approx 9.35
\]
\[
y(0.88) = 9.35 - 2.77 = \boxed{6.58}
\]
---
### (b) \( x = 1.50 \):
\[
y(1.50) = \frac{2}{3}e^{3 \times 1.50} - 2.77
\]
Calculate:
\[
3 \times 1.5 = 4.5
\]
\[
e^{4.5} \approx 90.02
\]
\[
\frac{2}{3} \times 90.02 \approx 60.01
\]
\[
y(1.50) = 60.01 - 2.77 = \boxed{57.24}
\]
---
## **Final Answers:**
\[
\boxed{y(0.88) = 6.58}
\]
\[
\boxed{y(1.50) = 57.24}
\]
---
**Summary Table:**
| x-coordinate | Solution Value |
|--------------|---------------|
| 0.88 | 6.58 |
| 1.50 | 57.24 |
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