Give step-by-step solution with explanation and final answer:15. A man pries up one end of a 480-Ib crate with a steel pipe 6 ft long. If he exerts a force of 80 Ib, the distance of the fulcrum from the crate is a. 6in. b. 9 in. c. 18in. d. 24 in.
Question:
Give step-by-step solution with explanation and final answer:
15. A man pries up one end of a 480-Ib crate with a
steel pipe 6 ft long. If he exerts a force of 80 Ib,
the distance of the fulcrum from the crate is
a. 6in. b. 9 in.
c. 18in. d. 24 in.
This is AI generated Response.
Asked by: Test User 100252
Created at: 2025-05-21 18:48:28
Asked by: Test User 100252
Created at: 2025-05-21 18:48:28
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Given:
- Weight of crate (load, \( F_L \)) = **480 lb**
- Length of steel pipe = **6 ft = 72 in** (since \(1 \text{ ft} = 12 \text{ in}\))
- Effort applied (\( F_E \)) = **80 lb**
- Distance from fulcrum to crate = \( x \) (what we need to find)
- Distance from fulcrum to where effort is applied = \( 72 - x \) (since total length is 72 in)
We use the **principle of levers** (Law of the Lever):
\[
\text{Effort} \times \text{Effort Arm} = \text{Load} \times \text{Load Arm}
\]
\[
80 \times (72 - x) = 480 \times x
\]
Let's solve for \( x \):
1. **Expand the equation:**
\[
80 \times 72 - 80x = 480x
\]
\[
5760 - 80x = 480x
\]
2. **Combine like terms:**
\[
5760 = 480x + 80x
\]
\[
5760 = 560x
\]
3. **Solve for \( x \):**
\[
x = \frac{5760}{560}
\]
\[
x = 10.2857 \text{ in}
\]
None of the choices exactly match, but let's check which is **closest**:
Choices:
- a. 6 in
- b. 9 in
- c. 18 in
- d. 24 in
**9 in** is the closest answer to 10.3 in.
---
### **Final Answer**
**b. 9 in**
---
#### **Explanation:**
We balanced the moments (force × distance) around the fulcrum, solved for the unknown distance from the fulcrum to the crate, and matched it to the closest given answer.
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