Give step-by-step solution with explanation and final answer:(a) Find the cos series for f(z) with period 2L. (b) Sketch the graph of the function to which the series converges over 3 periods.
Question:
Give step-by-step solution with explanation and final answer:
(a) Find the cos series for f(z) with period 2L.
(b) Sketch the graph of the function to which the series converges over
3 periods.
This is AI generated Response.
Asked by: Test User 100253
Created at: 2025-05-22 18:22:39
Asked by: Test User 100253
Created at: 2025-05-22 18:22:39
Final Answer:
Rendered
Raw Text
Did you like this answer?
Let's break down the problem step by step.
---
## (a) **Find the cos series for \( f(x) \) with period \( 2L \):**
This is asking for the **Fourier cosine series** for a function \( f(x) \) that is defined on \( [0, L] \) and extended as an even function to \( [-L, L] \), with periodicity \( 2L \).
### **Step 1: General Form of the Cosine Series**
The Fourier cosine series for a function \( f(x) \) defined on \( [0, L] \) is:
\[
f(x) \sim \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos\left(\frac{n\pi x}{L}\right)
\]
where the coefficients are:
\[
a_0 = \frac{2}{L} \int_0^L f(x)\,dx
\]
\[
a_n = \frac{2}{L} \int_0^L f(x) \cos\left(\frac{n\pi x}{L}\right) dx, \quad n \geq 1
\]
This series represents the **even extension** of \( f(x) \) on \( [-L, L] \), and then it is repeated every \( 2L \) (thus, period \( 2L \)).
---
### **Step 2: Write the Final Answer (General Cos Series)**
**The cosine series for \( f(x) \) with period \( 2L \) is:**
\[
\boxed{
f(x) \sim \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos\left(\frac{n\pi x}{L}\right)
}
\]
where
\[
a_0 = \frac{2}{L} \int_0^L f(x)\,dx, \qquad
a_n = \frac{2}{L} \int_0^L f(x) \cos\left(\frac{n\pi x}{L}\right) dx
\]
---
## (b) **Sketch the graph of the function to which the series converges over 3 periods**
### **Step 1: Description of the Extended Function**
- The cosine series converges to the even periodic extension of \( f(x) \) with period \( 2L \).
- Over one period \( [0, 2L] \), \( f(x) \) is defined as:
- On \( [0, L] \): \( f(x) \) (the original function)
- On \( [L, 2L] \): \( f(2L - x) \) (mirror image)
- Extend this pattern to the left and right for additional periods.
### **Step 2: Sketch (Describe since text-only)**
- On \( [0, L] \): Draw the original \( f(x) \).
- On \( [-L, 0] \): Draw the mirror image of \( f(x) \) (since it's even).
- Repeat this \( 2L \)-long shape to the left and right for a total of 3 periods (\( -2L \) to \( 4L \)).
**(You can sketch this as a "wavy" shape that repeats every \( 2L \), symmetric about \( x = 0, 2L, 4L, \ldots \))**
---
## **Summary**
### **(a) Cosine Series:**
\[
f(x) \sim \frac{a_0}{2} + \sum_{n=1}^{\infty} a_n \cos\left(\frac{n\pi x}{L}\right)
\]
with
\[
a_0 = \frac{2}{L} \int_0^L f(x)\,dx, \qquad
a_n = \frac{2}{L} \int_0^L f(x) \cos\left(\frac{n\pi x}{L}\right) dx
\]
### **(b) Sketch:**
The function is the **even periodic extension** of \( f(x) \) with period \( 2L \), repeated over three periods.
---
**If you provide a specific \( f(x) \), I can calculate the coefficients and show a specific plot!**
Question:
please draw the graph
This is AI generated Response.
Asked by: Test User 100253
Created at: 2025-05-22 18:28:58
Asked by: Test User 100253
Created at: 2025-05-22 18:28:58
Final Answer:
Rendered
Raw Text
Did you like this answer?
Certainly! Since I can't physically draw here, I'll guide you through how to sketch the graph of the function to which the Fourier cosine series converges, based on the typical form of such problems.
---
### Step-by-step guide to sketch the graph of the periodic extension:
#### 1. **Identify the original function \( f(x) \) on \( [0, L] \):**
- For example, if \( f(x) \) is given in the problem (e.g., a specific function like a constant, linear, or piecewise function), note its shape on \( [0, L] \).
*Note:* Without the explicit \( f(x) \) from the image, let's assume a generic case for illustration, say \( f(x) = x \) on \( [0, L] \).
#### 2. **Construct the even extension on \( [-L, L] \):**
- Extend \( f(x) \) to \( [-L, 0] \) as an even function:
\[
f(-x) = f(x)
\]
For \( f(x) = x \), the reflection is \( f(-x) = -x \), but since the Fourier cosine series corresponds to an **even extension**, the function should be made even, i.e., \( f_{even}(x) = |x| \) for the example.
- For general \( f(x) \), mirror the graph across the y-axis.
#### 3. **Repeat periodically with period \( 2L \):**
- After constructing the \( 2L \)-periodic even extension, replicate this pattern to the left and right for multiple periods.
- For **three periods**, sketch the pattern over \( x \in [-L, 3L] \):
- **Period 1:** \( [0, L] \)
- **Period 2:** \( [L, 2L] \)
- **Period 3:** \( [2L, 3L] \)
- The pattern repeats every \( 2L \), so the graph looks like a wave that repeats, with symmetry about the y-axis (even extension).
#### 4. **Sketch the combined shape:**
- For each period:
- On \( [0, L] \), plot the original \( f(x) \).
- On \( [L, 2L] \), plot the mirror image of \( f(x) \) about \( x = L \).
- Connect the points smoothly to visualize the convergence of the Fourier series.
---
### **Summary of the sketch:**
- A "wave-like" pattern repeating every \( 2L \).
- Symmetric about the y-axis within each period.
- The function's shape within one period is the even extension of the original \( f(x) \).
---
### **Example (if \( f(x) = x \) on \( [0, L] \)):**
- On \( [0, L] \): linearly increasing from 0 to \( L \).
- On \( [-L, 0] \): mirror image, decreasing from 0 to \(-L\), making the extension even.
- Repeat this pattern over three periods.
---
**If you'd like, I can help generate a specific sketch if you tell me the form of \( f(x) \).**
Question:
yes please
This is AI generated Response.
Asked by: Test User 100253
Created at: 2025-05-22 18:29:21
Asked by: Test User 100253
Created at: 2025-05-22 18:29:21
Final Answer:
Rendered
Raw Text
Did you like this answer?
Certainly! To provide a clear sketch, I will assume a specific example function \(f(x)\) on \([0, L]\). Let's choose:
\[
f(x) = x, \quad \text{for } 0 \leq x \leq L
\]
This is a common example and will illustrate the process well.
---
## Step-by-step sketch guide for \(f(x) = x\):
### 1. **Original function on \([0, L]\):**
- A straight line starting from \(0\) at \(x=0\) to \(L\) at \(x=L\).
### 2. **Construct the even extension:**
- Since the Fourier cosine series corresponds to the **even extension** of \(f(x)\), define:
\[
f_{even}(x) =
\begin{cases}
x, & x \in [0, L] \\
-x, & x \in [-L, 0]
\end{cases}
\]
- For \(x \in [-L, 0]\), the graph is a straight line decreasing from \(0\) at \(x=0\) to \(-L\) at \(x=-L\).
- The overall extended function over \([-L, L]\) is symmetric about the y-axis, forming a "V" shape with vertex at the origin.
### 3. **Periodicity:**
- The function repeats every \(2L\), so:
\[
f_{periodic}(x) = f_{even}(x \bmod 2L)
\]
- Over the interval \([-L, L]\), it looks like a symmetric "V".
- Over three periods, the graph will extend from \(-L\) to \(3L\):
- \(\boxed{-L \text{ to } L}\): first period
- \(\boxed{L \text{ to } 3L}\): second period, repeating the pattern
### 4. **Sketch the graph:**
- **Center at \(x=0\):** \(f(0) = 0\).
- **On \([0, L]\):** linearly increasing from 0 to \(L\).
- **On \([-L, 0]\):** decreasing linearly from 0 at \(x=0\) to \(-L\) at \(x=-L\).
- **Repeat for subsequent periods:**
- From \([L, 3L]\), the pattern repeats:
- On \([L, 2L]\): \(f(x) = x - 2L\), decreasing from \(f(L)=L\) at \(x=L\) to \(f(2L)=0\) at \(x=2L\).
- On \([2L, 3L]\): \(f(x) = x - 2L\), increasing from \(f(2L)=0\) to \(f(3L)=L\).
- The overall graph looks like a repeated wave of straight lines forming "V" shapes, symmetric about the y-axis, with each "V" spanning length \(2L\).
---
## **Summary of the sketch:**
- **Shape:** Repeating "V" shapes with the vertex at each multiple of \(L\).
- **Symmetry:** About the y-axis.
- **Period:** \(2L\).
---
## **Final note:**
If you wish, I can help generate a simple ASCII art sketch or guide you through plotting this with graphing software. Let me know!
📢 Instructions:
- Ask anything relatd to above question only.
- For new Question goto :
VIPSolutions